?offset
?formula
On Jun 4, 2010, at 4:53 PM, array chip wrote:
Hi, is it possible to specify a constant intercept (based on prior
knowledge) in linear regression using lm()?
Thanks
John
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https://stat.ethz.ch/ma
I would think this could be approached by segmenting the probability "volume"
using identities such as these:
P(Y1 < Z1, Y2 < Z2, Y3 > Z3, Y4 > Z4) + P(Y1 < Z1, Y2 < Z2, Y3 > Z3, Y4 < Z4) =
P(Y1 < Z1, Y2 < Z2, Y3 > Z3, Y4 < Inf)
and
P(Y1 < Z1, Y2 < Z2, Y3 < Z3, Y4 Z3, Y4 < Inf) =
P(Y1 <
It returns a chi-squared statistic with one degree of freedom.
--
David Winsemius
-- Original message --
From: Timthy Chang
>
>
> >See the cpower() and spower() functions in Frank Harrell's Hmisc package
> >on CRAN.
> >
> >HTH,
> >
> >Marc Schwartz
>
> How to
-- Original message --
From: Dimitri Liakhovitski
> Thank you for providing advice on this graphics question.
>
> I am building an interaction.plot.
>
> d=data.frame(xx=c(3,3,2,2,1,1),yy=c(4,3,4,3,4,3),zz=c(5.1,4.2,4.4,3.5,3.3,-1.1,-
> 1.3)
You have different l
Try setting exclude=NULL if you think that the NA's need to be considered as a
value.
The default is to exclude both NaN and NA.
--
David Winsemius
-- Original message --
From: "Farley, Robert"
> I presume the behavior below (no Connector values in the second
- Original Message -
From: "baptiste auguie"
To: "Gundala Viswanath"
Cc: "r-h...@stat.math.ethz.ch R-help"
Sent: Thursday, February 19, 2009 7:12:23 AM GMT -06:00 US/Canada Central
Subject: Re: [R] Insert value in a Vector Alternately
Perhaps you can try this,
> d <- c(0.003774
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