Hi
I'm storing two functions in a list
# creating two function
function1 <- function(n) {
return(sum(n))
}
function2 <- function(n) {
return(mean(n))
}
#storing the function
function3 =c(function1,function2)
is it possible to call the stored function and used it ?
x=c(10,29)
funtion3[
On 08.02.2012 22:10, Martin Morgan wrote:
On 02/08/2012 12:13 PM, Ben Ganzfried wrote:
Hi Uwe,
Thanks for the help. R version 2.14.0 (2011-10-31). The file in question
looks like this (w/ a few minor edits for privacy):
There are two 'description' entries; the second might be combined with
Thanks for nice explanation.
Unfortunately, matrix in my question is exactly similar to the one I posted
earlier :
mat <- matrix(rnorm(700), ncol=5, dimnames=list( paste("f", c(1:140),sep="_"),
c("A", "B", "C", "D", "E")))
Question here is which of the 140 characteristics (i.e. f_1...f_140
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On 09/02/12 00:01, Peter Langfelder wrote:
> Hi all, in particular package developers,
>
> I'm exploring using a version control system to keep better track
> of changes to the packages I maintain. I'm leaning towards git
> (although mercurial also lo
On 09.02.2012 08:54, arunkumar wrote:
Hi
I'm storing two functions in a list
# creating two function
function1<- function(n) {
return(sum(n))
}
function2<- function(n) {
return(mean(n))
}
#storing the function
function3 =c(function1,function2)
is it possible to call the stored
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On 09/02/12 00:33, Tom Roche wrote:
>
> Peter Langfelder Thu Feb 9 00:01:31 CET 2012
>> I'm exploring using a version control system
>
> +1! welcome to the new millenium :-)
>
>> to keep better track of changes to the [R] packages I maintain.
>> I'm
Dear all,
I'm using xtable package in order to produce Latex table. There is a way to
specify not only the alignment but also the width of table colums??
Thanks for your attention.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listin
Once upon a time r-forge had the option to sync from an external svn
repository, e.g. hosted on googlecode. I haven't seen it available for
some time, sadly. I'm sure many users would appreciate if this feature
came back with the new interface. Not sure if it could work with git
as well, though.
b
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On 09/02/12 10:09, baptiste auguie wrote:
> Once upon a time r-forge had the option to sync from an external
> svn repository, e.g. hosted on googlecode. I haven't seen it
> available for some time, sadly. I'm sure many users would
> appreciate if t
Dear Andrew,
Thanks for your suggestion.
I will indeed have a look at Allison's booklet...
Best,
On 7 February 2012 23:39, Andrew Miles wrote:
> Based on Paul Allison's booklet "Fixed Effect Regression Models" (2009), the
> FE model can be estimated by person-mean centering all of your variable
Justin Fincher wrote:
> Howdy,
> This should be simple, but I am finding that I can't find a simple
> solution. I have a plot to which I am manually adding the annotations
> to the y-axis with this command:
>
> axis(2,
c(-4,-3,-2,-1,0,1,2,3,4,5,6,7),labels=c(-4,-3,-2,-1,0,1,2,3,4,5,6,7),cex.
Hi all,
I've got the following matrix :
mat <- matrix(rnorm(700), ncol=5, dimnames=list( paste("f", c(1:140), sep="_"),
c("A", "B", "C", "D", "E")))
I can see that currently most of the multivariate Hotelling T2 tests are
limited for application on two groups/samples.
I wud appreciate if so
On Wed, Feb 08, 2012 at 05:01:01PM -0500, Sam Steingold wrote:
> loop is too slow.
> it appears that sparseMatrix does what I want:
>
> ll <- lapply(l,length)
> i <- rep(1:4, ll)
> vv <- unlist(l)
> j1 <- as.factor(substring(vv,1,1))
> t <- table(j1)
> j <- position of elements of j1 in names(t)
>
Hi,
You can set the width of the columns the same way you would in any other LaTeX
table, e.g., by setting align to p{width}.
http://www.giss.nasa.gov/tools/latex/ltx-68.html has a good summary of LaTeX
tables that you may find helpful.
Best,
Ista
On Thursday, February 09, 2012 10:08:32 AM n.
Dear all,
I have question but cannot explain without providing some context first:
I want to calculate how many policy-connected coalitions between 7 parties are
possible. I have positions on an one-dimensional scale for each party and I
have sorted the parties on the positions (it is sorted fr
Hello everybody!
Let's assume I have the following factor with it's levels:
a<-factor(c(2,3,3,2,4,2,3,2,2,2,3,2,3))
mydata<-data.frame(a)
When I plot the vector "a" using
barplot(table(mydata$a)
unfortunately the value "1" does not
show up, as it does not appear in my data.
But still, it theor
Hi
Here is an example with something at hand if you use Sweave.
Using Sweave you can embed the R in a chunk and properly format the
headers and sometimes the table.
the D{.}{.}{4.0} requires the use of \usepackage{dcolumn}
\begin{table}[h]
\caption[DNO and \rdate]%
{DNO and \rdate with row to
Hi
>
> Hello everybody!
>
> Let's assume I have the following factor with it's levels:
>
> a<-factor(c(2,3,3,2,4,2,3,2,2,2,3,2,3))
> mydata<-data.frame(a)
>
> When I plot the vector "a" using
>
> barplot(table(mydata$a)
>
> unfortunately the value "1" does not
> show up, as it does not appea
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Hash: SHA1
Hi
This question is towards development of packages, but I think it does
not fit into R-devel mailing list, so I post it here.
I would like to use git as the VCS for my packages, but still be able
to use the "magic" of R-forge.
I know how to mgrate
On Thu, Feb 09, 2012 at 12:18:06PM +, Schumacher, G. wrote:
> Dear all,
>
> I have question but cannot explain without providing some context first:
>
> I want to calculate how many policy-connected coalitions between 7 parties
> are possible. I have positions on an one-dimensional scale for
Hi David,
On Thursday, February 09, 2012 01:21:48 PM David Studer wrote:
> Hello everybody!
>
> Let's assume I have the following factor with it's levels:
>
> a<-factor(c(2,3,3,2,4,2,3,2,2,2,3,2,3))
> mydata<-data.frame(a)
#You need to specify levels and labels here, like this:
a <- factor(c(2
> It seems there is a function ?tt? in R which can help to find this
> function and integrate it in my Cox model.
> I am searching a good tutorial (or book reference) with example(s) to
> understand and apply the function ?tt? in R;
There is a vignette describing the tt function. Due to an overs
On Feb 9, 2012, at 12:11 , Vickie S wrote:
>
> Hi all,
> I've got the following matrix :
>
> mat <- matrix(rnorm(700), ncol=5, dimnames=list( paste("f", c(1:140),
> sep="_"), c("A", "B", "C", "D", "E")))
>
> I can see that currently most of the multivariate Hotelling T2 tests are
> limited
This can be done without nested loops.
a <- expand.grid(rep(list(c(0,1)),7))
tmp <- apply(a, 1, function(x){
var(cumsum(x == 0)[x == 1])
})
a[is.na(tmp) | tmp == 0, ]
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature and
Forest
team Biometrie & Kwalit
Thanks Thierry and Petr for your solutions. I can continue now (until the next
problem arises ;).
From: r-help-boun...@r-project.org [r-help-boun...@r-project.org] on behalf of
ONKELINX, Thierry [thierry.onkel...@inbo.be]
Sent: Thursday, February 09, 2012
Hi,
I am trying to replicate a training of AttributeSelectedClassifier with
CFsSubsetEval, BestFirst and NaiveBayes that I have initially done with
Weka. Now, I am trying to use RWeka in R.
I have a problem of passing arguments to the CfsSubsetEval, BestFirst
and NaiveBayes. I have first created a
On Thu, 2012-02-09 at 14:52 +0100, Milan Bouchet-Valat wrote:
> Le jeudi 09 février 2012 à 15:31 +0200, Kari Ruohonen a écrit :
> >
> > And then I am trying to run the classifier with:
> >
> > nb.model<-AS(class~.,data=ex,
> > control=Weka_control(
> >E="weka.attributeSelect
Good afternoon everybody,
I'm using optimization routines like optimix or nlminb to optimize the
parameters of my dispersal curves which are "working" with different
kernels :
/anlb2002z1b <- nlminb(c(0.5,2), objective=LogLiketot,lower=c(0,0),
upper=c(1,200))/
where /LogLiketot/ contains my dis
Thank you very much for taking the time to answer. This pointed me in
the right direction.
For those interested, I found a useful explanation of the derivation
of the estimated variance of the random effect in Hosmer & Lemeshow's
Applied Survival Analysis (1999), pp.321-26 (I love your book, Dr.
T
On Feb 8, 2012, at 9:48 PM, kevin123 wrote:
Hi,
This is only a small portion of the Data i am working on
I want to make a subset of this data set( Data Set=Claims)
MemberID ProviderID Vendor PCPYear Specialty
1 422869788013252 172193 37796 Y1Surgery
2 979032483316066 7
Hey Peter,
I agree that Hotelling's T test, although technically possible for two groups
but rejecting the Ho in this case is not going to convey any meaning.
But I am sure there is a possibility. My assumption is based on using simulated
reference set for each comparison.
-- Vickie
Dear Vickie,
No one will be able to wave a magic wand over your data to allow you to
usefully estimate linear models with 0 df for error, and you certainly can't
perform statistical tests. As Peter Dalgaard pointed out, the same confusion
was reflected in your subsequent question about Hotellin
Anywez, I have figured out a solution. Whether it is a magic wand or something
else, that I don't know but I wish it would work.
Thx for the critical stand.
-- Vickie
> From: j...@mcmaster.ca
> Subject: Re: [R] dropterm in MANOVA for MLM objects
> T
Hello All,
I have a question about measurement invariance in a multigroup SEM. I am of the
impression that one cannot test the equality of structural paths across groups
without demonstrating measurement invariance of latent factors first. At a
minimum, this would involve demonstrating that cor
Happy New Year !
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course
date/city
(1) R-PLUS: A Point-and-Click Approach to R
(2) S-PLUS / R : Programming Essentials.
(3) R/S+ Fundamentals and Programm
Good day Eugene and R-useRs !
We have a few course coming up in New York City and Washington DC
during the week of March 11th, 2012.
http://www.xlsolutions-corp.com/rplus.asp
R Rocks !
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From: eugene dalt
To: "r-help@r-project.org"
Sent: Monday, February 6, 2012 11:57 AM
Subject: [R
Hi List,
I am reading table from postgres database into R session using RJDBC, table
contains 150 columns and 20 rows.
Sample code is as below, which works fine with smaller tables.
db_driver <- mydir$db_driver
db_jar_fi
Thanks it works
-
Thanks in Advance
Arun
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Sent from the R help mailing list archive at Nabble.com.
__
R-help
Hello,
I need to print a screen message after a test.
>list<-c("10","1","100","10")
>ifelse(all(list %in% c(1,10,100)==TRUE),cat("YES\n"),cat("NO\n"))
YES
Error in ifelse(all(l %in% c(1, 10, 100) == TRUE), cat("YES\n"), cat("NO\n")) :
replacement has length zero
I have the correct answer, YE
Dear all,
I would like to generate 500 matrices of 20 numbers from
standard normal distribution with names x1,x2,x3,â¦.x500. Â
I tried with loop for, but I donât know how to name matices :
for (i in 1:500)Â {
  x[[i]] <- matrix(rnorm(20), 4)    }
Any suggestion?
Thanks, Blaž
Dear Giovanni,
Many thanks for your interesting suggestions.
Your guess is indeed right, I only use the 'within' fixed effects specification.
I will soon send to this list all the additional information you
requested in order to understand what might cause this problem, but I
would say as a first
I'm trying to calculate the row-wise kronecker product A \Box B of two
sparse matrices A and B, and am struggling to find a quick way to do this
that takes advantage of sparseness. I thought a good idea would be to use
"rep" to construct 2 matrices of the same dimension of the end product, and
m
Greetings R users,
I have been working on running plsda and I would like to have the R2 and Q2
values. I know the function R2 from the 'pls' package will generate both
R2 and Q2 but they are for each separate class. Is there a way to get the
cumulative R2 and Q2 for the whole model?
R2(pls.new,
William,
I had a problem similar to Wolfgang and I solved it through your help.
Many thanks!
Just an observation which sounded strange to me ( I am not a statistician,
just a wildlife biologist)
I have noticed that running the pca using principal with raw data (and
therefore using scores=TRUE i
PREFERED WAY OF DOING IT
I have a data set of observations every second for a month long period, I
want to extract the observations according to the date & time of another
data frame ( the other data frame is in the same format). I want to do this
to match these observations to my test observa
What about this?
B <- 500
X <- matrix(rnorm(B*20), ncol = B)
colnames(X) <- paste('x', 1:B, sep = "")
head(X)
Thus, each column correspond to a sample of 20 numbers from a standard
normal distribution.
HTH,
Jorge.-
On Thu, Feb 9, 2012 at 8:38 AM, Blaz Simcic <> wrote:
> Dear all,
> I would li
Hello,
I need to analyse a data matrix with dimensions of 30x100.
Before analysing the data there is, however, a need to remove outliers from
the data.
I read quite a lot about outlier removal already and I think the most common
technique for that seems to be Principal Component Analysis (PCA). H
Dear all,
I'm an Sri Lankan undergraduate student. I'm also a total newbie to R.
My aim is to use the poLCA package to do a latent class analysis.
I found the documentation very helpful, but need to make a small
clarification that has stumped me awhile.
In my work, I need to make provision for c
Dear all,
I have question regarding GLMs:
I have a discrete response variable and a continuous explaining
variable. Like this:
http://www.myimg.de/?img=example1db0f.jpg
I want to use a GLM to investigate. I have to specify the "familiy of
the distribution of the response variable" - or, maybe
Hi,
I am trying to create a graph using Arial font (as required by PLoS One). I
have read probably all posts in R-help on this topic, as wells as R-news 2006.
The code I have been trying is following:
Arial <- Type1Font(family="Arial",
metrics=c("ArialMT.afm", "arial-BoldMT.afm"
A new version of the kopls package has been made available. This installs
without problems in R 2.14 (windows 32-bit). Download from here:
https://sourceforge.net/projects/kopls/files/K-OPLS%20for%20R/1.1.2/
[[alternative HTML version deleted]]
___
Hello,
I would like to make a function which extracts a subset, from a dataset,
with only the columns that I want (specifying their names).
For example, having this matrix:
> mydata<-matrix(c(22,1,3,2001,24,5,7,2002,26,7,8,2002,28,5,7,2003),
byrow=TRUE, ncol=4, dimnames=list(c(1,2,3,4),
c("ag
When I make a sample in sp, for example a random samping of 5 points in
dataset1:
sample.dataset1=spsample(dataset1, n = 5, "random")
I have a sp object for the selected sampling...
My question is : How can I extract from dataset2 the points & data for the
coordinates(sample.dataset1) ?
The da
i know RCurl pakage to retrieve web content,it has limited use, i want
interactive package like
(in perl--->Mechanize,
In java--->Watij,Prowser,HTMLunit,HTTPunit,
in Ruby>Watir ,etc)
this modules/packages opens appropriate browser,which can create
queries,retrieves output, clicks buttons, fil
Hello everyone!
I´ve started using R last week and I´m having really persistent problems
trying to make predictions using the HoltWinters function.
I´m sending my script and the errors I´m getting.
My data is:
Jan Feb Mar Apr May Jun Jul Ago Sep Oct Nov Dec
2004 118 143 169
Le jeudi 09 février 2012 à 15:31 +0200, Kari Ruohonen a écrit :
> Hi,
> I am trying to replicate a training of AttributeSelectedClassifier with
> CFsSubsetEval, BestFirst and NaiveBayes that I have initially done with
> Weka. Now, I am trying to use RWeka in R.
>
> I have a problem of passing argu
Hi,
I want to estimate parameter of weibull distribution using mle for below
density function,
The PDF is,
f(x) = b a^-b x^(b-1) exp -(x/a)^b
In R ,density of the weibull distribution is,
f(x) = (a/b) (x/b)^(a-1) exp(- (x/b)^a)
which is different from my density,
I trying to estimate mle par
Hi,
I'd like to plot a point: plot(1,2)
I use RStudio.
I'd like to know how to specify the length of Oy axis. I 'd like to put 20
as length of Oy but , by default, I 've got 2.5.
Thanks for your help
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Hello,
I have got an issue with this code:
plot(...)
xMontant = as.POSIXlt(ecs$startAt[i])
xDescendant = as.POSIXlt(ecs$endAt[i])
arrows(xMontant, 0, xMontant, ecsPOW, col="green")
Here is the error:
"Erreur dans arrows(xMontant, 0, xMontant, ecsPOW, col = "green") :
premier argument incorr
Dear all,
I am using the ROCR library to compute the AUC and also the Hmisc library
to compute the C-index of a predictor and a group variable. The results of
AUC and C-index are similar and give a value of about 0.57. The Wilcoxon
p-value is <0.001! Why the AUC is showing small value and the p-va
Hello,
>
> I want to estimate parameter of weibull distribution using mle for below
> density function,
> The PDF is,
> f(x) = b a^-b x^(b-1) exp -(x/a)^b
>
> In R ,density of the weibull distribution is,
> f(x) = (a/b) (x/b)^(a-1) exp(- (x/b)^a)
>
> which is different from my density,
>
Is
Dear All,
I have questions about the function "rpart" to construct a regression tree in
R code.
My problem is how to change the splitting criteria.
In the "rpart" we have : parms=list(split="..") , I ask you if in this
command is it possible to use an another splitting criterion to substitu
I found the issue:
arrows( ) , segments( ) do not accept argument of type POSIXlt. One must
convert the argument into POSIXct and it works well.
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Sent from the R help mailing list archive at
cat() returns a null value so it's problematic inside ifelse. Here you
probably need a regular if statement:
if(all(list %in% c(1, 10, 100))) cat("YES\n") else cat("NO\n") # The
== TRUE is redundant.
Michael
On Thu, Feb 9, 2012 at 11:37 AM, Arnaud Gaboury
wrote:
> Hello,
>
> I need to print a s
On Thu, Feb 9, 2012 at 2:54 AM, arunkumar wrote:
> Hi
>
> I'm storing two functions in a list
>
> # creating two function
> function1 <- function(n) {
> return(sum(n))
> }
>
> function2 <- function(n) {
> return(mean(n))
> }
>
> #storing the function
> function3 =c(function1,function2)
>
>
TY much.
Works for me.
Arnaud Gaboury
A2CT2 Ltd.
-Original Message-
From: R. Michael Weylandt [mailto:michael.weyla...@gmail.com]
Sent: jeudi 9 février 2012 17:47
To: Arnaud Gaboury
Cc: r-help@r-project.org
Subject: Re: [R] ifelse
cat() returns a null value so it's problematic insid
On Feb 9, 2012, at 11:37 AM, Arnaud Gaboury wrote:
Hello,
I need to print a screen message after a test.
list<-c("10","1","100","10")
ifelse(all(list %in% c(1,10,100)==TRUE),cat("YES\n"),cat("NO\n"))
YES
Error in ifelse(all(l %in% c(1, 10, 100) == TRUE), cat("YES\n"),
cat("NO\n")) :
rep
On Thu, 9 Feb 2012, mails wrote:
I need to analyse a data matrix with dimensions of 30x100. Before
analysing the data there is, however, a need to remove outliers from the
data. I read quite a lot about outlier removal already and I think the
most common technique for that seems to be Principal
On Feb 9, 2012, at 8:38 AM, Blaz Simcic wrote:
Dear all,
I would like to generate 500 matrices of 20 numbers from
standard normal distribution with names x1,x2,x3,….x500.
I tried with loop for, but I don’t know how to name matices :
for (i in 1:500) {
x[[i]] <- matrix(rnorm(20), 4) }
An
Perhaps the ylim argument to plot()
Michael
On Thu, Feb 9, 2012 at 9:04 AM, ikuzar wrote:
> Hi,
>
> I'd like to plot a point: plot(1,2)
> I use RStudio.
> I'd like to know how to specify the length of Oy axis. I 'd like to put 20
> as length of Oy but , by default, I 've got 2.5.
>
> Thanks for
On Feb 9, 2012, at 7:32 AM, wo...@posteo.de wrote:
Dear all,
I have question regarding GLMs:
I have a discrete response variable and a continuous explaining
variable. Like this:
http://www.myimg.de/?img=example1db0f.jpg
I want to use a GLM to investigate. I have to specify the "familiy
o
On Feb 8, 2012, at 21:56 , David Winsemius wrote:
>
> On Feb 8, 2012, at 2:29 PM, Ron Michael wrote:
>
>> Okay, so I understood that appending can only happen row-wise. Therefore I
>> tried with following code:
>>
>>> write.csv(matrix(1:5, 1), "dat.csv")
>>> write.csv(matrix(1:5, 1), "dat.csv
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of Francisco
> Sent: Thursday, February 09, 2012 4:52 AM
> To: r-help@r-project.org
> Subject: [R] subset select="variable with a list of names"
>
> Hello,
> I would like to make a
I wonder why it is still standard practice in some circles to search for
"outliers" as opposed to using robust/resistent methods.
Here is a great paper with a scientific approach to "outliers":
@Article{fin06cal,
author = {Finney, David J.},
title ={Calibration
On Thu, Feb 09, 2012 at 02:05:08PM +, linda Porz wrote:
> Dear all,
>
> I am using the ROCR library to compute the AUC and also the Hmisc library
> to compute the C-index of a predictor and a group variable. The results of
> AUC and C-index are similar and give a value of about 0.57. The Wilco
Posting under new subject.
I’ve a question on saving a earth object to disk.
Say m is the model then
print(object.size(m), units=”Mb”)
163.8 Mb
and save it off
save(m, “tmp.rda”)
and “tmp.rda” is roughly 171Mb file.
I would like this to be much smaller.
So I try
m$bx<-NULL
then
print(object.size(
I have the following variable, time, which is a character variable and it's
structured as follows.
> head(as.character(dat$time), 30) [1] "00:00:01" "00:00:16" "00:00:24"
> "00:00:25" "00:00:25" "00:00:40" "00:01:50" "00:01:54" "00:02:33" "00:02:43"
> "00:03:22"
[12] "00:03:31" "00:03:41" "00:03
Hi,
This worked great:
sub <- subset(Claims, Year=="Y1")
Thanks for your help
Kevin
On Thu, Feb 9, 2012 at 6:12 AM, David Winsemius wrote:
>
> On Feb 8, 2012, at 9:48 PM, kevin123 wrote:
>
> Hi,
>>
>> This is only a small portion of the Data i am working on
>> I want to make a subset of this
## To read .csv file(data) and performing "rpart" ##
# library(Hmisc)
library(rpart)
read.csv("D:/Training/RRE/Revolution(My Projects)/Project1/RProject(pmml
from SPSS)/telco_churn.csv", header = TRUE, sep = ",", quote="\"", dec=".")
# help(read.csv)
Telco<- read.table(file = "D:/Training/RRE/Revo
Maybe one of these will improve:
>help.search('kronecker')
...
spam::kronecker Kronecker Products on Sparse Matrices
spam::spam.classClass "spam"
base::kronecker Kronecker Products on Arrays
Matrix::kronecker-methods
Methods for Function 'kronecker()'
Below. -- Bert
On Thu, Feb 9, 2012 at 9:06 AM, David Winsemius wrote:
>
> On Feb 9, 2012, at 7:32 AM, wo...@posteo.de wrote:
>
>> Dear all,
>>
>> I have question regarding GLMs:
>> I have a discrete response variable and a continuous explaining variable.
>> Like this:
>> http://www.myimg.de/?img=
Hello,
I sourced successfully my function().
I need to load libraries, so I wrote this inside my function():
function()
{
#load needed library
library(plyr)
library(car)
/...
}
It is OK, but I have this on my invite command when running the function:
> function()
Loading required packa
Hi Elai, yes, the approach works out pretty well. Thanks a lot for
spending time on this and for the great help!
Gang
On Wed, Feb 8, 2012 at 5:43 PM, ilai wrote:
> I'm going to declare this SOLVED. Yes, if you don't want a separate
> script for batch, you will need to modify the original script
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of Frank Harrell
> Sent: Thursday, February 09, 2012 9:19 AM
> To: r-help@r-project.org
> Subject: Re: [R] Outlier removal techniques
>
> I wonder why it is still standard practice
I've dug around but not been able to find anything, am probably missing
something obvious.
How can I fill a three-dimensional (or higher dimension) array by rows
instead of columns.
eg
new1 <- array(c(1:125), c(5,5,5))
works fine for me but fills it by columns and
new2 <- array(c(1:125), c
Inline below.
-- Bert
On Thu, Feb 9, 2012 at 8:59 AM, David Winsemius wrote:
>
> On Feb 9, 2012, at 8:38 AM, Blaz Simcic wrote:
>
>> Dear all,
>> I would like to generate 500 matrices of 20 numbers from
>> standard normal distribution with names x1,x2,x3,….x500.
>> I tried with loop for, but I d
Use aperm on the output of array:
> aperm(array(1:8, dim=c(2,2,2)), perm=c(2,1,3))
, , 1
[,1] [,2]
[1,]12
[2,]34
, , 2
[,1] [,2]
[1,]56
[2,]78
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
> -Original Message-
> Fr
On Feb 9, 2012, at 12:47 PM, Jim Maas wrote:
I've dug around but not been able to find anything, am probably
missing something obvious.
How can I fill a three-dimensional (or higher dimension) array by
rows instead of columns.
eg
new1 <- array(c(1:125), c(5,5,5))
works fine for me but
Hi All,
I am having trouble getting a complex subscript to work. I'm sure it's
possible. Here is what I have:
ylab=expression(paste("log ",L[peak]," [erg ",s^{-1},"]")),
I would like to have the subscript read "peak,gamma" where the gamma
would be the greek symbol. I do want the comma
On Thu, Feb 9, 2012 at 1:46 AM, Gregory Jefferis wrote:
> Dear Peter,
>
> Trying to respond to your original question
Thanks for staying on thread :)
>
>
> I have a git repositiory in the root of my packages:
>
> ie
>
> package-foo/.git
> package-foo/R
> package-foo/inst
>
> Running make check
On Feb 9, 2012, at 12:53 PM, Eileen Meyer wrote:
Hi All,
I am having trouble getting a complex subscript to work. I'm sure
it's possible. Here is what I have:
ylab=expression(paste("log ",L[peak]," [erg ",s^{-1},"]")),
I would like to have the subscript read "peak,gamma" where the gam
> Same warning here. Which made me think that R CMD build will probably
> tar up the git repository along with the package, which is not
> something I would like to do, and which CRAN people most likely won't
> tolerate in a package on CRAN.
It doesn't. And you can always use .Rbuildignore to ign
Perhaps the longest function in base R I know of:
suppressPackageStartupMessages
e.g.,
suppressPackageStartupMessages(library(zoo))
Michael
On Thu, Feb 9, 2012 at 12:44 PM, Arnaud Gaboury
wrote:
> Hello,
>
> I sourced successfully my function().
>
> I need to load libraries, so I wrote this i
On Feb 9, 2012, at 1:20 PM, David Winsemius wrote:
On Feb 9, 2012, at 12:53 PM, Eileen Meyer wrote:
Hi All,
I am having trouble getting a complex subscript to work. I'm sure
it's possible. Here is what I have:
ylab=expression(paste("log ",L[peak]," [erg ",s^{-1},"]")),
I would like
>> I'm exploring using a version control system to keep better track
>> of changes to the packages I maintain. I'm leaning towards git
>> (although mercurial also looks good) but am not sure what is the
>> best way to set up the repository. It seems I can't set the
>> repository directly within the
Perhaps cut.POSIXt (which is a generic so you can just call cut)
depending on the unstated form of your time object.
Michael
On Thu, Feb 9, 2012 at 12:15 PM, Abraham Mathew wrote:
> I have the following variable, time, which is a character variable and it's
> structured as follows.
>
>> head(as.
Try
sub <- subset(Claims, Year==Y1)
In R, the equality test is performed by two
equal signs, not one.
- Phil Spector
Statistical Computing Facility
Department of Statistic
On Thu, Feb 09, 2012 at 06:33:09PM +0100, Petr Savicky wrote:
> On Thu, Feb 09, 2012 at 02:05:08PM +, linda Porz wrote:
> > Dear all,
> >
> > I am using the ROCR library to compute the AUC and also the Hmisc library
> > to compute the C-index of a predictor and a group variable. The results of
TY for your answer, but here what i did :
#load needed lybrary
suppressPackageStartupMessages(library(plyr))
suppressPackageStartupMessages(library(car))
library(plyr)
library(car)
But I still get :
Loading required package: MASS
Loading required package: nnet
Arnaud Gaboury
A2CT2 Ltd.
--
So close. The first version should work if you switch the order of the
postscript() and par() functions:
Arial <- Type1Font(family="Arial", metrics=c("ArialMT.afm",
"arial-BoldMT.afm",
"Arial-ItalicMT.afm", "Arial-BoldItalicMT.afm"))
postscriptFonts(Arial=Arial)
par(family="Arial")
postscrip
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