Readers,
Previous questions about this requirement have been for m$ users, my
failure occurs using linux.
I have tried to add the delta (δ) symbol to the y axis label and the
result is &D, using the command:
...ylab="δt"...
Any advice please?
rh...@conference.jabber.org
mandriva 2008
r 251 (27
Readers,
I am not able to create a postscript file with the following command:
postscript("/pathto/filename.eps,horizontal=FALSE,onefile="FALSE")
A file is not created, instead the command terminal shows the plus
sign(+) on a new line:
+
What does this mean please?
rh...@conference.jabber.org
On 17/08/2009, Patrick Connolly wrote:
> On Mon, 17-Aug-2009 at 11:51AM +0100, e-letter wrote:
>
> |> Readers,
> |>
> |> Previous questions about this requirement have been for m$ users, my
> |> failure occurs using linux.
> |>
> |> I have tried to add th
On 17/08/2009, Michael Knudsen wrote:
> On Mon, Aug 17, 2009 at 12:51 PM, e-letter wrote:
>
>> I have tried to add the delta (δ) symbol to the y axis label and the
>> result is &D, using the command:
>>
>> ...ylab="δt"...
>
> Try ylab = expr
On 18/08/2009, Gavin Simpson wrote:
> On Mon, 2009-08-17 at 11:51 +0100, e-letter wrote:
>> Readers,
>>
>> Previous questions about this requirement have been for m$ users, my
>> failure occurs using linux.
>>
>> I have tried to add the delta (δ) symbol to t
On 18/08/2009, Rodrigo Aluizio wrote:
> I'm not shure but I guess that you miss a " and putted it in the wrong
> place!
> Try this: postscript("/pathto/filename.eps",horizontal=FALSE,onefile=FALSE)
>
> Hope It helps.
Thank you, that did help a little, but the eps file was faulty and I
could not o
On 18/08/2009, Stefan Grosse wrote:
> On Tue, 18 Aug 2009 13:52:58 +0100 e-letter wrote:
>
> EL> On 18/08/2009, Rodrigo Aluizio wrote:
> EL> > I'm not shure but I guess that you miss a " and putted it in the
> EL> > wrong place!
> EL> > T
On 18/08/2009, Gavin Simpson wrote:
> On Tue, 2009-08-18 at 13:06 +0100, e-letter wrote:
>> On 17/08/2009, Michael Knudsen wrote:
>> > On Mon, Aug 17, 2009 at 12:51 PM, e-letter wrote:
>> >
>> >> I have tried to add the delta (δ) symbol to the y axis labe
On 19/08/2009, Gavin Simpson wrote:
> On Wed, 2009-08-19 at 14:20 +0100, e-letter wrote:
>> On 18/08/2009, Gavin Simpson wrote:
>> > On Tue, 2009-08-18 at 13:06 +0100, e-letter wrote:
>> >> On 17/08/2009, Michael Knudsen wrote:
>> >> > On M
Readers,
How do I configure R so that all units of measurement are in
millimetres? For example if I want to set the width of a graph, I want
to write:
width=100
and R interprets this value as millimetres.
Yours,
rh...@conference.jabber.org
r 251
mandriva 2008
___
On 18/08/2009, Stefan Grosse wrote:
> On Tue, 18 Aug 2009 16:08:36 +0100 e-letter wrote:
>
> EL> >
> postscript("/pathto/filename.eps",horizontal=FALSE,onefile=FALSE,paper="special")
> EL> >
> EL> This command created a small blank eps f
On 20/08/2009, Patrick Connolly wrote:
> On Thu, 20-Aug-2009 at 10:25PM +1000, Jim Lemon wrote:
>
>> e-letter wrote:
>>> Readers,
>>>
>>> How do I configure R so that all units of measurement are in
>>> millimetres? For example if I want to set the
Readers,
I have been reading the r book (Crawley) and tried to use the
influence measures function for linear regression, as described. I
have one datum that I wish to show in the graph but exclude from the
regression and ab line.
x y
0 5
10 9
20 10
30 19
40 4
Wit
On 14/09/2009, Steve Lianoglou wrote:
> Hi,
>
> On Sep 14, 2009, at 9:47 AM, e-letter wrote:
>
>> Readers,
>>
>> I have been reading the r book (Crawley) and tried to use the
>> influence measures function for linear regression, as described. I
>> have
On 15/09/2009, Uwe Ligges wrote:
>
>
> e-letter wrote:
>> On 14/09/2009, Steve Lianoglou wrote:
>>> Hi,
>>>
>>> On Sep 14, 2009, at 9:47 AM, e-letter wrote:
>>>
>>>> Readers,
>>>>
>>>> I have been readin
Readers,
I tried to the following commands:
plot(y~x,ylab=expression(A[1]~B[2],xlab=expression(C~D))
mtext(expression(A[1]~B[2]),"additional text",side=3,line=1)
I receive the text that I want, but the command terminal shows the
following response:
Warning message:
NAs introduced by coercion in
On 16/02/2010, Peter Ehlers wrote:
> On 2010-02-16 9:21, e-letter wrote:
>> Readers,
>>
>> I tried to the following commands:
>>
>> plot(y~x,ylab=expression(A[1]~B[2],xlab=expression(C~D))
>> mtext(expression(A[1]~B[2]),"additional text",side=3
I have data like so:
timedatum
30 12
60 24
90 37
120 41
150 8
In addition to standard deviation, I want to measure the average of
the differences in data for each time interval, i.e. average of 24-12,
37-24, 41-37, 8-41. Is there a statistical term for this task? Which
Readers,
Please refer to attached example data files. It seems that the merge
function fails for the latter section of the data set. Command
terminal output:
> library(chron)
> library(zoo)
> x<-read.zoo("test1.csv",header=TRUE,sep=",",FUN=times)
> y<-read.zoo("test2.csv",header=TRUE,sep=",",FUN=
Data files test1, ...2, ...3, ...4 respectively.
time1,dataset1
01:01:00,0.73512097
01:01:30,0.34860813
01:02:00,0.61306418
01:02:30,0.01495898
01:03:00,0.27035612
01:03:30,0.69513898
01:04:00,0.46451758
01:04:30,0.61672569
01:05:00,0.82496122
01:05:30,0.34766154
01:06:00,0.69618714
01:06:30,0.390
On 02/04/2010, Gabor Grothendieck wrote:
> The files only have one data column. What is the meaning of x[,2],
> etc. ? What is z1?
>
I only want to merge one column from one file with one column from
another file. With [x,2], I am trying to select the column of data.
> Please provide reproduci
On 02/04/2010, Gabor Grothendieck wrote:
> The code does not run with the files. I need the requested
> information, namely a single file containing code and data and that I
> can just copy into a session without editing and see the result you
> see.
I don't understand how I can combine the four
I tried your instructions, as shown.
> library(chron)
> library(zoo)
> z1<-read.zoo("test1.csv",header=TRUE,sep=",",FUN=times)
> z2<-read.zoo("test2.csv",header=TRUE,sep=",",FUN=times)
> z12<-merge(z1,z2)
> z3<-na.approx(z12,xout=time(z1))
Error in approx(along[!na], y[!na], along[na], ...) :
Readers,
For a command:
x<-a data matrix
y<-another data matrix
z<-and another data matrix
boxplot(c(x,y,z),las=1,xaxt="n",ylab="text",xlab="text",ylim=c(0,..?))
is it possible to specify only that the boxplot graph starts with
value 0 at the bottom of the ordinate (y axis) and the maximum value
Readers,
I have data with different time stamps that I wish to plot (for example):
data set 1
time(hh:mm:ss),datum
01:00:00,500
01:00:15,600
01:00:30,750
01:00:45,720
01:01:00,700
01:01:15,725
01:01:30,640
01:01:45,710
data set 2
time,datum
01:00:12,20
01:01:01,55
01:01:55,22
The time interval i
I created separate text files for the 2 data sets. I enter the
following comands:
library(zoo)
library(chron)
z1<-read.zoo(textConnection("/path/to/test1.txt"),header=FALSE,sep=",",FUN=times)
z2<-read.zoo(textConnection("/path/to/test2.txt"),header=FALSE,sep=",",FUN=times)
z3<-window(na.approx(mer
Test1 file contained data set 1, test2 contained data set 2
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, sel
I saved the data sets as files and then tried to refer to those files.
Therefore the instruction:
> z1<-read.zoo(textConnection("/path/to/test1.txt")
means that I wanted to replace the manual data entry for Lines1 with a
file containing the data. It seems that your instructions only work
when dat
Readers,
I have tried to use a plotmath command to add the temperature degree
sign (i.e. ᵒ C) to the axis label of a graph:
> x<-(1:10)
> y<-(200:191)
> plot(x~y,ylab=expression(*degree~C))
Error: syntax error, unexpected '*', expecting ',' in
"plot(x~y,ylab=expression(*"
According to plotmath m
Readers,
I am unable to plot a label consisting of both subscript text and
percentage (%) symbol:
x<-(1:10)
y<-(200:191)
plot(x~y,ylab=expression(~degree~C),xlab=expression(x[2]~%))
Error: syntax error, unexpected ERROR in
"plot(x~y,ylab=expression(~degree~C),xlab=expression(x~%)"
It seems that
Readers,
I have a data set as follows:
1,1
2,2
3,3
4,4
5,3
6,2
7,-10
8,-9
9,-3
10,2
11,3
12,4
13,5
14,4
15,3
16,2
17,1
I entered this data set using the command 'read.csv'. I want to
exclude values fewer than zero in column 2 so then I tried the
following command:
boxplot.stats(x[>0,2],do.conf=
Readers,
I have the following command:
expression(A[1]B~"%")
but that causes an error so I changed to:
expression(A[1]~B~"%")
but the result is too much whitespace between subscript and B. Is
there a way to reduce this whitespace?
Yours,
rhelp at conference.jabber.org
r 251
mandriva 2008
__
Readers,
I have tried to use the zoo package to merge datasets and then use the
coplot function, but the graph is not fully created. Only the panel
data is shown. Command terminal output below, with csv files. What is
the meaning of the warning message? Can anyone help please?
rhelpatconference.j
Readers,
Scenario: data x consists of one column;
1
2
3
data y;
4
5
6
Is it possible to write to file such that the file is:
1,4
2,5
3,6
using the write.file function? I have tried the command:
write(x,file="file.csv",ncolumns=1,append=TRUE,sep=",")
write(y,file="file.csv",ncolumns=1,append=TR
On 24/11/2009, jim holtman wrote:
> You can not append a column. Best bet, read the old file in, do a
> 'cbind', write the object back out.
>
> On Tue, Nov 24, 2009 at 5:59 AM, e-letter wrote:
>> Readers,
>>
>> Scenario: data x consists of one column;
>
Readers,
For a data set 'x':
1 a
2 b
3 c
4 d
5 e
6 f
7 g
8 h
9 i
How to select multiple subscripts to plot? For example to plot values
1:3 and 9:10:
plot(x[1:3,1],x[,2])
and
plot(x[9:10,1],x[,2])
into one plot?
Yours,
rhelpatconference.jabber.org
r251
_
On 13/01/2010, Duncan Murdoch wrote:
> On 13/01/2010 7:36 AM, e-letter wrote:
>> Readers,
>>
>> For a data set 'x':
>>
>> 1 a
>> 2 b
>> 3 c
>> 4 d
>> 5 e
>> 6 f
>> 7 g
>> 8 h
>> 9 i
>>
>> How t
On 13/01/2010, e-letter wrote:
> On 13/01/2010, Duncan Murdoch wrote:
>> On 13/01/2010 7:36 AM, e-letter wrote:
>>> Readers,
>>>
>>> For a data set 'x':
>>>
>>> 1 a
>>> 2 b
>>> 3 c
>>> 4 d
>>> 5
Readers,
I am trying to use the zoo package with an array of data:
file1:
hh:mm:ss1
hh:mm:ss2
hh:mm:ss3
hh:mm:ss4
file2:
hh:mm:ss11 55
hh:mm:ss22 66
hh:mm:ss33 77
hh:mm:ss44 88
I wanted to merge these data set s
Assuming my documentation is correct, my version shows faq 1 to refer
to duplicate times but if file2 is:
01:01:0111 55
01:01:0422 66
01:01:0733 77
01:01:1044 88
I cannot see what is duplicate? If I create two new files:
file3:
01:01:01
> library(chron)
> library(zoo)
> z1<-read.zoo("~/path/to/test1.csv",header=TRUE,sep=",",FUN=times)
> z2<-read.zoo("~/path/to/test2.csv",header=TRUE,sep=",",FUN=times)
> z3<-(na.approx(merge(z1,z2),time(z1)))
Error in approx(along[!na], y[!na], along[na], ...) :
need at least two non-NA val
Readers,
Two variables 'M', 'T', each contain a column of numbers.
Have tried to create a derivative function to see how 'M' varies with
respect to 'T':
dm<-D(m)(dm/dt)~dt
dm(m=M,t=T)
but R returns an error:
Error: could not find function "dm"
What is my mistake please?
--
R2151
___
Readers,
Am trying to use the function 'approx' to interpolate time series data sets:
data1:
01:23:40 5
01:23:45 10
01:23:50 12
01:23:55 7
data2:
01:23:42
01:23:47
01:23:51
01:23:54
The objective is to obtain interpolated values of 'data1' column 2 (5,
10, 12, 7) for the times shown in data2. T
Readers,
Responding to an old post
(http://tolstoy.newcastle.edu.au/R/e2/help/07/06/18850.html), and
using the example in the manual:
monthextract<-strptime("20/2/06 11:16:16.683", "%m")
monthextract
[1] NA
Why is the result 'NA' and not '2'?
--
r2151
__
On 16/01/2013, Rui Barradas wrote:
> Hello,
>
> Like this?
>
>
> data1 <- read.table(text = "
> 01:23:40 5
> 01:23:45 10
> 01:23:50 12
> 01:23:55 7
> ")
>
> data2 <- read.table(text = "
> 01:23:42
> 01:23:47
> 01:23:51
> 01:23:54
> ")
>
> approx(as.POSIXct(data1$V1, format = "%H:%M:%S"), y = data1
On 18/01/2013, Gabor Grothendieck wrote:
> On Fri, Jan 18, 2013 at 7:31 AM, e-letter wrote:
>> On 16/01/2013, Rui Barradas wrote:
>>> Hello,
>>>
>>> Like this?
>>>
>>>
>>> data1 <- read.table(text = "
>>>
On 18/01/2013, Gabor Grothendieck wrote:
> On Fri, Jan 18, 2013 at 7:31 AM, e-letter wrote:
>> On 16/01/2013, Rui Barradas wrote:
>>> Hello,
>>>
>>> Like this?
>>>
>>>
>>> data1 <- read.table(text = "
>>>
Readers,
Am trying to plot a graph with type 'h' and want to remove the white
space between the plot lines and the x axis. The help section 'par'
suggests that the option 'mai' controls this feature, but the syntax
plot(...mai=c(0,1,1))
is ineffective
Any advice please?
--
r2151
_
On 29/01/2013, Pascal Oettli wrote:
> Hi,
>
> Please provide a reproducible example.
>
test<-seq(10:50)
plot(test,type='h',mai=c(0,1,1))
Tried
plot(test,type='h',yaxs='i')
but this has the non-wanted effect of removing white space from
between the highest peak and the upper (top) axis
___
Readers,
For a graph plot instruction:
plot(seq(10:50),type='h',yaxt='n',yaxs='i',lab=c(20,2,2),xlab='x axis
label',bty='l',main='graph title')
how to remove y-axis label and keep the x-axis label?
_
r2151
__
R-help@r-project.org mailing list
https:/
Readers,
For a 12 hour time stamp:
> testtime<-("2013-01-01 01:00:01 PM")
> testtime
[1] "2013-01-01 01:00:01 PM"
> testtime24hour<-strftime(testtime,'%H:%M:%S')
> testtime24hour
[1] "01:00:01"
how to convert to 24 hour format so that the object 'testtime24hour' is:
'13:00:01'
Thanks.
--
r215
Readers,
Is it possible to add a data symbol (e.g. pch='21') to an axis label?
The objective is to plot a graph with two (2) y-axes and the plotting
character for data set 1 is added to the label of y1 axis (left); plot
character for data set 2 is added to label of y2 (right) axis.
Thanks.
--
r2
On 08/02/2013, e-letter wrote:
> Readers,
>
> For a 12 hour time stamp:
>
>> testtime<-("2013-01-01 01:00:01 PM")
>> testtime
> [1] "2013-01-01 01:00:01 PM"
>> testtime24hour<-strftime(testtime,'%H:%M:%S')
>> testtime24h
Readers,
Have since tried to plot converted 24 hour data:
testtimedataset
V1
1 13:01:41
2 13:02:10
3 13:02:38
4 13:03:05
5 13:03259
> testdata<-seq(1:5)
> plot(testdata~testtimedataset)
Error in function (formula, data = NULL, subset = NULL, na.action = na.fail, :
invalid type (list)
On 11/02/2013, PIKAL Petr wrote:
>
> str(testtimedataset)
With my real data set, revealed that after conversion, the time series
data consists of 'chr' which I guess means character type data,
reporting the following error:
Error in plot.window(...) : need finite 'xlim' values
In addition: Warni
Readers,
According to the help '?approxfun', the function can be used to obtain
the interpolated values. The following test was tried:
> testinterpolation<-read.csv('test.csv',header=FALSE)
> testinterpolation
V1 V2
1 10 2
2 20 NA
3 30 5
4 40 7
5 50 NA
6 60 NA
7 70 2
8 80
Readers,
For this data set:
testvalues<-c(10,20,30,40)
How to amend the plot instruction:
plot(testvalues,ann=FALSE,type='l',yaxt='n',xaxt='n')
so that x axis ticks labels can be added to existing graph with
arbitrary value such as 0,100,200,300)?
Thanks in advance.
--
r2151
___
On 14/02/2013, PIKAL Petr wrote:
> Hi
>
> much quicker and better for you is to inspect help pages.
>
> ?axis
>
> axis(1, at=1:4, labels=c(letters[1:4]))
Had tried, but noticed that the labels created were not positioned
equally across the entire axis, but occupied about 50 % (the left
half) of t
On 14/02/2013, MacQueen, Don wrote:
>> plot(testvalues,ann=FALSE,type='l',yaxt='n',xaxt='n')
>> par()$usr
> [1] 0.88 4.12 8.80 41.20
>
> The x axis range is from 0.88 to 4.12, so tick labels at 0, 100, 200, 300
> makes no sense.
>
True per se, but the purpose of the tick labels is to indicate
On 15/02/2013, Jim Lemon wrote:
> On 02/14/2013 09:41 PM, e-letter wrote:
>> Readers,
>>
>> For this data set:
>>
>> testvalues<-c(10,20,30,40)
>>
>> How to amend the plot instruction:
>>
>> plot(testvalues,ann=FALSE,type='l'
On 15/02/2013, Duncan Murdoch wrote:
> On 13-02-15 3:28 AM, e-letter wrote:
>> On 15/02/2013, Jim Lemon wrote:
>>> On 02/14/2013 09:41 PM, e-letter wrote:
>>>> Readers,
>>>>
>>>> For this data set:
>>>>
>>>> testvalu
Readers,
How to solve this unicode input error please?
> postscript("~/tmp/test.eps",width=100/25.4,height=100/25.4,horizontal=FALSE,onefile=TRUE,paper="special")
> testx<-seq(1:5)
> testy<-seq(1:5)
> plot(testy~testx)
> mtext('text (O₂)\n more text',side=3,line=1)
Warning messages:
1: In mtext("
On 19/02/2013, r-help-requ...@r-project.org
wrote:
> --
>
> Message: 22
> Subject: Re: [R] mtext unicode failure
>
> On 18/02/2013 14:15, e-letter wrote:
>> Readers,
>>
>> How to solve this unicode input error please?
>
> On
Readers,
Is it possible to create a plot command based upon the indices of
missing values in a data set?
dataset1<-read.table(text='
10 2
20 NA
30 5
40 7
50 NA
60 NA
70 2
80 6
90 NA
100 9
')
dataset2<-read.table(text='
0.2
0.4
0.1
0.9
0.2
0.3
1.1
0.7
0.9
0.6
0.4
')
The 'approx' function is used
On 16/11/2012, Rolf Turner wrote:
>
> Your question makes little sense. Functions have derivatives --- at
> least some of them do. Data sets do not have derivatives. The
> functions D(), deriv() etc. work on specified analytic expressions
> for functions --- data sets do not come into the pictu
Readers,
If a vector consists of:
10
20
30
how to create a new vector based upon the results of calculations to
the elements, e.g. addition of successive elements, so that a new
vector would be:
30
50
i.e. 10+20, then 20+30, etc.?
__
R-help@r-projec
Readers,
The function 'read.delim' was used to import data into R:
columnnamea columnnameb columnnamec
1 2 3
2 3 4
3 4 5
After import, the column names were:
X.columnnamea columnnameb columnnamec
Why did this occur?
--
r2151
__
R-help@r-project.org
Readers,
For a data set 'a':
1
2
3
4
Please what is the syntax to remove the last row and create a new object 'b':
1
2
3
Thanks.
--
R2151
__
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PLEASE do read the posting g
On 12/12/2012, Daniel Nordlund wrote:
>> -Original Message-
>> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
>> On Behalf Of e-letter
>> Sent: Tuesday, December 11, 2012 11:45 PM
>> To: r-help@r-project.org
>> Subject:
Readers,
A csv file was created:
column1,column2,column3,column4
1,10,3,2
2,20,6,4
3,30,12,16
4,40,24,256
The csv was imported:
testcsv<-read.csv('/path/to/test.csv')
testsum<-testcsv[2,2]+testcsv[2,3]+testcsv[2,4]
What is the correct syntax to abbreviate the following command using
the functi
On 13/02/2014, Rolf Turner wrote:
>
> What you've written is simply not (anything like!) R syntax. You should
> learn to speak R if you are going to use R.
>
Agree; was reviewing the help text examples invoked by '?with'.
> In this particular instance
>
> testsum <- sum(testcsv[2,2:4])
>
Readers,
I have been reading 'the r book' by Crawley and think that the
generalised additive model is appropriate for this problem. The
package 'gam' was installed using the command (as root)
install.package("gam")
...
library(gam)
> library(gam)
Loading required package: splines
Loading require
Readers,
I am trying to use the function dotchart. The data is:
> testdot
category values1 values2 values3 values4
1a 10 27 56 709
2b 4 46 47 208
3c 5 17 18 109
4d 6 50 49 308
The fol
On 18/12/2010, David Winsemius wrote:
>
> On Dec 18, 2010, at 7:01 AM, e-letter wrote:
>
>> Readers,
>>
>> I am trying to use the function dotchart. The data is:
>>
>>> testdot
>> category values1 values2 values3 values4
>> 1a 10
>Ben Bolker
>Sat, 18 Dec 2010 07:07:24 -0800
>David Winsemius comcast.net> writes:
>
>>
>>
>> On Dec 18, 2010, at 7:01 AM, e-letter wrote:
>>
>> > Readers,
>> >
>> > I am trying to use the function dotchart. The data is:
>&g
On 18/12/2010, Peter Ehlers wrote:
> On 2010-12-18 07:50, e-letter wrote:
>>> Ben Bolker
>>> Sat, 18 Dec 2010 07:07:24 -0800
>
> [... snip ...]
>
>> I am trying to create a chart like this
>> (http://www.b-eye-network.com/images/content/Fig4_3.jpg); so
On 18/12/2010, Peter Ehlers wrote:
> On 2010-12-18 07:50, e-letter wrote:
>>> Ben Bolker
>>> Sat, 18 Dec 2010 07:07:24 -0800
>
> [... snip ...]
>
>> I am trying to create a chart like this
>> (http://www.b-eye-network.com/images/content/Fig4_3.jpg); so
On 18/12/2010, e-letter wrote:
> On 18/12/2010, Peter Ehlers wrote:
>> On 2010-12-18 07:50, e-letter wrote:
>>>> Ben Bolker
>>>> Sat, 18 Dec 2010 07:07:24 -0800
>>
>> [... snip ...]
>>
>>> I am trying to create a chart like this
>
On 20/12/2010, e-letter wrote:
> On 18/12/2010, e-letter wrote:
>> On 18/12/2010, Peter Ehlers wrote:
>>> On 2010-12-18 07:50, e-letter wrote:
>>>>> Ben Bolker
>>>>> Sat, 18 Dec 2010 07:07:24 -0800
>>>
>>> [... snip ...]
>&
Readers,
The following commands were applied, to create a dot chart with black
dots and blue squares for data:
> library(lattice)
> testdot
category values
1b 44
2c 51
3d 65
4a 10
5b 64
6c 71
7d 49
8a
Readers,
According to the documentation for the function 'plotmath' there is no
apparent possibility to add the percent sign (%) to a plot function,
e.g.
plot(a[,1]~b[,2],ylab=expression(x~%),xlab=expression(z))
How to achieve this please?
yours,
rh...@conference.jabber.org
r251
mandriva2009
On 24/08/2010, Henrique Dallazuanna wrote:
> You've tried:
>
> plot(a[,1]~b[,2],ylab=expression(x~'%'),xlab=expression(z)) ?
>
This is successful for me, thank you. This instruction should be added
to the documentation for 'plotmath'.
__
R-help@r-projec
On 24/08/2010, David Winsemius wrote:
>
> On Aug 24, 2010, at 9:37 AM, e-letter wrote:
>
>> Readers,
>>
>> According to the documentation for the function 'plotmath' there is no
>> apparent possibility to add the percent sign (%) to a plot functi
>On Wed, 2010-08-25 at 09:32 +0100, e-letter wrote:
>> On 24/08/2010, David Winsemius wrote:
>> >
>> > On Aug 24, 2010, at 9:37 AM, e-letter wrote:
>> >
>> >> Readers,
>> >>
>> >> According to the documentation for the funct
>It's possible that my help page is different than yours. Right after
>the syntax/meaning description on mine (which is a Mac OSX system) is
>a paragraph:
>
>"The symbol font uses Adobe Symbol encoding so, for example, a lower
>case mu can be obtained either by the special symbol mu or by
>symbol("
Readers,
I have entered a file into r:
,column1,column2
row1,0.1,0.2
row2,0.3,0.4
using the command:
dataframe<-read.table("/path/to/file.csv",header=T,row.names=1)
When I try the command:
dataframe[,2]
I receive the response:
NULL
I was expecting:
row1 0.2
row2 0.4
What is my error with
On 31/05/2010, Gabor Grothendieck wrote:
> Use read.csv or read.table(..., sep = ","). Also note that if you
> delete the first comma of the header (as in the second example below)
> you won't have to specify row.names since it can figure it out from
> the fact that there is one fewer column name
Readers,
Data was imported using the read csv command:
dataimport<-read.csv("/path/to/dataimport.csv")
10,2000
12,2001
13,2002
15,2003
17,2004
Using the help contents for 'predict.lm' (i.e. ?predict.lm) a new data
frame was created
dataimportextra<-data.frame(x=seq(1990,2010,1))
predict(lm(dat
Readers,
For a data set:
text1,23,text2,45
text1,23,text3,78
text1,23,text3,56
text1,23,text2,45
The following command was entered:
datasubset<-data.frame(dataset[,3]=="text3")
The result of
datasubset
is
TRUE
TRUE
The required result is
text1,23,text3,78
text1,23,text3,56
What is the co
On 15/03/2011, Francisco Gochez wrote:
> Hi,
>
> What you are after is:
>
> datasubset <- dataset[ dataset[,3] == "text3", ]
Thank you. For the set
text1,23,text2,45
text1,23,text3,78
text1,23,text3,56
text1,23,text2,45
Is it possible to write a function that selects rows containing
'text3' and
Readers,
A data set consists of time-stamp values:
00:00:00
23:11:00
06:22:00
The data set was imported:
timestamps<-read.table("path/to/timestampsvalues")
hist(timestamps)
...error... x must be numeric
Then tried:
plot(timestamps).
How to adjust the graph to create a histogram where the in
On 16/07/2012, r-help-requ...@r-project.org
wrote:
> --
>
> Message: 77
> Date: Mon, 16 Jul 2012 10:48:39 +0100
> From: Rui Barradas
> To: e-letter
> Cc: r-help@r-project.org
> Subject: Re: [R] histogram of time-stamp data
>
On 16/07/2012, r-help-requ...@r-project.org
wrote:
> --
>
> Message: 77
> Date: Mon, 16 Jul 2012 10:48:39 +0100
> From: Rui Barradas
> To: e-letter
> Cc: r-help@r-project.org
> Subject: Re: [R] histogram of time-stamp data
> Message-ID
On 16/07/2012, Rui Barradas wrote:
> Hello,
>
> Em 16-07-2012 22:45, e-letter escreveu:
>> On 16/07/2012, r-help-requ...@r-project.org
>>wrote:
>> > --
>> >
>> > Message: 77
>> > Date: Mon, 16 Jul 20
On 17/07/2012, Rui Barradas wrote:
> Hello,
>
> That's not the error I've had. You must be aware that read.table creates
> a data.frame and therefore the object 'timestamps' is NOT holding time
> stamps, it's holding a vector, 'V1', of time stamps.
>
Was not aware of the significance of the data
Readers,
Attempting to solve the knapsack problem (e.g. see:
http://rosettacode.org/wiki/Knapsack_problem/Unbounded), the following
error occurred:
...
result would be too long a vector
Is this indicative that R is not suitable to solve this problem when
combinations are large?
Is there a known
Readers,
I am having difficulty understanding how to enter commands into r.
I have data arranged as:
100, 200, 300
5.6, 6.7, 7.8
8.9, 9.0, 0.1
1.2, 2.3, 3.4
The data is saved in csv format and I use the command 'read.table' to
import into r.
The values 5.6...3.4 are a function of values 100,..
Readers,
Using version 251 I tried the following command:
lm(y~a+b,data=datafile)
Resulting in, inter alia:
...
coefficients
(intercept) a
1.2 3.4
Packages installed:
acepack ace() and avas() for selecting regression
transformations
adlift
2008/5/15 Douglas Bates <[EMAIL PROTECTED]>:
> Did you happen to notice the part at the bottom of every message about
> "provide commented, minimal, self-contained, reproducible code"?
>
Sorry, don't understand what that statement means in my context.
> Considering that the result you quote from "
Professor Kubovy
As you instructed, below is the command terminal output:
sessionInfo()
R version 2.5.1 (2007-06-27)
i586-mandriva-linux-gnu
locale:
LC_CTYPE=en_GB.UTF-8;LC_NUMERIC=C;LC_TIME=en_GB.UTF-8;LC_COLLATE=en_GB.UTF-8;LC_MONETARY=en_GB.UTF-8;LC_MESSAGES=en_GB.UTF-8;LC_PAPER=en_GB.UTF-8;L
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