I have a table like this:
Date TIME Q
A a1
A b2
A c3
B a4
B b5
B c6
C a7
C b8
C c9
I want use R language to turn it to a matrix like :
a b c
A 1 2 3
B 4 5 6
C 7 8 9
I am new to R , anyone can help? Than
Hi thanks ! that works perfectly ! now I am wodering how to create a new
table ,
I run the codes:
x<-read.table("C:/R/DATA.txt",colClasses=c("Date","character","integer"),
header=T)
DateTime<-as.POSIXct(paste(x[,1],x[,2]),format="%Y-%m-%d%H%M%S")
and get :
"2004-11-01 23:33:11 GMT"
"2004-11
Hello, I just start using R. I want to use ??fitdistr?? to fit distribution of
the data. Then how can I verify if the data really fit the distribution? Thanks
[data is attached]
res<-fitdistr(data$Report.delay, "Poisson")
h<-hist(data$Report.delay)
xfit<-floor(seq(0, 250, 50))
yfit<-dp
problem if I have different types of predictor variable
(factor and numerical)?
Any help would be greatly appreciated,
-- Jessica Lavabre-Micas
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
em or have
any ideas as to how to solve this?
Greatest appreciation,
Jessica
--
Jessica L Joganic
Graduate Student
Department of Anthropology
Campus Box 1114
Washington University
St. Louis, MO 63130-4899
email: jljog...@artsci.wustl.edu
[[al
**file.info* <http://file.info>*(x) : argument "destdir" is
missing, with no default*
Let me know if that doesn't clarify my query. If this ends up being a
product of my preferring the terminal over the R.app then I'll post to the
Mac people and see what they have to say.
Jessica
*
p then I'll post to the
> Mac people and see what they have to say.
>
> Jessica
> **
>
> On Mon, Feb 15, 2010 at 9:06 PM, David Winsemius
> wrote:
>
>>
>> On Feb 15, 2010, at 8:58 PM, Jessica Joganic wrote:
>>
>> Hi Fellow R Users,
>>> I recently
wnload.packages() instead of
install.packages() because they are both giving me the same error
message but at least download.packages() gives me some response by
loading a Tcl/Tk interface to select my CRAN mirror so I at least know
it's working.
Thank you all!
Jessica
On Mon, Feb 15, 2010 at 1
Hi everyone,
I've tried your various suggestions and through a combination of them
I think I've managed to make it work. This latest version appears to
be much more finicky than earlier ones. Thank you so much for all your
help!
Best to all,
Jessica
> On Wed, Feb 17, 2010 at 6:32
erence <=269) {Month <-"8-9 months"} else if
(curvedata$Date.difference <=299) {Month <-"9-10 months"} else if
(curvedata$Date.difference <=329) {Month <-"10-11 months"} else if
(curvedata$Date.difference <=359) {Month <-"11-12 months"} else
,
Jessica Schedlbauer
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
lumns and rows, rather than just
the datapoints appearing in rows. Is this possible?
Thanks,
Jessica
From: Felipe Carrillo [mazatlanmex...@yahoo.com]
Sent: Sunday, May 02, 2010 5:53 PM
To: Jessica Schedlbauer; r-help@r-project.org
Subject: Re: [R] Questi
Hello;
Can anyone tell me how to set my y-axis to a probability scale on an ECDF
plot? Or alternatively, how to generate a plot of percent cumulative
probability against concentration? DASplusR does this and calls it a CP
plot, but I would like to be able to generate this outside of DASplusR-
T
so any assistance would be
much appreciated.
Regards,
Jessica Schedlbauer
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commen
Following problem:
Say you have a bunch of parameters and want to produce results for all
combinations of those:
height<-c("high","low")
width<-c("slim","wide")
then what i used to do was something like this:
l<-list()
for(h in height){
l[[h]]<-list()
for(w in width){
o
On 20.12.2012, at 15:48, Chris Campbell wrote:
> Dear Jessica
>
> Aggregate is a function that allows you to perform loops across multiple
> variables.
>
> tempData <- data.frame(height = rnorm(20, 100, 10),
>width = rnorm(20, 50, 5),
>par1 = rnorm(20))
>
w, sep="/") # doSomething()
> }
> }
>
> grid <- expand.grid(height, width, stringsAsFactors=FALSE)
> as.character(grid[1,])
> # [1] "high" "slim", not the [1] "1" "1" you get with stringsAsFactors=TRUE
> l[[ as.c
@David : In my mind it was quite complete enough.
@William: Thanks, didn't know you could do that with data frames, if i ever
have to do something similar again i might try this.
On 20.12.2012, at 22:39, David Winsemius wrote:
>
> On Dec 20, 2012, at 10:01 AM, Jessica Stre
A bit of data might be useful. Make a small example and post the data with
dput().
On 24.12.2012, at 20:21, jenna wrote:
> I am trying to get the means of each participants avg saccade amplitude as a
> function of the group they were in (designated by "shape_"), but there are
> missing values in
Well for one, if ever someone looks at your code, cvtest[[lambda.rule]] is much
easier to read and understand than
eval(parse(text=paste0("cvtest$",lambda.rule)))
On 27.12.2012, at 11:44, Heramb Gadgil wrote:
> I am not sure why "Never ever!"
>
> Can you please elaborate. What are the negative
If test is the structure, will
test2<-sapply(test[,-c(1:4)],function(x){table(t(x))})
to what you want?
On 09.01.2013, at 15:48, jim holtman wrote:
> forgot the data. this will count the characters; you can add logic
> with 'table' to count groups
>
>
> x <-
> structu
Sorry, you wanted rows, i wrote for columns
#rows would be:
test2<-apply(test[,-c(1:4)],1,function(x){table(t(x))})
#find single values in a row
sapply(test2,function(row){
allVars<-paste(names(row),collapse="")
u <- unique(strsplit(allVars,"")[[1]])
parts<-sapply(names(ro
Maybe rle can help a little here
rle(b>1)
Run Length Encoding
lengths: int [1:5] 3 5 5 8 3
values : logi [1:5] FALSE TRUE FALSE TRUE FALSE
r<-rle(b>1)
r$lengths[r$values]
[1] 5 8
# started for the maximum but need to go home now, sorry. Will continue
tomorrow if noone else finishes it.
g
Sorry, but i don't get the problem at all.
Could you provide a bit of y by using dput()?
Can you provide an example of how you want the data to look like after the
transformation?
On 16.01.2013, at 16:42, Andrea Goijman wrote:
> Dear list,
>
> I'm working with a large data set, where I groupe
Rather unspecific.
Basically you'd need a loop to create the sets, and a way to write them into a
file.
You did not specify the format of your data. You might be able to use write,
write.table or write.csv and the like.
You could also have a look at ?save which allows you to save any R object.
Next time please provide sample data in a form we can easily read in (look at
?dput for example)
If i understand this right:
yourData<-read.table(header=T,text="
datedays rate
1996_01_02 155.74590
1996_01_02 505.67332
1996_01_02 785.60888
1996_01_0
You're not giving people much to work with. I googled the error, and it seems
to come from the call to optim and has likely to do with bad starting
parameters.
That said, the documentation of fitdistr doesn't suggest it even supports
"dbeta", there is only a "beta" mentioned.
On 22.01.2013, at
Or maybe
x<-matrix(test,nrow=10)
apply(x,2,mean)
On 23.01.2013, at 00:09, Wim Kreinen wrote:
> Hello,
>
> I have vector called test. And now I wish to measure the mean of the first
> 10 number, the second 10 numbers etc
> How does it work?
> Thanks Wim
>
>> dput (test)
> c(0, 0, 0, 0, 0, 0, 0
As an example:
chars<-c("A","A","B")
numbers<-as.numeric(as.factor(chars)) #make this numerical
plot(numbers,c(0.4,0.5,0.6),xaxt="n") #xaxt="n" says to not plot the x-axis
axis(side=1,at=numbers,labels=chars) #make the axis with labels
On 23.01.2013, at 10:16, Ng Wee Kiat Jeremy wrote:
> Dea
Professor of Anthropology
> Texas A&M University
> College Station, TX 77843-4352
>
>
>> -Original Message-
>> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
>> project.org] On Behalf Of Jessica Streicher
>> Sent: Wednesday, January 23
If you wanted this for all values in x that are smaller, i'd use
x[x$a < y$a,] <- y
for just the smallest:
x[intersect(which(x$a < y$a),which.min(x$a)),] <- y
On 29.01.2013, at 22:11, Dimitri Liakhovitski wrote:
> Hello!
>
> I have a large data frame x:
> x<-data.frame(item=letters[1:5],a=1:
greatly appreciated.
Thank you very much,
Jessica
_
Jessica Inskip, PhD Candidate
Cardiovascular Physiology Laboratory, K8512 | Department of Biomedical
Physiology and Kinesiology
Simon Fraser University, University Drive, Burnaby BC, V5A 1S6
Now i know why using else never worked for me - really, i'd consider this more
of a bug than a feature of the language ;)
On 17.09.2012, at 14:35, R. Michael Weylandt wrote:
> And now it is easy to see why we should all the one true brace style ;-)
>
> Michael
>
> On Mon, Sep 17, 2012 at 12:29
> paste("Trial and",x[1],"sheet")
[1] "Trial and a sheet"
> cat("Trial and",x[1],"sheet")
Trial and a sheet
On 18.09.2012, at 11:40, Sri krishna Devarayalu Balanagu wrote:
> Suppose I want the output as "Trial and a sheet" without quotes
> x=c("a", "b", "c")
> print("Trial and x[1] sheet")
>
>
> x<-c(NA , 1 ,NA, 1 , 1 , 1 , 1 , 1 ,1 ,NA , 1)
> embed(x,3)
[,1] [,2] [,3]
[1,] NA1 NA
[2,]1 NA1
[3,]11 NA
[4,]111
[5,]111
[6,]111
[7,]111
[8,] NA11
[9,]1 NA1
> which(rowSums(embed(x,
I'm making tables for prediction results of classifiers (2 classes) that show
the usual numbers, true positives, false positives, etc
I used the command
table(predictedLabels,realLabels)
to make those.
I just had a case though ,where one of the label vectors had only one class in
it. This wil
---
> Sent from my phone. Please excuse my brevity.
>
> Jessica Streicher wrote:
>
>> I'm making tables for prediction results of classifiers (2 classes)
>> that show the usual numbers, true positives, false positives, etc
>>
>> I used the c
ying
> Research Engineer (Solar/BatteriesO.O#. #.O#. with
> /Software/Embedded Controllers) .OO#. .OO#. rocks...1k
> ---
> Sent from my phone. Please excuse my brevity.
&g
Can i somehow append objects to an .Rdata file?
I didn't see an option for it in the save() method.
dump() won't work since i have s4 objects in there.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read th
You could set xlim and slim when using plot()
plot(vector,xlab="Period",ylab="Values",xlim=range(0,length(vector)+1),ylim=range(vector,est_vector,forecast))
i think - you forgot to provide data for the vectors :)
On 10.10.2012, at 11:31, piranha piranha wrote:
> Hello,
>
> i have been doing br
From: 발송실패알림
Subject:[발송실패 안내]
envy721c@naver.cobSDsnLzroZwg66mU7J287J20IOyghOyGoeuQmOyngCDrqrvtlojsig==teuLiOuLpC4=
The only plain english in the message is that the mail was denied by the
receiver
Anyone else getting this?
__
R-he
This is pretty confusing writeup, but if you have iterations, then yes, you
need a loop or a recursion.
A loop is probably easier, take a look at
?"for"
or
?apply
for this.
there are several derivates of apply
for example, say your outputs are what the code below gives you for each file,
m<-matrix(1:10,ncol=5)
> m
[,1] [,2] [,3] [,4] [,5]
[1,]13579
[2,]2468 10
apply(m,2,function(x){median(x,m[,5])})
[1] 5.5 6.5 7.5 8.5 9.5
Though i am not 100% sure thats what you mean. But the median of each row
between two columns kind of doesn't make
Actually i just saw that i copied the wrong code
apply(m,2,function(x){median(c(x,m[,5]))})
it should be.
Sorry if this confused anyone.
On 15.10.2012, at 15:32, eliza botto wrote:
>
> Dear Arun and Jessica,
> thnx for your reply. it realy worked out.
> regards
> eliza
>
&
- Why are you making a matrix for lookzone if it is ever only one number?
- changing a variable used for iteration is bad practice (input in this case)
though you aren't changing the rows i guess.
- There are too many x and too few y in those ifs.
Plus this is shorter:
test<-apply(input,
riment so its only around once.
I'll take a look at the lazy-load stuff too, thanks.
On 10.10.2012, at 19:47, J Toll wrote:
> On Tue, Oct 9, 2012 at 10:35 AM, Jessica Streicher
> wrote:
>> Can i somehow append objects to an .Rdata file?
>>
>> I didn't see an o
Hello Vignesh, we did not get any attachments, maybe you could upload them
somewhere?
On 19.10.2012, at 09:46, Vignesh Prajapati wrote:
> As I found the memory problem with local machine/micro instance(amazon) for
> building SVM model in R on large dataset(2,01,478 rows with 11 variables),
> the
t have any experience with either Rstudio or Amazon whatever. The local
system seems to be windows so the above might work, don't know the other, you
might need to change the memory limit at startup of the console if its not.
On 22.10.2012, at 10:18, Vignesh Prajapati wrote:
> Hello Jessic
s <- seq(0.8, 1.2, by = 0.1)
as.list(s)
to get the first type of list from the sequence.
On 30.10.2012, at 16:51, ONKELINX, Thierry wrote:
> You first example is a list of 5 items, each item is a number
> The second example is a list with one item: a vector with 5 elements.
>
> You'll need c()
A look at the tutorial might help here, but anyway:
Say you have that dataframe down there with the name myData (you should use
dput() to give us the data btw),
then you can subset that by using myData[rows,columns], where left of the comma
you define which rows you want, and right of the comma
se or if you need any more information?
Any help or guidance would be massively appreciated.
Best wishes
Jessica Timms
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
P
Hi,
I still seem to be getting errors from trying to run my altered R script, any
advice?
Thanks
Jess
Model1A = function(meth_matrix,exposure, X1, X2, X3, batch) {
+
+ mod = lm(methcol ~ exposure+X1+X2+X3+batch, data = meth_matrix)
+
+
+ res=coef(summary(mod))[2,]
+
+
+ }
>
>
> ##Run
please provide a bit of the dataframe in the future using the dput() function
> x<-data.frame(height=1:10,
> color=sample(c("blue","green","brown"),10,replace=T))
> x
height color
1 1 blue
2 2 green
3 3 blue
4 4 brown
5 5 blue
6 6 brown
7 7 green
8
I really don't understand what you want to achieve and how your data presents
itself.
You have several combinations of trial/subject which are unique?
There is a variable for each such combination that you want to test against
(tt)?
In addition you have data on each such combination (several set
I didn't have the same exception yet, but please make sure you have a stable
connection (avoid wlan).
I personally ran out of memory very often and had to make several queries,
combining the results in R instead.
This is probably not the best thing to do, but worked for me to fetch large
amount
Actually forget that loop, that was old code. Now remember i had to actually
split the one query down into several queries to get everything.
On 01.11.2012, at 18:38, Jessica Streicher wrote:
> I didn't have the same exception yet, but please make sure you have a stable
> connec
It depends a bit on your setup, but you could have a look at
?memory.size
or
?memory.limit
and see if any of that helps
Jessi
On 05.11.2012, at 12:49, Haris Rhrlp wrote:
> Dear R users,
>
> I have this problem with memory i guess
>
> AA<-array(rep(0,96096000),dim=c(16,5,3003,400))
> Error
I'll second the full path option.
Just create a variable path_to_data and concatenate it with the names of any
files you need in that directory.
You could also try to use relative paths if the data is "nearby" and is likely
to not change that position.
e.g. if the data was in '/home/r/Documents
Not that i really understand what that shall do, but..
why do you define 2 functions that do exactly the same?
why do you want to make a matrix of functions instead of a matrix with the
results of functions?
On 06.11.2012, at 05:11, Aimee Kopolow wrote:
> Hi all,
>
>
> I have a matrix simulat
If i understand this correctly, what you want to use is a vector or a list as a
parameter to that function.
getdata<-function(letterVec){
...
query<-paste("SELECT *FROM myfile1 where MODEL in",
sqlListFromVector(letterVec))
...
}
sqlListFromVector<-function(v){
Its not scaling.. so..
I guess i'll stay severely frustrated, and yes i know this is probably not
enough information for anyone to help.
Still, talking helps ;)
On 15.11.2012, at 15:15, Jessica Streicher wrote:
> with
>
> pred.pca<-predict(splits[[i]]$pca,trainingData
with
pred.pca<-predict(splits[[i]]$pca,trainingData@samples)[,1:nPCs]
dframe<-as.data.frame(cbind(pred.pca,class=isExplosive(trainingData,2)));
results[[i]]$classifier<-ksvm(class~.,data=dframe,scaled=T,kernel="polydot",type="C-svc",
C=C,kpar=list(degree=degree,scale=scale,offset=
Now i let it run for one specific set and got the same bad result, then i
deactivated the probabilities and got a good result, then i activated the
probabilities again and got a good result .. huh???
On 15.11.2012, at 15:32, Jessica Streicher wrote:
> Its not scaling.. so..
>
> I g
70
[12,] 0.291356830
[13,] 0.291341980
[14,] 0.291324840
[15,] 0.291326520
Now that i managed to get me (and you) a closer look - seems like class labels
switched maybe? pred.svm[,2] is named "1", but seems to have the probability to
be class 0 in it.
This does not al
Guess it has something t do with the values in prob.model. The classifiers with
bad predicitons have positive values and the ones with good predictions have
negative values.
On 15.11.2012, at 17:18, Jessica Streicher wrote:
> I'll try .. lets see
>
> dput(dframe)
> struc
Hi again!
This might be more of a statistical question, but anyway:
If i train several support vector machines with different degrees of
polynomials, and as result, get that higher degrees not only have a higher test
error, but also a higher in-sample error, why is that?
I would assume i shoul
Fixed it by using e1071 instead..
On 15.11.2012, at 17:43, Jessica Streicher wrote:
> Guess it has something t do with the values in prob.model. The classifiers
> with bad predicitons have positive values and the ones with good predictions
> have negative values.
>
> On 15.11
wrong with the asumption, that if i get those
probabilities, that 0.5 is the threshold to get "the default" result?
On 16.11.2012, at 16:32, Jessica Streicher wrote:
> Hi again!
>
> This might be more of a statistical question, but anyway:
> If i train several support vector m
At least for me this is not enough information to go on Elli.
What exactly is the problem? Can you post example data?
On 20.11.2012, at 18:39, Elli wrote:
> How I can plot the standard deviation and variance separately or is there a
> graph where I can show the two?
>
>
>
> --
> View this mes
rly visible in just one plot with hundreds of
variables.
some kind of distribution maybe, like how likely some value of variance is?
do you have an example of what it should look like?
Whats the purpose of plotting it?
On 20.11.2012, at 19:22, Jessica Streicher wrote:
> At least for me this is
Anyway, need to go home. If you really only want to plot the values of all
variables, and its for some reason not important what value belongs to what
exact variable:
plot(variances,ylim=range(variances,sdevs)) # black circles
points(sdevs,col=2,pch=3) #red crosses
On 20.11.2012, at 19:32, Elli
, the glht function yields the expected results without problems.
Can anyone help? Is the glht function not appropriate for binary data? Or
have I got something wrong?
Thank you!
Jessica
My data and code are below.
# My data:
Nest<
Hello Bikek,
please use dput() next time to provide the data, its easier to use that.
also: looking at the data provided, how would you want to decide which value of
the non-unique times to retain? Just take the first one? They aren't all the
same.
On 30.11.2012, at 16:59, bibek sharma wrote:
TRUE
mtest[!duplicated(mtest[,1:2]),]
id time value
[1,] 13 1
[2,] 12 3
[3,] 11 4
[4,] 21 5
[5,] 23 6
On 30.11.2012, at 17:15, Jessica Streicher wrote:
> Hello Bikek,
>
> please use dput() next time to provide the data, its easier to
Thats not a very precise question. I'll try anyway..
- if you use c, you need to separate the values by commas
- i think you mean seq(1,100,0.1), otherwise x only has one value
- function sen is not defined
- If you call int(1), upper will be 1, not x[i]
- why are you making a function and calling
This is not a reproducible example ;)
anyways, dcast has an attribute:
drop
should missing combinations dropped or kept?
does that not do what you want?
On 03.12.2012, at 16:07, michael.laviole...@dhhs.state.nh.us wrote:
>
> Hello--I'm doing a simple crosstab using dcast:
>
> rawfreq <- d
ll if necessary.
thanks, Jessica
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Nevermind, found i can at least do it with pdf() and consorts, so i'll get it
right in my images, and thats the main point.
On 03.12.2012, at 18:06, Jessica Streicher wrote:
> I'd like to make plots that do not have the quadratic layout, like having a
> plot that is twice as wi
You need to install the party package and then load the package before you can
use its functions:
install.packages("party")
library(party)
On 11.12.2012, at 16:56, Peterson, Kim - DNR wrote:
> Greetings! I'm trying to use function varimpAUC in the party package
> (party_1.0-3 released Septemb
dataset<-data.frame(id=c(1,1,2,3,3,3),time=c(3,5,1,2,4,6))
dataset
id time
1 13
2 15
3 21
4 32
5 34
6 36
ids<-unique(dataset$id)
for(id in ids){
+ dataset$time[dataset$id==id]<-c(0,diff(dataset$time[dataset$id==id]))
+ }
dataset
id time
1 10
2 1
f<-factor(c(1,1,2,3))
n<-c(1,1,2,3)
df<-data.frame(f,n)
sapply(df,is.factor)
f n
TRUE FALSE
df[sapply(df,is.factor)]
f
1 1
2 1
3 2
4 3
df[sapply(df,is.numeric)]
n
1 1
2 1
3 2
4 3
something like that?
On 17.12.2012, at 11:02, Martin Spindler wrote:
> Dear R users,
>
> I have a dataf
7/library/uroot/html/HEGY.test.html it works, but for
my time series it doesn't (giving names to the columns and rows did not help
either...).
Thanks for your help.
Jessica
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r
ariates I use.
Any help with these problems would be greatly appreciated!
Thanks,
Jessica Myers
Instructor in Medicine
Division of Pharmacoepidemiology
Brigham and Women's Hospital
The information in this e-mail is intended only for the ...{{dropped:7}}
_
Hello everyone.
In my last post I did not explained my problem quite well. I made a principal
component analysis and took the 2 first principal components. I made ââa
chart of my points based on the score of the 2 PC. I would like to add on this
graph a 95% confidence region. To do this
the confidence ellipse. But I have no clue how to do it
Can anyone help me?
Best regards
Jessica
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman
I am applying a GLS model and would like to look at diagnostic plots of
influence.
The function (plot(model)) that works for linear models does not seem to
function for GLS models. Is there a reason for this? Or is different code
required?
Sorry if it's a very basic question, but thanks for you
My issue relates to adding text to a matrix and finding that the text is
converted to a number.
This is the section of code I'm having trouble with:
# First, I load in a list of names from a .csv file to 'names'
names <- read.csv(file("Names.csv"))
# Then I define a matrix which will be p
Thanks for all your help. I found adding the 'stringsAsFactors' condition
solved the problem.
On 1 June 2010 17:09, Joris Meys wrote:
> Hi Jessica,
>
> this tells me that your text is saved as a factor.
> Try :
> names <- read.csv(file="Names.csv",st
reted by the function, rather than the object names.
For example,
x1 <- 1:4
x2 <- 2:5
x3 <- 3:6
xs <- c("x1", "x2", "x3")
If I wanted to cbind(x1, x2, x3) without typing this out, how would I
do it?
Thanks very much!
Jessica Myers
Instructor in Me
Thanks - your last suggestion does seem to work with the ridge
function, but the names of the objects get lost in the process. Is
there a way to keep the object names with get?
Thanks,
Jessica Myers
On Apr 21, 2011, at 11:00 AM, Uwe Ligges wrote:
On 21.04.2011 16:03, Jessica Myers
http://stackoverflow.com/questions/9399459/r-sweave-arguments
google is your friend ;)
Am 06.06.2012 um 15:29 schrieb manish gupta:
> I don't want to use it as manual. I want my software to automated.
>
> On Wed, Jun 6, 2012 at 9:13 PM, Yihao Lu wrote:
>
>> you use this list as your manual?
Well, i have my System not set up to run from command line, so i can't help you
there, but the scipt solution
id<-1
Sweave('test.Rnw') #printing out the id
works fine for me. There were several other suggestions in the answers given in
the link.
Am 07.06.2012 um 09:30 schrieb Manish Gupta:
>
c(argList[2]))
print(PatientId)
@
results in:
\begin{Schunk}
\begin{Soutput}
[1] "PatientId=2"
\end{Soutput}
\begin{Soutput}
[1] "PatientId" "2"
\end{Soutput}
\begin{Soutput}
[1] 2
\end{Soutput}
\end{Schunk}
Am 08.06.2012 um 11:00 schrieb Jessica Streicher:
>
http://www.walware.de/goto/statet
eclipse plugin
Having tried both sweave and knitr:
Knitr is easier to set up by far, but i don't like its documentation, so i
stayed with Sweave.
I needed a few days to get it running properly though, and it needed
workarounds.
Am 12.06.2012 um 00:32 schrieb Tr
Hi!
I am getting a lot of numbers in the background of the pca screeplots if i use
call("plot") and eval(somecall).
Til now, creating the calls and plotting later on this way worked fine. Example:
pcaI<-prcomp(iris[,1:4])
plot(pcaI)
x<-call("plot",pcaI)
eval(x)
Anyone got an idea how i can
Thanks Josh,
that soggy sandwhich saves me a LOT of code by the way,
I'll keep it for the time being ;)
greetings
Jessica
On 28.06.2012, at 17:15, Joshua Wiley wrote:
> Hi Jessica,
>
> x <- call("plot", quote(pcaI))
> eval(x)
>
> that said, I suspect y
ts will be saved to files.
I'm saving several lines of latex and several lines when creating the file each
time i use it, and i use it often.
On 28.06.2012, at 17:47, Joshua Wiley wrote:
> On Thu, Jun 28, 2012 at 8:27 AM, Jessica Streicher
> wrote:
>> Thanks Josh,
>>
&
On 29.06.2012, at 10:05, Jessica Streicher wrote:
> Well, i built the methods to create a bit of latex and plot to pdf files for
> figures, especially figures with subfloats, which weren't possible with
> sweave (at least i didn't find a way). So i only have to make the cal
Hm.. i attached a file with the code, but it doesn't show up somehow..
On 29.06.2012, at 10:13, Jessica Streicher wrote:
>
>
> On 29.06.2012, at 10:05, Jessica Streicher wrote:
>
>> Well, i built the methods to create a bit of latex and plot to pdf files for
>>
Then lets go with this:
http://pastebin.com/6dtGCrpA
as an example of what i do. If you've got a better idea lets hear it :)
On 29.06.2012, at 17:30, Joshua Wiley wrote:
> On Fri, Jun 29, 2012 at 1:20 AM, Jessica Streicher
> wrote:
>> Hm.. i attached a file with the code, bu
1 - 100 of 202 matches
Mail list logo
