Hi,
My question might be a little general.
I have a number of values to select for the complexity parameters in some
classifier, e.g. the C and gamma in SVM with RBF kernel. The selection is based
on which values give the smallest cross validation error.
I wonder if the randomized splitting of
g smallest validation error. It appears to me the
splitting is once for all choices of the complexity parameter.
Thanks!
--- On Sun, 7/12/09, Tim wrote:
> From: Tim
> Subject: [R] Splitting dataset for Tuning Parameter with Cross Validation
> To: r-h...@stat.math.ethz.ch
> Date: Sunda
f
the stump tree , and 13.5, which I believe to be the threshold on the
feature. If I am able to get these two out, then I will be able to
further process them or write them into a file.
Any hint?
Thanks and regards!
-Tim
[[alternative HTML version deleted]]
feature ID. Is this the correct way to get the row label of
fit$splits[1,]?
Regards,
- Tim
--- On Fri, 5/8/09, Terry Therneau wrote:
From: Terry Therneau
Subject: Re: Get (feature, threshold) from Output of rpart() for Stump Tree
To: "Tim"
Cc: r-help@r-project.org
Date: Friday, May
to have a
more distinguishable plot of the ROCs. So is it possible to have a logarithm FP
axis which might probably separate them well? Or zoom in the part close to the
leftup corner of ROC plot? Or any other ways to make the ROCs more separate?
Thanks and regards!
--Tim
[[alterna
quot;, the color of bars are still black, the default one,
instead of red "2".
--Tim
--- On Tue, 5/12/09, Tobias Sing wrote:
From: Tobias Sing
Subject: Re: [R] ROCR: auc and logarithm plot
To: timlee...@yahoo.com, r-help@r-project.org
Date: Tuesday, May 12, 2009, 5:54 AM
> 1. I hav
#question I have the following data set:
Date<-c("9/7/2010","9/7/2010","9/7/2010","9/7/2010","9/7/2010","9/7/2010","9/8/2010")
EstimatedQuantity<-c(3535,2772,3279,3411,3484,3274,3305)
ScowNo<-c("4001","3002","4002","BR 8","4002","BR 8","4001")
dataset<- data.frame(EstimatedQuantity,Date,ScowNo)
I am trying to learn how to reshape my data set. I am new to R, so please
bear with me. Basically, I have the following data set:
site<-c("A","A","B","B")
bug<-c("spider","grasshopper","ladybug","stinkbug")
count<-c(2,4,6,8)
myf <- data.frame(site, bug, count)
myf
site bug count
1
file or directory
make[5]: *** [Rdfiles] Error 127
make[5]: Leaving directory `/home/USERACCOUNT/mybin/R-2.8.0/src/library'
file ../../library/base/R-ex cannot be opened at
../../share/perl/massage-Examples.pl line 136.
...
Is there any advice on what might be happening or on what I
Hi,
I've had a quick look through the package list, and unless I've missed
something, I can't seem to find anything that will do I-MR / Xbar-R /
Xbar-S control charts ?
Assuming there is something out there, can anyone point me in the
right direction ?
Interesting, thanks for that. I came accross qcc but my quick scan of
the docs is that it only did xbars but maybe I need to re-read the
docs, I guess it does the individual plot versions (I-MR) too.
Tim
On 8 July 2017 at 20:53, Rui Barradas wrote:
> Hello,
>
> I have no experience
perfect fit, but a p-value of 0.3112 doesn’t seem reasonable.
As a side note, the various r^2 values seem odd too.
Tim Glover
Senior Scientist II (Geochemistry, Statistics), Americas - Environment &
Infrastructure, Amec Foster Wheeler
271 Mill Road, Chelmsford, Massachusetts, USA 01824-4105
T
General linear constraints don't seem to work. I get an error message if I
have more constraint equations than variables. E.g. executing the following
code
print(R.version)
library('tmvtnorm')
cat('tmvtnorm version ')
print(packageVersion('tmvtnorm'))
## Let's constrain our sample to the dwarfed h
34
22 NA NA5
3 NA NA NA6
What am I missing?
Thanks,
Tim
[[alternative HTML version deleted]]
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PLEAS
Hello,
I am using R 3.1.1 on a (four year old) MacBook, running OSX 10.9.4.
I just tried making and labeling a plot as follows:
> x<-rnorm(10)
> y<-rnorm(10)
> plot(x,y)
> title(main="random points")
which produces a scatter plot of the random points, but without the title
and without any numbe
How can I create an improved version of a method in R, and have it be used?
Short version:
I think plot.histogram has a bug, and I'd like to try a version with a fix.
But when I call hist(), my fixed version doesn't get used.
Long version:
hist() calls plot() which calls plot.histogram() which fa
thz.ch
> > Subject: Re: [R] How can I overwrite a method in R?
> >
> > This is usually ill-advised, but I think it's the right solution for
> > your problem:
> >
> > assignInNamespace("plot.histogram", function(...) plot(1:10), "graphics")
> > hi
Another source of large datasets is the Public Data Sets on AWS
http://aws.amazon.com/public-data-sets/
Tim Hoolihan
@thoolihan
http://linkedin.com/in/timhoolihan
On Oct 28, 2014, at 7:00 AM, r-help-requ...@r-project.org wrote:
> --
>
> Message: 2
> D
Hi ,
I work for the NHS, and our IT service has been unable to download as its
anti-virus software says it contains an exploit.
Is this normal? Is there a way around this?
Kind regards,
Tim Kingston
Sent from my HTC
[[alternative HTML version deleted
insight would be very helpful. See error messages below. Thanks -- Tim
- When attempting to install, the print-out I get in the Console in RStudio
is any length of: > install.packages("swirl")
% Total% Received % Xferd Average Speed TimeTime Time
Current
rpg is a package for working with postgresql: https://github.com/thk686/rpg
odeintr is a package for integrating differential equations:
https://github.com/thk686/odeintr
Cheers,
THK
http://www.keittlab.org/
[[alternative HTML version deleted]]
__
rap is used for inference
(bias, standard error, confidence intervals), not improving on
ThetaHat.
Tim Hesterberg
>Hi Doran,
>
>Maybe I am wrong, but I think bootstrap is a general resampling method which
>can be used for different purposes...Usually it works well when you do not
>have a
thanks for any help you might be able to provide.
tim
--
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0406 753 997
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and pr
or "-"
and would like to convert these to characters or factors, without
having to specify the individual column types manually.
Is there any way to still do so in a new version of R?
Many thanks and best wishes,
Tim
__
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rements for each
day to check that the mean and max are likely to be valid (for example I
need at least 18 hourly measurements to calculate a valid daily mean)
Try as I might I have not found a simple way of doing this.
Can anybody help please?
Many thanks,
Tim.
--
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This mailing list is too intrusive. Remove my name.
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.ht
quot; "12:30:01" "12:45:01"
"13:00:00" "13:15:02"
This gives me the data taken at quarter hour intervals (removes 12:20:00) but I
am still left with multiple values at the quarter hours.
I would like to obtain:
"12:00:00" "12:15:05&quo
ontex, or what the number one at the end
does.
Thanks for you help,
Tim
Tim Clark
Department of Zoology
University of Hawaii
--- On Fri, 8/14/09, jim holtman wrote:
> From: jim holtman
> Subject: Re: [R] Finding minimum of time subset
> To: "Tim Clark"
> Cc: r-help@r
Jim,
Got it! Thanks for the explanation and the example. Always nice to learn new
tricks on R.
Aloha,
Tim
Tim Clark
Department of Zoology
University of Hawaii
--- On Fri, 8/14/09, jim holtman wrote:
> From: jim holtman
> Subject: Re: [R] Finding minimum of time subset
>
Thanks for everyones help and for the alternate ways of doing this. I am
always amazed at how many solutions this list comes up with for things I get
stuck on! It really helps us non-programmers learn R!
Aloha,
Tim
Tim Clark
Department of Zoology
University of Hawaii
--- On Fri, 8/14/09
slotNames().
> slotNames(mymcp)
[1] "data""polygons""plotOrder" "bbox" "proj4string"
What am I missing here? Is Slot "ID" not a slot? Can I export the ID's with
the shapefiles to qGIS? Can I rena
tell, neither can handle the task.
Does anyone know anything else that might work? Or generally know different?
Cheers,
Tim.
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PLEASE do read the posting guide http://
This is what I've done. Just capture two identifies and then replot.
If the identifies are right left, I zoom out. Works quite well.
Still, can't wait for iplot xtreme.
Cheers,
Tim.
On Thu, Sep 3, 2009 at 5:03 AM, Jim Lemon wrote:
> Tim Shephard wrote:
>>
>&
On Thu, Sep 3, 2009 at 1:25 PM, Jim Porzak wrote:
> Tim,
>
> I've had success (& user acceptance) simply plotting to a .pdf &
> passing zoom functionality to Acrobat, or whatever.
>
> Worked especially well with large US map with a lot of fine print annotation.
>
As far as I know there isn't anything available for this, but I
thought I'd check before working up something of my own.
Is there a way to query Amazon SimpleDB and import the data results
directly into R?
Cheers,
Tim.
__
R-help@r-project.o
st entry with only two values
p...@x.values[[1]] <- c(0,1)
p...@y.values[[1]] <- c(0,1)
p...@alpha.values[[1]] <- c(Inf,0)
plot(perf, avg="threshold")
##output results in an error with this message
# Error in if (from == to) rep.int(from, length.out) else as.vector(c(from, :
#
,y1,y1,y1,y2,y1,y2,y1,y2)
xy<-cbind(x,y)
I would like to know each time the numbers change.
Correct answer should be:
x=1,11,21,51,61,71,81,91
I would appreciate any help or suggestions. It seems like it should be simple
but I’m stuck!
Thanks,
Tim
Tim Clark
Department of Zoology
Unive
Thanks everyone! I would have been banging my head around for quite a while
and still wouldn't have come up with either solution. The function rle() is a
good one to know!
Aloha,
Tim
Tim Clark
Department of Zoology
University of Hawaii
--- On Wed, 2/10/10, Ben Tupper wrote:
&
# SEE WHAT RLE GIVES
test <- rle(xy[,2])
print(str(test)
# USE JIM"S TRICK OF CUMULATIVE SUMMING
# TO GET THE LOCATIONS
result <- cumsum(c(1,rle(xy[,2])$lengths))
Tim Clark
Department of Zoology
University of Hawaii
--- On Wed, 2/10/10, Ben Tupper wrote:
> From:
format (x1)?
#Sample data
x<-c(1,2,3,4,5,6)
y<-c(1,2,2,1)
#I need to format the data like this
x1<-c(1,1,2,2,NA,3,3,4,4,NA,5,5,6,6,NA)
y1<-rep(c(1,2,2,1,NA),length(x)/2)
#Final plot
plot(c(1,6), 1:2, type="n")
polygon(x1,y1,density=c(40))
Thanks,
Tim
Tim Clark
Department
Thanks Uwe! And Peter for the correction. I would never have come up with
that!
Tim
Tim Clark
Department of Zoology
University of Hawaii
--- On Fri, 2/12/10, Uwe Ligges wrote:
> From: Uwe Ligges
> Subject: Re: [R] Formatting question for separate polygons
> To: "Peter
Hi,
In my version of R, the stats package splinefun code for fitting a
Fritsch and Carlson monotonic spline does not appear to guarantee a
monotonic result. If two adjoining sections both have over/undershoot
the way the resulting adjustment of alpha and beta is performed can give
modified values
direction and moving one knot would
no longer guarantee that the curve changes in only a finite region) or
possibly shrink the coefficients twice (which would create a flatter
spline than necessary but would give a finite effect and the same curve
if the data were entered in the opposite dir
n't c give me the correct answer?
Thanks,
Tim
> a<-as.POSIXct("2000-01-01 12:00:00")
> a
[1] "2000-01-01 12:00:00 HST"
> b<-rbind(a,a)
> b
[,1]
a 946764000
a 946764000
> c<-as.POSIXct(b,origin="1970-01-01")
> c
[1] "2000
Glad to know it isn't just me! I couldn't use Phil's data.frame method since
my real problem went from a POSIXct object to a large matrix where I used rbind
and then back to POSIXct. Jim's function worked great on converting the final
product back to the proper date.
Than
One additional option on the Linux-on-the-local-machine option described below.
Consider running Microsoft's free virtual machine with a copy of Linux in
there. Now you have the advantages of dual-boot with BOTH operating systems
available with a toggle key sequence.
Tim Glover
S
Have you considered taking a random subset and plotting that? I'd bet you can
get a really impression of the distribution with a few hundred thousand points
at most.
Tim Glover
Senior Environmental Scientist - Geochemistry
Geoscience Department Atlanta Area
MACTEC Engineering and Consu
o that
it is easier to consume by machines, while being easy to read for
humans.
The early records are a serious machine parsing challenge as they are
tiff images of old notebooks ;-)
tia
Tim
Tim Coote
t...@coote.org
vincit veritas
__
R-he
documentation for. What is it that's removing the -999 and -888
values in this code -they seem to be gone, but I cannot see why.
Phil's reads in the data, but interleaves rows with just a year and
all other values as NA.
Tim
On 27 Feb 2010, at 17:33, Gabor Grothendieck wrote:
self-contained, reproducible code.
Tim Coote
t...@coote.org
+44 (0)7866 479 760
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide com
3.2 1.3 0.2 setosa
> 4 4.6 3.1 1.5 0.2 setosa
> 5 5.0 3.6 1.4 0.2 setosa
> 6 5.4 3.9 1.7 0.4 setosa
>
> Liviu
>
> ____
size of each slice, which makes for a different presentation than ggplot2. Any
suggestions on how to use this calculation method in the ggplot framework?
Thanks in advance for your help.
Tim Howard
New York Natural Heritage Program
__
R-help@r-projec
Hi,
I wanted to do the cox model using a matrix. The following lines illustrate
what I want to do:
dat <- matrix(rnorm(30), ncol=3,dimnames = list(1:10,letters[1:3]))
Survival <- rexp(10)
Status <- ifelse(runif(10) < .7, 1, 0)
mat <- as.data.frame(cbind(dat,Surviv
geom_bar(width=1) +
opts(axis.text.x =
theme_text(size = 18))
smp2 + coord_polar()
Cheers,
Tim
>>> Tim Howard 3/9/2010 9:25 AM >>>
Dear R gurus -
consider this plot:
library(ggplot2)
dat <- sample(1:8,100,replace=TRUE)
smp <- ggp
.g.
sqrt(countInBin/totalCount) . My goal is for area of the slice to correlate
with number of records in each bin (rather than area expanding at a faster
rate).
Thanks,
Tim
>>> hadley wickham 3/10/2010 9:14 AM >>>
For Q2 you can use opts(legend.position = c(0.9, 0.9)).
For Q3, y
Got it.
Thanks again so much for the help.
Best,
Tim
>>> hadley wickham 3/10/2010 2:46 PM >>>
> By Q2 I was trying to refer to the Y-axis labels. For the polar plot, the
> Y-axis labels reside left of the panel. I was looking for a way to get the
> Y-axis lab
Hi,
I wanted to make more than one side color bar. For example, I can make one side
color bar (col1) with the following code:
---
library(gplots)
mat <- matrix(sample(1:100,40),nrow=5)
class1 <- c(rep(0,4),rep(1,4))
col1 <- ifelse(class1 == 0,"blue","red")
class2
Hi,
Is there a way I can draw an abline on a heatmap? I try the abline function,
but don't get the line. My sample code is:
mat <- matrix(sample(1:100,40),nrow=5)
heatmap(mat,col=greenred(75),trace="none",
dendrogram = "column",labCol = NULL)
abline(h=5,v=4)
thanks!
[[alternati
iff<-diff(SP.utm$Lat)
d=(long.diff^2+lat.diff^2)^.5
speed=d/date.diff
Aloha,
Tim
Tim Clark
Department of Zoology
University of Hawaii
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PLEASE do read the po
t I'd want there is something
like:
> f1_denorm
c1c2 Split SplitDenorm
1 0 A,B,C A, B, C A
2 0 A,B,C A, B, C B
3 0 A,B,C A, B, C C
4 1 A,EA, E A
5 1 A,EA, E E
6 2 F,G,H F, G, H F
7 2 F,G,H F, G, H G
8 2 F,G,H F, G, H H
I thought perhap
#x27;t find a way to do this, the result I'd want there is something
like:
> f1_denorm
c1c2 Split SplitDenorm
1 0 A,B,C A, B, C A
2 0 A,B,C A, B, C B
3 0 A,B,C A, B, C C
4 1 A,EA, E A
5 1 A,EA, E E
6 2 F,G,H F, G, H F
7 2 F,G,H F, G
quot;],"%H")
and
hf$month <- as.POSIXct(strptime(hf$date, format = "%m"))
but they are still coming out as characters.
Any ideas please?
Thanks,
Tim.
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;hour"],"%H")
and
hf$month <- as.POSIXct(strptime(hf$date, format = "%m"))
but they are still coming out as characters.
Any ideas please?
Thanks,
Tim.
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Actually, the CI index and VIF are just a start. It is best to look at what
they call a matrix of "variance proportions" (found in SAS and a few other
places...)--which hardly anyone understands (including the SAS folks). It is a
matrix of estimates of what the variences of the regression coef
(07/30/02 00:00:00) (08/06/03 17:45:00)
Is there a reason different dates would come up as duplicate values? I would
prefer not to have to delete them if I don't have to. Any suggestions on how
to get R to realize they are different?
Thanks,
Tim
Tim Clark
Department of Zoolo
Don and Jim,
Thanks! I got it! Duplicated is only returning one of the two duplicated
dates (the second date). It all makes sense now!
Tim
Tim Clark
Department of Zoology
University of Hawaii
--- On Fri, 7/24/09, Don MacQueen wrote:
> From: Don MacQueen
> Subject: Re: [R] Dupl
choose between these and obtain the one with
the fewest missing values.
In my real dataset I have multiple variables collected every second and I would
like to subsample it every 5, 10, and 15 minutes.
I appreciate your help.
Tim
Tim Clark
Department of Zoology
Univer
write sql to make a table or
that I could run the sql, extract it to R, and then use sqlSave to save the
dataframe as a table in the db.
thanks in advance,
--
Tim Calkins
0406 753 997
[[alternative HTML version deleted]]
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nux-gnu
system i386, linux-gnu
status
major 2
minor 10.0
year 2009
month 10
day26
svn rev50208
language R
version.string R version 2.10.0 (2009-10-26)
And from installed.packages ():
xtsNA NA "GPL-3"
x
Jan 2010 6.08
> zoo (aggregate (vv, as.yearmon(index(vv)), mean))
x
Feb 2010 6.08
On 8 Apr 2010, at 15:53, Tim Coote wrote:
Hullo
I may have missed something blindingly obvious here. I'm using xts
to handle some timeseries data. I've got daily measurements for 100
y
x
Jan 2010 6.08
> zoo (aggregate (vv, as.yearmon(index(vv)), mean))
x
Feb 2010 6.08
On 8 Apr 2010, at 15:53, Tim Coote wrote:
On 8 Apr 2010, at 15:53, Tim Coote wrote:
Hullo
I may have missed something blindingly obvious here. I'm using xts
to handle some timeseries d
r
a valid alternative to narrowing down models when you have a lot of data and a
large number of variables your interested in.
Any thoughts on either of these methods? Or should I be doing something else?
Thanks for your help,
Tim
Tim Clark
Department of Zoology
University
, 0.88, 0.62, 0.19, 0.21, 0.01, 0.70, 1.00, 0.88, 0.04, 0.70, 0.93,
0.23, 0.99, 0.19, 0.79, 1.00, 0.03, 0.01, 0.00)
g1<-glm(y~cos((2*pi*lp)/29.530589)+sin((2*pi*lp)/29.530589))
Thanks,
Tim
Tim Clark
Department of Zoology
University of Hawaii
__
theta for the glm
model? The two models are:
mod.nb<-glm.nb(mantas~site,data=mydata)
mod.glm<-glm(mantas~site,data=mydata, family=negative.binomial(mod.nb$theta))
How else can I get theta for the family=negative.binomial(theta=???)
Thanks!
Tim
Tim Clark
Department of Z
n't use this method in ROCR
library(ROCR)
data(ROCR.xval)
RCdat <- plot(perf, avg="threshold")
RCdat
## output: NULL
Does anyone have any tricks for piping or extracting these data?
Or, perhaps for steering me in another direction?
Thanks,
Tim
From: "Tim Howard"
Sub
Whoops, sorry. Here is the full set with the missing lines:
library(ROCR)
data(ROCR.xval)
pred <- prediction(ROCR.xval$predictions, ROCR.xval$labels)
perf <- performance(pred,"tpr","fpr")
RCdat <- plot(perf, avg="threshold")
RCdat
Thanks.
Tim
>>> D
ll see
if
I can get in there and tweak it.
Thanks to both of you for the help.
Tim
>>> David Winsemius 9/24/2009 9:43 AM >>>
On Sep 24, 2009, at 9:09 AM, Tim Howard wrote:
> All,
> I'm trying again with a slightly more generic version of my first
> questio
Yes, that's exactly what I am after. Thank you for clarifying my problem for me!
I'll try to dive into the plot.performance function.
Best,
Tim
>>> Tobias Sing 9/24/2009 9:57 AM >>>
Tim,
if I understand correctly, you are trying to get the numerical values
of aver
Hi,
I was trying to read in a file test.txt, which has the following data:
norm normnormclass class class
a 1 2 3 4 5 6
b 3 4 5 6 7 8
c 5 6 7 8 9 10
in my R code, I do the f
ting a multiple line plot.
Thanks,
Tim
Tim Clark
Department of Zoology
University of Hawaii
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? I don't have to use matplot(), but would like to understand its
use.
Thanks,
Tim
Tim Clark
Department of Zoology
University of Hawaii
--- On Sun, 9/27/09, Henrique Dallazuanna wrote:
> From: Henrique Dallazuanna
> Subject: Re: [R] Data formatting for matplot
> To: "
Thanks for everyones help. It is great to have a number of options that result
in the same graph.
Aloha,
Tim
Tim Clark
Department of Zoology
University of Hawaii
--- On Mon, 9/28/09, Henrique Dallazuanna wrote:
> From: Henrique Dallazuanna
> Subject: Re: [R] Data formatti
Data Point",
ylab = "MCP Area",
ylim = c(0,150),
scales = list(tck = c(1, 0)), #Removes tics on top and r-axis
pch=19,cex=.4,
auto.key = list(title = "Mantas", x = .05, y=.95, corner =
c(0,1),border = TRUE)) #Legend
Thanks,
Tim
n you have data that groups in clusters
separated by a large range.
Aloha,
Tim
Tim Clark
Department of Zoology
University of Hawaii
--- On Mon, 9/28/09, Felix Andrews wrote:
> From: Felix Andrews
> Subject: Re: [R] xyplot help - colors and break in plot
> To: "Tim Cla
Did not work!
id<-factor(id,levels=c(7,8,9,4,5,6,1,2,3),lables=letters[1:9])
Your help would be greatly appreciated.
Tim
Tim Clark
Department of Zoology
University of Hawaii
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Peter,
Thanks, that did it!
Tim
Tim Clark
Department of Zoology
University of Hawaii
--- On Wed, 9/30/09, Peter Ehlers wrote:
> From: Peter Ehlers
> Subject: Re: [R] bwplot scales in alphabetical order
> To: "Tim Clark"
> Cc: r-help@r-project.org
> Date: Wednesd
nd to "100". So I am stuck.
What I want is:
homerange[[1]]$polygons$"100"
What I need is something like the following, but that works:
percent<-c("100","75","50")
p=1
paste(homerange[[1]]$polygons$,percent[p],sep="")
Thanks fo
at is what I am stuck
on. The result should be a vector the values for the "100","75",and "50"
levels, but not the "90" level.
Aloha,
Tim
Tim Clark
Department of Zoology
University of Hawaii
--- On Sat, 10/3/09, David Winsemius wrote:
> From:
ode and couldn't figure
it out. I knew there had to be an easier way.
I greatly appreciate all your help,
Tim
Tim Clark
Department of Zoology
University of Hawaii
--- On Sat, 10/3/09, David Winsemius wrote:
> From: David Winsemius
> Subject: Re: [R] Paste a character to an
similar to what is found on the
CoastWatch web page:
http://oceanwatch.pifsc.noaa.gov/imagery/GA2009281_2009282_sst_2D_eddy.jpg
Thanks!
Tim
Tim Clark
Department of Zoology
University of Hawaii
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https://stat.ethz.ch
Thanks! The colorRampPalette() did just what I need.
Tim
Tim Clark
Department of Zoology
University of Hawaii
--- On Fri, 10/9/09, Barry Rowlingson wrote:
> From: Barry Rowlingson
> Subject: Re: [R] Satellite ocean color palette?
> To: "Tim Clark"
> Cc: r-hel
between min(x) and max(x)).
Mark Hindell asked the same question in 2006
(http://tolstoy.newcastle.edu.au/R/e2/help/06/12/7034.html). I contacted him
and he never found a workable function. Has one been developed since then?
Thanks,
Tim
Tim Clark
Department of Zoology
University of Hawaii
within the series? (So for a monthly data set, calculate median
for all Januarys, all Februarys, all Marchs, etc.)
Thanks,
Tim
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at 4:09 PM, Kjetil Halvorsen <
kjetilbrinchmannhalvor...@gmail.com> wrote:
> introduce a factor variable with the months and then use tapply?
>
> Kjetil
>
> On Sun, Nov 1, 2009 at 9:07 PM, Tim Bean wrote:
> > Hello, I have a quick question about time series methodology. If
Hi,
I wanted to make a graph with the following table (2 rows, 3 columns):
a b c
x 1 3 5
y 5 8 6
The first column represents the start cordinate, and the second column contains
the end cordinate for the x-axis. The third column contains the y-axis
co-ordinate. For example, the first row in the m
Hi,
I was trying to get a graph in lattice with the following data frame (7 rows, 5
cols):
chr start1 end1 meth positive
1 1 10 20 1.5y
2 2 12 18 -0.7n
3 3 22 34 2.0y
4 1 35 70 3.0y
5 1120 140 -1.3n
6 1180 19
David Winsemius :
>
> On Nov 16, 2009, at 12:40 PM, Tim Smith wrote:
>
>> Hi,
>> I wanted to make a graph with the following table (2 rows, 3 columns):
>> a b c
>> x 1 3 5
>> y 5 8 6
>> The first column represents the start cordinate, and the second c
ke my final result to have two more columns in
cut.ltr[[1]]. One with speed, and the second with burst.
Thanks in advance for your help.
Tim
> cut.ltr[1:5]
*** List of class ltraj ***
Type of the traject: Type II (time recorded)
Irregular traject. Variable time lag between
er=c("A","B"),number=c(1,2))
df3<-data.frame(letter=c("A","B","C","D","E"),number=c(1,2,3,4,5))
df4<-data.frame(letter=c("A","B","C","D","E"),number=c(1,2,3,4,5))
lst<-li
Linlin,
Thanks! That works great!
Tim
Tim Clark
Department of Zoology
University of Hawaii
--- On Sat, 11/28/09, Linlin Yan wrote:
> From: Linlin Yan
> Subject: Re: [R] Removing objects from a list based on nrow
> To: "Tim Clark"
> Cc: r-help@r-project.org
> Da
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