Anybody have an idea why I would get a non-integer value for the
number of days here?
> difftime('2004-08-05','2001-01-03',units='days')
Time difference of 1309.958 days
Would you just round off?
Best,
Jon
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https:/
This is probably not the best way, but (assuming you had vectors and
not lists, since I'm not sure what your list looks like):
C <- B[which(B %in% A ==FALSE)]
Regards,
Jonathan
On Fri, Feb 12, 2010 at 5:06 PM, Zoppoli, Gabriele (NIH/NCI) [G]
wrote:
> Sorry, maybe it's easy but
ctor of size 732.4 Mb
Since it seems these matrices are too large, I'm wondering whether
there's a better way to call a hist command without actually building
the said matrix..
I'd greatly appreciate any ideas!
Best,
Jonathan
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gt; expandedCondition2 <- matrix(rep(Condition2[[1]], nrow(Condition1)),
> byrow=FALSE, nrow=nrow(Condition2))
Error: cannot allocate vector of size 732.4 Mb
Since it seems these matrices are too large, I'm wondering whether
there's a better way to call a hist command without actua
whether this a reasonable experience (and if
so, is there a way to get the desired effect, or am I SOL)? I can't
find anything in the help archives.
OS: Windows 7 64-bit; R version 2.10.1; RAM: 4 gb
Thanks,
Jonathan
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ks.test(rep(1:940,10),rep(1:940,800))
Error: cannot allocate vector of size 358.6 Mb
Any ideas?
OS: Windows 7 64-bit, R ver. 2.10.1, Memory: 4 gb
Best,
Jonathan
Best,
Jonathan
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t find some cluster
with a lot of memory to run this code on (presumably I'd be able to
allocate those vectors then)?
Jonathan
On Tue, Mar 9, 2010 at 4:11 PM, Jonathan wrote:
> Hi R-help,
> I am interested in comparing two vectors of data
> observations to see if they come from t
pts of my own, but I figured I'd
ask if one of you R-ninjas might know of an existing function (or
algorithm I could look up and then code) that can do this somewhat
efficiently (or even just correctly!).
Best,
Jonathan
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ood pseudocode:
http://www.public.iastate.edu/~ddoty/HungarianAlgorithm.html
Actually, it appears the "seriation" package in R could come in handy here..
I'll write back if I find more.
Jonathan
On Fri, Apr 23, 2010 at 4:20 PM, David Winsemius wrote:
> Can you specify how you
er the same. For
example, row 1 of the original matrix was 13 9 2, and in the second
matrix, it is 13 1 2.
I'm looking to conserve the rows, but only reorder them vertically.
Thanks,
Jonathan
On Fri, Apr 23, 2010 at 4:32 PM, Dimitris Rizopoulos
wrote:
> one way is:
>
> M <- ma
11
> a[order(rowSums(a)),]
[,1] [,2] [,3]
[1,]11 20
[2,] 3011
[3,]1 501
In this case, I would like to rearrange the original matrix into:
[,1] [,2] [,3]
[1,] 3011
[2,]1 501
[3,] 11 20
Best,
Jonathan
On Sat, Apr 24, 2
Hi,
A noobie question: I'm simply trying to run a conditional statement that
evaluates if a substring is found within a larger string. I find that if it
IS found, my function returns TRUE (great!), but if not, the condition does
not evaluate to FALSE.
ex):
if( grep("hi", "hop", fixed = TRUE)
our substring is not in your string')
> [1] "no, your substring is not in your string"
> >
>
>
> On Sat, Dec 19, 2009 at 3:47 PM, Jonathan wrote:
>
>> Hi,
>> A noobie question: I'm simply trying to run a conditional statement
>> that
&g
troubleshooting.
I generated it with some grep, gawk commands using Cygwin in a Windows
environment (though subsequently converted it to Windows format - R loads it
exactly the same way, regardless of whether it's in linux or windows format)
Regards,
Tried deleting several line above and below line 362; did that and changed
the extension. Still finds the same number of rows (362).
Strange!
Jonathan
On Sun, Dec 20, 2009 at 12:19 AM, David Winsemius wrote:
>
> On Dec 20, 2009, at 12:07 AM, David Winsemius wrote:
>
>
>> O
#x27;aa','aaa')[[1]])
[1] 1
returns 1.
**What I want to do:**
I'm looking for a way to count all occurrences of the substring, including
overlapping sets (so 'aa' would be found in 'aaa' two times, because the
middle 'a' gets counted twice).
Thanks everyone! The problem was definitely with the apostrophe being
interpreted as a single quote.
Jonathan
On Sun, Dec 20, 2009 at 7:49 AM, jim holtman wrote:
> Most likely an unbalanced quote. put the following option in the
> read.table:
>
> quote='', comment.char
Is it just me, or is the bio3d package no longer available?
Is there another way to do a reasonable nucleic acid sequence alignment in
R?
Thanks,
Jonathan
[[alternative HTML version deleted]]
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Hi All,
My R installation is acting strangely and I'm hoping somebody might have
an idea what's going on:
I can't seem to load the "RMySQL" function. It seems to have installed
without a problem, but when I enter:
library(RMySQL)
R tells me:
Error in utils::readRegistry("SOFTWARE\\MySQL AB"
ed a fresh copy today before
emailing the list).
I installed MySQL, but I get the same error.
My operating system is Windows 7 64-bit.
Any ideas?
Best,
Jonathan
On Tue, Jan 26, 2010 at 5:05 PM, Duncan Murdoch wrote:
> On 26/01/2010 4:54 PM, Jonathan wrote:
>
>> Hi All,
>>My R i
ng than I did with the version I
installed from the server via install.packages("RMySQL"), so perhaps I'll be
alright with the older version.
Best,
Jonathan
-- Forwarded message --
From: Phil Spector
Date: Tue, Jan 26, 2010 at 5:07 PM
Subject: Re: [R] unidentif
) :
access to 'http://www.r-project.org
<http://www.r-project.org/>'<http://www.r-project.org/%3E'>denied
Any other ideas?
Jon
On Tue, Jan 26, 2010 at 5:39 PM, Duncan Murdoch wrote:
> On 26/01/2010 5:32 PM, Jonathan wrote:
>
>> Hi Duncan,
>> I tried:
&g
in shell.exec(url) : access to 'http://www.r-project.org' denied
Any thoughts? Thanks!
Regards,
Jonathan
[[alternative HTML version deleted]]
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PLEASE do r
):
> setInternet2()
[1] FALSE
Warning message:
In setInternet2() : internet routines were already initialized
--
I'm open to further suggestions!
Thanks again,
Jonathan
On Wed, Feb 3, 2010 at 4:34 PM, RICHARD M. HEIBERGER wrote:
> In addition to Marc's comments, you might want to use
> setI
and paste the URL into a browser every time I want to read the entry
for a particular function..
Happy to hear any other ideas!
Best,
Jonathan
On Wed, Feb 3, 2010 at 5:00 PM, RICHARD M. HEIBERGER wrote:
> If you paste
>
>
> http://127.0.0.1:12300/library/base/html/sum.html
>
>
&
files.
Then I rebooted my machine. I'm still getting the same error.
Any other ideas?
Thanks,
Jon
On Wed, Feb 3, 2010 at 5:57 PM, Duncan Murdoch wrote:
> On 03/02/2010 5:14 PM, Jonathan wrote:
>
>> Rich:
>>Both IE and Firefox are unable to find the link you supplied.
is
pretty good.
Thanks so much,
Jonathan
On Thu, Feb 4, 2010 at 6:29 AM, S Ellison wrote:
> Might this be a firewall-like issue and nothing to do with html or R?
>
> If I understand the 2.10 help system, it operates by starting R as an
> http server - effectively a web server,
V1 V2
1 a2
2 b9
3 c4
If somebody could (relatively easily) figure out how to get closer to
a solution, I'd appreciate hearing how. Also, I'd be interested to
hear how you came upon the answer (so I can get bet
1x
1 1 7008
2 2 6593
3 3 9996
What I'm looking for, of course, is:
> aggregate(as.Date(df$V2),df['V1'],min)
V1V2
1 1 1996-11-18
2 2 1988-01-20
3 3 1997-05-15
Any idea how to produce the desired output?
Thanks,
Jonathan
On Mon, Feb 8, 2010 at 12:11 PM, Gabor
t;
>> Actual:
>>> sample(10,1)
>> [1] 2
>>> sample(10,1)
>> [1] 9
>>> sample(10,1)
>> [1] 4
>>
>>
>> Desired:
>>> sample(10,1)
>> [1] 10
>>> sample(10,1)
>> [1] 10
>>> sample(10,1)
>>
then do a
filled.contour plot on the data.
I think this is the same as what Jessica is asking...
Regards and many thanks,
Jonathan
UCL Computer Science
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ns, e.g. standard
plot() seem to work fine and display in a Quartz window, but when I run this
I'm not getting anything =/
Any tips?
Jonathan
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nder other operating systems but
that's the basic idea.
Jonathan
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there... and I should be good to go!
Hope that you got your stuff to work Jessica, and thanks to everyone for
your help :-) I'm sure I will be posting here again very soon!
Jonathan
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Sen
he question is: how do I do this?
Any help much appreciated!
Thanks,
Jonathan
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Sorry to bump this up again, but I've been continuing to look for a solution
to this including a look into stats.bin but I still can't find any solution
to do this within R.
Any help would be much appreciated!
Thanks,
Jonathan
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might be able to explain how to go about rounding the
values?
Thanks,
Jonathan
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R-h
iagram), there are
bigger points, so say 0<=x<10, 0<=y<10 is one point in the lower left,
rather than having 100 points for each x,y value.
The same strategy should then be applied to the whole graph.
Any ideas how to achieve this? I'm sure this is quite a common thing to do
tions to solve my problem.
Thanks,
Jonathan
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Hi All,
Anyone know how to quickly query some summary information on the
components of a list?
For example, I have a list that contains dataframes (originally
generated by using split() on one large data frame).
I simply want to know the number of rows in the longest dataframe from the list.
have to use the dyadic(?).
But I have a rather complicated conditional, so if my dataframes were huge
or I had to do this many, many times, I would think about how to vectorize
this, but in my case, just running through in a loop suits my needs.
Thanks!
Jonathan
On Thu, May 5, 2011 at 6:
erations for previous values of i, increment i to the next value,
and repeat.
Ideally, I could accomplish this in some sort of vectorized manner,
although the Force is not yet strong with me. Any ideas would be
appreciated!
Regards,
Jonathan
[[alternative HTML version deleted]]
lying the
function (in my case, 'outer') to category 3 vs 4 (and 4 vs 5, etc.),
instead of skipping category 3 altogether and moving to 4 vs 4. There's
probably a way to mitigate that, but I suppose at this point, I can
implement the method using merge().
Regards,
Jonathan
x27;type' (list) of argument
> max(husk[[]])
Error in husk[[]] : invalid subscript type 'symbol'
> max(husk[[1:length(husk)]])
Error in husk[[1:length(husk)]] : recursive indexing failed at level 2
> max(husk[1:length(husk)])
Error in max(husk[1:length(husk)]) : inva
or am I going to need to
program something from scratch (something like ordering the vectors and then
looping through them)?
ex:
> a <- c(2,4,2,3)
> b<-c(6,6,5,2,2,8,4)
> intersect(a,b)
[1] 2 4
I'd hope the answer to be 2 2 4.
Regards,
Jonathan
[[alterna
ill show only one 2.
Consider:
> a <- c(2,4,3)
> b<-c(6,6,5,2,2,8,4)
> b[b %in% a]
[1] 2 2 4
> a[a%in%b]
[1] 2 4
The second answer is correct, but I can't predict which variable to put in
which position in the statement, so I'd need them both to be correct.
Best,
Thank you, David and Gabor, for the creative solutions, and for introducing
me to pmin()
Jonathan
On Thu, May 20, 2010 at 9:55 PM, Gabor Grothendieck wrote:
> Try this one liner. The first argument of rep is the sorted
> intersection and the second argument is the calculated fr
"ThisI" "lo"
Then I'd like to concatenate them (there will be many of them)
> result <- paste(longerString,collapse='')
> result
[1] "ellThisIlo"
(perhaps the paste command as I've done it is the best way, but depending on
ho
e, and the large
number of substrings to fetch), ie is it much slower than C++, or in the
same ballpark?
Thanks!
Jonathan
On Mon, Apr 11, 2011 at 4:14 PM, Duncan Murdoch wrote:
> On 11/04/2011 3:48 PM, Jonathan wrote:
>
>> Hi All,
>> I'm looking for a way to get man
Hi all,
I'm trying to generate a grid of four plots. The first 2 appear
just fine, but the final 2 will not appear in the grid, instead
overwriting the first two.Any ideas on how to get them all in the
same window would be greatly appreciated.
Cheers,
Jonathan
library(fields)
par(
Hi, I am wondering whether we can apply 'cbind/rbind' on many **equivalent**
list objects. For example please consider following:
> list1 <- list2 <- vector("list", length=2); names(list1) <- names(list2)
<- c("a", "b")
> list1[[1]] <- matrix(1:25, 5)
> list1[[2]] <- matrix(2:26, 5)
> list2[[1]] <
Hi there, I have following equations to be solved for a and b:
a/(a+b) = x1
ab/((a+b)^2 (a+b+1)) = x2
Is there any direct function available to solve them without
disentangling them manually? Thanks for your help.
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h
Dear all, my question is not directly related to R, however I believe that
experts here would not mind anything to have a look on my problem.
Please consider a symmetric matrix and it's eigen values:
> set.seed(1)
> mat <- matrix(rnorm(36), 6)
> mat <- mat %*% t(mat) # symmetric matrix
> mat
It is not any homework problem. I just need some pointer. Given that I think
I would be able to carry forward.
Thanks,
On Thu, Jul 21, 2011 at 4:52 AM, Bert Gunter wrote:
> A homework problem?
> -- Bert
>
> On Wed, Jul 20, 2011 at 10:06 AM, B. Jonathan B. Jonathan
> wrote:
&
formation").
I want to have a control on: How far min eigen value I want from zero.
Please let me should I need to give more information.
Thanks,
On Thu, Jul 21, 2011 at 9:27 AM, David Winsemius wrote:
>
> On Jul 20, 2011, at 11:17 PM, B. Jonathan B. Jonathan wrote:
>
> It is
27;m having a
hard time figuring out how to do this test.
--j
--
--
Jonathan A. Greenberg, PhD
Randall Endowed Professor and Associate Professor of Remote Sensing
Global Environmental Analysis and Remote Sensing (GEARS) Laboratory
Natural Resources & Environmental Science
University of Nevada, R
t <- gini(prop.table(table(y)))
impurity_L <- gini(prop.table(table(obs_L)))
impurity_R <- gini(prop.table(table(obs_R)))
impurity <- impurity_root * n - (n_L*impurity_L + n_R*impurity_R) # 2.880952
Thus, an improvement of 2.88 should result in a split. It does not.
Why?
Jonathan
__
replicate(1000, test_split(0.5))) # 2-12, i.e. splits only sometimes...
Adding a constant to y and getting different trees is a bit strange,
particularly stochastically.
Will see if I can track down a copy of the CART book.
Jonathan
From: Therneau, Terry
rg/web/packages/rDotNet/index.html
<https://cran.r-project.org/web/packages/rDotNet/index.html>
The package is stable, as has been in use for some years, but only now packaged
up for public use on CRAN. Feel free to contact with questions or suggestions
on GitHub or by email.
Regards
--
Jo
me any feedback or suggestions you may have.
Kind regards,
- Jonathan Carroll.
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Folks:
Is there an easy function to open a finder window (on mac) or windows
explorer window (on windows) given an input folder? A lot of times I want
to be able to see via a file browser my working directory. Is there a good
R hack to do this?
--j
[[alternative HTML version deleted]]
I recently compared two different approaches to calculating the correlation of
two variables, and I cannot explain the different results:
data(cars)
model <- lm(dist~speed,data=cars)
coef(model)
fitted.right <- model$fitted
fitted.wrong <- -17+5*cars$speed
When using the OLS fitted values, the
a linear function of speed! Hence
> cor(cars$dist,fitted.right)^2 and cor(x=cars$dist,y=fitted.wrong)^2 must be
> the same.
>
> HTH
> d
>
> Feladó: R-help [r-help-boun...@r-project.org] ; meghatalmazó: Jonathan
> Thayn [jth...@il
to have created the clean pattern I want, but I would like to
project the first component back into the original axes? Is there a simple way
to do that?
Jonathan B. Thayn
[[alternative HTML version deleted]]
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p. It's been a long time since I've played with PCA.
Jonathan Thayn
On Oct 2, 2014, at 4:59 PM, David L Carlson wrote:
> I think you want to convert your principal component to the same scale as d1,
> d2, d3, and d4. But the "original space" is a 4-dimensional space
This is exactly what I was looking for. Thank you.
Jonathan Thayn
On Oct 3, 2014, at 10:32 AM, David L Carlson wrote:
> You can reconstruct the data from the first component. Here's an example
> using singular value decomposition on the original data matrix:
>
>> d <
2 3 5 6 7
1 70 0 0 0 0 0
2 0 76 0 0 0 0
3 0 0 17 0 0 0
5 0 0 0 13 0 0
6 0 0 0 0 9 0
7 0 0 0 0 0 29
Can anyone clarify what fitted.values and predict actually do? I would have
expected they would give the same output.
Thanks... Jonathan
--
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oses kknn$best.parameters,
but want to verify this.
Hopefully that clarifies the issue. I post here in case future users have a
similar question.
Thanks to any who took the time to think about this!
Jonathan
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eplace any mean row NaN's with the offset value
from that very same row?
I don't want to use any pasting etc as this needs to be used as part of a
function working over a large dataset than the one shown here.
Cheers
Jonathan
Hi everyone,
Ignore my previous post, i realised that the rows and columns i typed into the
email were unreadable, sincere apologies for this.
A simple question, but i cannot figure this out.
I have a data-frame with 4 columns (onset, offset, outcome, mean):
df<-data.frame(onset=c(72071,142598,293
-
> Sent from my phone. Please excuse my brevity.
>
> On October 18, 2015 12:24:42 PM PDT, Jonathan Reardon
> wrote:
> >Hi, Sorry to be a pain. Would you be kind enough to briefly explain
> >what the lines
I could not find an answer elsewhere.
Thank you,
Jonathan
__
Jonathan Gellar
Statistician
Mathematica Policy Research
1100 First Street NE, 12th Floor
Washington, DC 20002
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Hello,
I ran a 2x2x2 repeated measures ANOVA which turned out fine:
DfSum Sq Mean Sq F
value Pr(>F) Attend1 0.5540
0.55402 7.03740.01079 *PercGrp 1
27;s
extremely clever algorithm.
> That said, does anyone have any techniques for Googling for info on some
> particular R functionality? I've had some luck with the term "R-help"
> or "R-sig" but that leaves out an awful lot of websites.
RSiteSearch()
is one. T
exp(x)/(1+exp(x))}
astart <- c(.5,.8,.8,.8,.65,.8,.8,.5,.5,.5,.5,
NA,NA,.5,.5,.5,.5,.5,.5,.5,.5,.5,
.5,.5,.5,.5,.5,.5,.5,.5,.5,.5,.5)
icc <- matrix(NA,nitems,4) # A,B,C,D coefficients
# the loop is over the items
for (i in 1:ns) {
icc.tmp<-nls(score[,
many other options.
The model I fit made exactly the same assumption you describe, namely,
that the upper asymptote was less than 1, because (for example) some
of the best students understand the question differently from what the
test makers intended. And the lower asymptote depends on what th
Another way to do it (based on summary data):
http://finzi.psych.upenn.edu/R/Rhelp02a/archive/131342.html
--
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Home page: http://www.sas.upenn.edu/~baron
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###
I am not clear what is missing -
the installation did not indicate any problem, or any missing
libraries.
Thanks for any help on this.
--
==
Prof. Jonathan M. Lees
Department of Geological Sciences
104 South Road, CB #3315, Mitchell Hall
University o
subject effect for the INTERACTION of IV1 and IV2?
lmer(DV ~ IV1 + IV2 + (1 + IV1 * IV2 | Subject))
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Home page: http://www.sas.upenn.edu/~baron
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http
Quick informal poll: what is everyone's favorite text editor for working
with R? I'd like to hear from people who are using editors that have
some level of direct R interface (e.g. Tinn-R, Komodo+SciViews). Thanks!
--j
--
Jonathan A. Greenberg, PhD
Postdoctoral Scholar
Center f
around these mean
values? Since pXY are stochastic probabilities, it seems that the
distribution and variance should be calculable.
Thanks!
--j
--
Jonathan A. Greenberg, PhD
Postdoctoral Scholar
Center for Spatial Technologies and Remote Sensing (CSTARS)
University of California, Davis
One
and tell you whether they are embedded.
Jon
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PLEASE
he matrix on the
> left hand side.
>
> __
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-
y again. That's the logically best way, but I don't know how
to do it so that it works.
Jon
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Home page: http://www.sas.upenn.edu/~baron
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ht
Example:
> df <- data.frame('id'=c('a','b','a','c','b','a'),'value'=c(6,4,2,9,1,7))
> df
id value
1 a 6
2 b 4
3 a 6
4 c 9
5 b 1
6 a 7
I'd like some kind
de4 is not a "standard" r
package.
That said, the made4 documentation says that do3d uses scatterplot3d. The
scatterplot3d package documentation says that "setting enlarged limits may
not work as exactly as expected (a known but unfixed bug)." So that may be
your problem.
Best o
4-05" "1927-04-05" "1927-04-05" "1927-04-05"
"1939-04-08" "1939-04-08" "1939-04-08" "1939-04-08" "1938-10-24"
"1938-10-24" "1938-10-24"
[35] "1938-10-24
Thanks Don MacQueen for this reply to my initial query - please SEE MY REPLIES
TO THESE IDEAS AND FURTHER INFORMATION BELOW
>From: Don MacQueen [m...@llnl.gov]
>Sent: 23 February 2010 21:25
>To: Jonathan Williams; r-help@r-project.org
>
>Subject: Re: [R] Problem with strptime gen
I'm having a mixed experience with using R and UNIX's screen function
-- sometimes when I close a connection that used screen, the R process
is killed (which, in theory, it shouldn't be -- it should be running
in the background). Does anyone have any ideas on how well (or not) R
behaves with scree
nt to take into account the fact that it's actually a time series,
R has plenty of tools for that too.
Jonathan
>
> Thanks in advance
> chinna.
> --
> View this message in context:
> http://n4.nabble.com/see-the-example-and-help-me-tp1587
<- a[(a$stain=="none"), "Count"]
a$calib <- a$Count - b[a$rep]
Note that it only works if the values of rep are integers starting with 1
and increasing sequentially (1, 2, 3, ...)
Jonathan
>
> Thanks in advance.
>
> Sam
>
> Note: I've already calculat
.
I use Fedora on both 64 and 32 bit systems.
Jon
--
Jonathan Baron, Professor of Psychology, University of Pennsylvania
Home page: http://www.sas.upenn.edu/~baron
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PLE
h a large dataset.
url:www.econ.uiuc.edu/~rogerRoger Koenker
emailrkoen...@uiuc.eduDepartment of Economics
vox: 217-333-4558University of Illinois
fax: 217-244-6678Urbana, IL 61801
On Jun 24, 2009, at 5:04 PM, Jonathan Gr
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R-help@r-project.org mailing list
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PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
--
Jonathan A. Greenberg, PhD
Post
and provide commented, minimal, self-contained, reproducible code.
--
Jonathan A. Greenberg, PhD
Postdoctoral Scholar
Center for Spatial Technologies and Remote Sensing (CSTARS)
University of California, Davis
One Shields Avenue
The Barn, Room 250N
Davis, CA 95616
Cell: 415-7
anks!
-scz
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R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
--
Jonathan A. Gree
I'm running the command:
file.copy(fnhdr,outdir,overwrite=TRUE)
Which successfully copies the file I want to the directory I want, but
each time it prints "FALSE" -- what does this mean, and how do I
suppress this output?
--j
--
Jonathan A. Greenberg, PhD
Postdoctoral
pling algorithm? Any help would be appreciated -- thanks -- I don't
see why a stratified sampling would take hours to run -- I am about to
recode this as a series of subset statements which I'm sure will take
only minutes...
--j
--
Jonathan A. Greenberg, PhD
Postdoctoral Scholar
C
it.el and .emacs files:
(global-set-key "\M-r" 'comment-region)
So now I do it with "alt-R". That key may have had some other
purpose, but not one I ever used.
I think the alt key is something else on a Mac. And I have no idea
whether this will work on Windows.
J
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> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
--
Jo
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