Hi Adam,
I don't think there is a faster alternative to plyr, without doing it in
nested for loops, with a lot of book-keeping of variables (but if someone
here were to correct me, I'd be happy to know).
Two things to consider:
1) See if you can optimizing your function. (there is a lot of mater
super! works like a charm,
best
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ht
Hi Adam,
A recent thread on R-help deals exactly with your problem. In one of the
responses I compare ddply to a number of alternative solutions (using
ave and data.table) [1]. The test in the e-mail shows that for large
amounts of unique categories, ddply is quite slow. Hadley (Wickham,
author o
I would take a look at the ddply function from the plyr package.
Without a reproducible example (most importantly an example dataset) I
cannot give you some example code.
cheers,
Paul
On 08/24/2011 05:51 PM, elh wrote:
> Apologies for the elementary nature of the question (yes, I'm another
> new
for example : I have files with the name
"ma01.dat","ma02.dat","ma03.dat","ma04.dat",I want to read the data in
these files into one data.frame
flnm<-paste("obs",101:114,"_err.dat",sep="")
newdata<-read.table(flnm,skip=2)
data<-(flnm,skip=2)
but the data only contains data from the flnm[1]
I als
Hello all, I used the following script to generate a plot, but when I
try to place axes, the axes start at the end of my plot and continue off
the plot; the attached image shows what happens when I try to generate
axes.
library(fields)
as.matrix(read.table("Matrix.txt", sep="\t"))->x
#the mat
Hi Jie,
you have to merge the sequential data.frames, and depending on the
structure of your inputs and the way you want your resulting data.frame
(which you both didn't specify) either ?merge or ?rbind should help.
cheers
Am 25.08.2011 10:17, schrieb Jie TANG:
> for example : I have files wit
Hello all, I've got a data set with two variables. I want to learn which copula
is suitable for my data set. I tried gofCopula function.I used this
code:gofCopula(gumbelCopula(1.5, d=2),x, method = "itau")x is my data set, and
"1.5" is my patameter which I found by converting Kendall tau to gu
Hi
>
> Hi there,
>
> I have length data of an organism over the year and I want to make a
> boxplot. I get the boxplot just fine but the months are all out of
order. In
> the data set they are in order from Jan-Dec...how can I fix this
problem?
Probably months are either character or factor v
>
> Dear all,
>
> How can I covert lm data to text in the form of "y=ax+b, r2" and how do
I
> calculate R-squared(r2)?
>
> Thanks.
>
> Code:
> x=18:29
> y=c(7.1,7,7.7,8.2,8.8,9.7,9.9,7.1,7.2,8.8,8.7,8.5)
> res=lm(y~x)
I am not sure what do you mean by text. There are some lm extraction
func
Dear R list
As suggested by Prof Brian Ripley, I have tried to read acf literature. The
main problem is I am not the statistician and hence have some problem in
understanding the concepts immediately. I came across one literature
(http://www.stat.nus.edu.sg/~staxyc/REG32.pdf) on auto-correlatio
Thank you for suggestions,
apparently data.table is much quicker than ddply and it's fantastic to use.
I forgot to mention in my topic I'm looking for alternative in R 2.10
version as on my platform our server runs older version of software which
only support R up to version of R-2.10 (upgrade is
Hi,
I want to use the result from smooth.spline outside R.
I take my data ,which is 180 point stored in x and y
s <- smooth(x,y)
I can know use to e.g. find the interpolated value at e.g. x=500
predict (s,500)
My problem is, that i don't know how to implement the predict function. I
have look
Hello,
I want to create two random variables (x1,x2) both with uniform distribution
bounded by (-1) and (1) that has a correlation of 0.6 between them.
Does somebody know how I can do it? For normal random variables I known how to
implement it with the rmvnorm command but I don't know how t
Hello,
for my project I wanted to create a side-by-side barplot. For each of 143
treatments there are always two measurement. This two measurements (a pair) are
represented by a red resp. a yellow bar. I was able to write the code for the
side-by-side barplot. Unfortunately however I am not able
Hi Paul,
I would use something like this:
> x <- c(2,2,3,3,4,6)
> table(x)
x
2 3 4 6
2 2 1 1
> x <- factor(x, levels=1:8)
> table(x)
x
1 2 3 4 5 6 7 8
0 2 2 1 0 1 0 0
Sarah
On Sun, Jul 31, 2011 at 5:41 PM, Paul Menzel
wrote:
> Dear R folks,
>
>
> I am sorry to ask this simple question, but my
Thank you for your attention and help!
In this way I get the diamond coloured, but actually I would have the
squares representing the values of the individual studies coloured. Is it
somehow possible?
*Paola*
2011/8/24 Viechtbauer Wolfgang (STAT) <
wolfgang.viechtba...@maastrichtuniversity.nl>
Thanks everyone, that's really helpful,
Cheers,
Sam
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R-help@r-project.o
While I'm very pleased with the results I get with rpart and
rpart.plot, I would like to change the scientific notation of the
dependent variable in the plots into integers. Right now all my 5 or
more digit numbers are displayed using scientific notation.
I managed to find this:
http://tolstoy.new
inputDataPath <- "/home/.../bla/"; #Directory containing data files
szPattern <- ".dat"; # File extension
# Get all files name in the specified directory
file2process <- list.files(inputDataPath, pattern=szPattern);
# Get number of files to be processed
iFileCnt <- len
On 08/25/2011 06:31 PM, Sumukh Sathnur wrote:
Hello all, I used the following script to generate a plot, but when I
try to place axes, the axes start at the end of my plot and continue off
the plot; the attached image shows what happens when I try to generate
axes.
library(fields)
as.matrix(read
Dear R helpers,
I'm new to R and struggling with applying functions to a spatial grid data
frame, called data for example.data has a variable named "slope" and "uparea"
Basically, I need to calculate the tan(data$slope)Next, I need to divide
data$uparea by data$slope and take the log() of that a
Hi!
On 08/24/2011 07:46 PM, David Winsemius wrote:
I was looking for an elegant solution ;) In the real case I have double
values and this would be quite inefficient then.
Still no r-code:
Then what about rank(order(...) , further-ties.method-argument) ?
I think that, as order() always give
> z <- ddply(past, c("GEO_CNTRY_NAME","PROD_SEG_NAME"),
> function(x) summary(lm(VAL~fy,x))$r.squared)
>
> But when ave is not exactly doing what I need. Above code runs under a
> minute for my data set where as ave runs over 8 mins.
It's hard to know without a reproducible example, but I doubt t
Hi Vincy,
Take a look on the material bellow, maybe they can help you:
http://www.statoek.wiso.uni-goettingen.de/veranstaltungen/zeitreihen/sommer03/ts_r_intro.pdf
http://www.maths.bris.ac.uk/~mazlc/TSA/r-ts.pdf
http://www.stat.pitt.edu/stoffer/tsa2/R_time_series_quick_fix.htm
On Thu, Aug 25,
Hello,
TO update R under Ubuntu on my macchine, I downloaded R-2.13.1. When running
./configure, I got the following error message:
checking for X... no
configure: error: --with-x=yes (default) and X11 headers/libs are not available
But I could use X11() function in R-2-10. So where does the p
On 08/25/2011 08:27 AM, carol white wrote:
Hello,
TO update R under Ubuntu on my macchine, I downloaded R-2.13.1. When running
./configure, I got the following error message:
checking for X... no
configure: error: --with-x=yes (default) and X11 headers/libs are not available
But I could use
I'm assuming that you meant to write
s <- smooth.spline(x, y)
You can look at the code for the predict method for smooth.spline by
typing
getAnywhere(predict.smooth.spline)
If a new value is provided (i.e., the 500 in your example) then the
predict method for smooth.spline.fit is applied to t
>From the help for barplot
?barplot
The argument "... space may be specified by two numbers, where the first
is the space between bars in the same group, and the second the space
between the groups. If not given explicitly, it defaults to c(0,1) if
height is a matrix and beside is TRUE ..."
S
Dear All,
I would like to report a possible mistake in the generic function rzigp in
ZIGP package, and seek for help.
Yesterday I tried the "rzigp" function, in this way:
1. generate poisson means from a pareto distribuion,
2. generate dispersion for each poisson from gamma distribution
3. gene
Have you tried searching the R-Help archives?
I found some answers to a similar question by Googling
r multivariate uniform distribution
Jean
Soberon Velez, Alexandra Pilar wrote on 08/25/2011 04:15:11 AM:
>
> Hello,
>
>
>
> I want to create two random variables (x1,x2) both with unifo
Thanks for your reply. I used the following commands:
sudo apt-get update
sudo apt-get install r-base
- Original Message -
From: Kevin E. Thorpe
To: carol white
Cc: "r-h...@stat.math.ethz.ch"
Sent: Thursday, August 25, 2011 2:34 PM
Subject: Re: [R] X11 problem
On 08/25/2011 08:27 AM, c
On 24.08.2011 21:59, Tyler Rinker wrote:
Apparently my request to view the help pages
Well, although the questions we see on R-help suggest that some useRs do
not look at those help pages, most of us do, but in text or html mode
rather than the pdf version.
Best,
Uwe Ligges
is not a
On 08/25/2011 08:49 AM, carol white wrote:
Thanks for your reply. I used the following commands:
sudo apt-get update
sudo apt-get install r-base
Is that how you installed R-2-10 or how you tried to install 2.13.1?
- Original Message -
From: Kevin E. Thorpe
To: carol white
Cc: "r-h...
Hi:
Similar in vein to the other respondents, you could try something like this:
On Thu, Aug 25, 2011 at 1:17 AM, Jie TANG wrote:
> for example : I have files with the name
> "ma01.dat","ma02.dat","ma03.dat","ma04.dat",I want to read the data in
> these files into one data.frame
>
# Your file n
both. But it worked for R-2-10.
I added
deb http://cran.ma.imperial.ac.uk/bin/linux/ubuntu lucid/
into /etc/apt/sources.list and ran
apt-get update
as root and got the following error message:
W: GPG error: http://cran.ma.imperial.ac.uk lucid/ Release: The following
signatures couldn't
Hello!
I am using R on two different machines (under Ubuntu and OS X, but this
is probably irrelevant) and I would like to keep the two installations
'synchronized', in particular in terms of installed packages. For
example, if I install package xxx on my Linux machine, I would like to
find it ins
Am 25.08.2011 15:05, schrieb carol white:
both. But it worked for R-2-10.
I added
deb http://cran.ma.imperial.ac.uk/bin/linux/ubuntu lucid/
into /etc/apt/sources.list and ran
apt-get update
as root and got the following error message:
W: GPG error: http://cran.ma.imperial.ac.uk lucid/ Re
Hello,
I am trying to write some code that dumps R objects to the harddisk in a binary
format so they can be quickly re-used later. Goal is to save time. The objects
may be quite large (e.g. classes for a GUI). I was thinking that save() and
load() would be suitable for this (until now I only
In order to build R-2.13.1 from source with X11, I guess you need to
install X11 develop library. Please try this:
sudo apt-get install libx11-dev
On Thu, 2011-08-25 at 05:49 -0700, carol white wrote:
> Thanks for your reply. I used the following commands:
> sudo apt-get update
> sudo apt-get inst
gpg --keyserver keyserver.ubuntu.com --recv-key E084DAB9
gpg: requesting key E084DAB9 from hkp server keyserver.ubuntu.com
gpgkeys: HTTP fetch error 7: couldn't connect to host
gpg: no valid OpenPGP data found.
gpg: Total number processed: 0
How to solve the problem?
Cheers,
Carol
- Origin
On Thu, Aug 25, 2011 at 3:25 PM, Giovanni Petris wrote:
> Hello!
>
> I am using R on two different machines (under Ubuntu and OS X, but this
> is probably irrelevant) and I would like to keep the two installations
> 'synchronized', in particular in terms of installed packages. For
> example, if I
It's not clear to me what problem you're having.
tan(data$slope)
should work. As should
log(data$uparea/data$slope)
I suggest that you provide a small subset of example data along with an
example of any code you've tried, and the output that you'd like.
Jean
Tom Vanwalleghem wrote on
Dear list,
I have problem that I cannot solve and would like to ask your opinion. I
tried to ask a few days ago already but got no answer and all my attempts to
solve it by myself since then failed. Sorry for repeated posting! Here the
problem broken down a bit.
My problem basically is, tha
I've been building a ranked dot plot for several days now and am sorting the
data using the reorder command. What I don't understand is how reorder
works when mutiple varibles are plotted by grouping. In the example below
I'm using re-order to sort by a variable name Resv_Prop, but I'm plotting u
Thanks I ran your command but still get the same error message when I run
./configure
configure: error: --with-x=yes (default) and X11 headers/libs are not available
- Original Message -
From: Linlin Yan (颜林林)
To: carol white
Cc: "r-h...@stat.math.ethz.ch"
Sent: Thursday, August 25
I suspect you need a get() in there somewhere, but this isn't a completely
reproducible example so I didn't try it.
get(filename) will return the R object whose name is given by the string
filename.
Sarah
On Thu, Aug 25, 2011 at 9:06 AM, J. Augusiak wrote:
> Dear list,
>
>
>
> I have problem th
Do you want to use 'get' in the last statement:
for (i in 1:10){assign(nam[i],as.ltraj(xy=get(char[i]),date=DATE,...)
I would also suggest the you use a 'list' instead of creating a lot of
variables in the workspace; e.g.,
result <- lapply(char, function(x) as.ltraj(xy = get(x), date = DATE, ...
It sounds like if you know you can pass the string "A1" where you need it to
go, the command get() *might* be what you are looking for.
Also, you can make your code much faster/prettier because R is smart about
recycling vectors of different lengths:
char <- paste("A",1:10, sep="")
x <- paste("X
On Thu, Aug 25, 2011 at 3:51 PM, carol white wrote:
> Thanks I ran your command but still get the same error message when I run
> ./configure
>
> configure: error: --with-x=yes (default) and X11 headers/libs are not
> available
>
If you are installing via apt-get, why do you have to run ./confi
Hi Carol,
When i ran into this problem, using the instructions as guide from here:
http://cran.r-project.org/bin/linux/ubuntu/
I did the following:
Went to this site: http://keyserver.ubuntu.com:11371/
searched for: 0xE084DAB9
Then clicked the hyperlinked "E084DAB9", copy, pasted and saved a
The problem I think is in your unmarshal. 'load' will load the object
into the local environment, not the global. You have to explicitly
return it, that means you have to know the name that its was 'save'd
by;
> unmarshal <- function(xdr) {
> object <- strsplit(strsplit(xdr, "\\.")[[1]][[1]]
Sorry for the wrong package name. It should be:
sudo apt-get install xorg-dev
On Thu, 2011-08-25 at 06:51 -0700, carol white wrote:
> Thanks I ran your command but still get the same error message when I run
> ./configure
>
> configure: error: --with-x=yes (default) and X11 headers/libs are not
>
> Dear list,
>
>
>
> I have problem that I cannot solve and would like to ask your opinion. I
> tried to ask a few days ago already but got no answer and all my
attempts to
> solve it by myself since then failed. Sorry for repeated posting! Here
the
> problem broken down a bit.
>
>
>
> M
Because the official source is not as new as the latest version yet.
On Thu, 2011-08-25 at 15:59 +0200, Rainer M Krug wrote:
>
>
> On Thu, Aug 25, 2011 at 3:51 PM, carol white
> wrote:
> Thanks I ran your command but still get the same error message
> when I run ./configure
>
Hi all,
I would like to use R in order to generate a Heatmap/Choropleth overlaid on
the UK map. Can someone please help with finding the right package/code? Any
help is much appreciated.
Best, Reza
[[alternative HTML version deleted]]
__
R-help@
Hi Dan,
You can save your .xls as .csv, set up your directory under the file where you
saved it, then
widge= read.csv("WidgeOne.csv", header=T)
It should work.
Kathleen.
> From: jorgeivanve...@gmail.com
> Date: Wed, 24 Aug 2011 18:31:21 -0400
> To: dan.abne...@gmail.com
> CC: r-help@r
This topic has been discussed (quite recently) on R-help.
http://r.789695.n4.nabble.com/Generating-uniformly-distributed-correlated-da
ta-td3314905.html
Enrico
> -Ursprüngliche Nachricht-
> Von: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] Im Auftrag von Soberon
> # Method 2: Use the plyr package
>
> library('plyr')
> bdf <- ldply(mlply(files, read.csv, header = TRUE), rbind)
Or just
bdf <- ldply(files, read.csv, header = TRUE)
Hadley
--
Assistant Professor / Dobelman Family Junior Chair
Department of Statistics / Rice University
http://had.co.nz/
_
Hi,
I have read your post about plotting multiple CI ellipses and I would like too,
but I don´t know how.
I would like to plot an ellipse for each group and I have slope and intercepts,
but I don´t know what to put in the arguments shape and radius.
CAn you help me please?
__
I don't see a quick solution to this.
You could contact the maintainer of the rpart.plot package, Stephen
Milborrow
maintainer("rpart.plot")
or you could try to modify the rpart.plot() function yourself to meet your
needs
rpart.plot
Jean
Jay wrote on 08/25/2011 05:30:25 AM:
>
>
Check out the maps package for a choropleth map. Specifically the map()
function (and its argument col=).
?map
Check out the image() function for a heat map which can be overlaid.
?image
Jean
Reza Salimi-Khorshidi wrote on 08/25/2011 09:00:04 AM:
>
> Hi all,
> I would like to use
On 08/25/2011 10:54 AM, Tom Vanwalleghem wrote:
> Dear R helpers,
> I'm new to R and struggling with applying functions to a spatial grid data
> frame, called data for example.data has a variable named "slope" and "uparea"
> Basically, I need to calculate the tan(data$slope)Next, I need to divide
On Aug 25, 2011, at 7:56 AM, Sebastian Bauer wrote:
Hi!
On 08/24/2011 07:46 PM, David Winsemius wrote:
I was looking for an elegant solution ;) In the real case I have
double
values and this would be quite inefficient then.
Still no r-code:
Then what about rank(order(...) , further-ties.
Hi,
I would like to add a two-lines label consisting of:
"Delta word1\n
word2"
(with Delta being the actual greek letter).
However, when I try "expression(paste(Delta,"word1\nword2"))", I obtain the
following display:
"word1\n
Delta word2".
Do you have any idea on how to obtain the desired displ
Thanks I could run configure and make but got warning after running configure:
configure: WARNING: you cannot build DVI versions of the R manuals
configure: WARNING: you cannot build DVI versions of all the help pages
configure: WARNING: you cannot build info or HTML versions of the R manuals
conf
Hi Jim,
Thanks for your reply. It seems that save and load can only be used for
datasets (as the title in ?load suggests).
I'd be very glad if I'm mistaken though!
Cheers!!
Albert-Jan
~~
All right, but apart from the sanitat
On Aug 25, 2011, at 10:38 AM, Jean V Adams wrote:
I don't see a quick solution to this.
You could contact the maintainer of the rpart.plot package, Stephen
Milborrow
maintainer("rpart.plot")
or you could try to modify the rpart.plot() function yourself to
meet your
needs
rpart.pl
Dear colleagues,
I'm trying to parse the html content from this webpage:
http://timesofindia.indiatimes.com/searchresult.cms?sortorder=score&searchtype=2&maxrow=10&startdate=2001-01-01&enddate=2011-08-25&article=2&pagenumber=1&isphrase=no&query=IIM&searchfield=§ion=&kdaterange=30&date1mm=01&date1dd
Thanks for your replies. I looked at those lines and didn't spot anything
unusual.
> tail(a)
test_id gene_id gene locus sample_1 sample_2 status
21418 tY(GUA)J1 - SUP7 chr10:354243-354332 air1rrp6 air2rrp6 OK
21419 tY(GUA)J2 - SUP4 chr10:542955-543044 air1rrp6
On 25 August 2011 at 22:24, Linlin Yan (颜林林) wrote:
| Because the official source is not as new as the latest version yet.
That is not true --- you get the most recent R version prebuilt for Ubuntu
(and other Linux distros) via the CRAN repositories.
See the R FAQ about where to get to current U
You probably need to change 'marshal' also. I see that you are
passing in the character string and this is what you are saving. what
you probably is something like this where you pass in the object and
then get its name:
>> marshal <- function(object.value) {
object <- deparse(substitut
But did you try the following:
x <- read.table(, comment.char = '', quote = '')
Most cases is that there is a missing quote somewhere in your data.
use a text editor and search for single and double quotes.
On Thu, Aug 25, 2011 at 11:49 AM, zhenjiang xu wrote:
> Thanks for your replies. I l
Oh thanks,
yes now I understand.
I did not realized that I did not save it.
:)
2011/8/24 Jean V Adams
>
> Claudio Zanettini wrote on 08/24/2011
> 04:33:50 PM:
>
> >
> > Thank you, this work fine,
> > and is not contorted like mine:)
> > In this case lastV=LastI but depending on the data that I
On Aug 25, 2011, at 11:23 AM, Sébastien Vigneau wrote:
Hi,
I would like to add a two-lines label consisting of:
"Delta word1\n
word2"
(with Delta being the actual greek letter).
But you are not saying how word1 and word2 are supposed to be
positioned relative to each other and to Delta.
The color of the squares is also currently hard coded.
The thing is, there are so many different elements to a forest plot (squares,
lines, polygons, text, axes, axis labels, etc.), if I would add arguments to
set the color of each element, things would really get out of hand (as far as I
am c
I suspect, but have not tested, that your src$date element has class
"POSIXlt", which is internally a list, in which case splitting by it might
not work properly, and might be the cause of your out of bounds error
message.
One of these might do the job:
src$date <- format(strptime(tickdata$da
Thanks, Jim. quote='' works. And then I found a single quote in each of
these lines:
3262
10403
17544
24685
31826
38967
None of them near the position the table got truncated. Why is it?
And read.table is a great function. Is it possible for it to give a warning
message when the data gets truncat
Thank you for the information!
On Thu, 2011-08-25 at 10:53 -0500, Dirk Eddelbuettel wrote:
> On 25 August 2011 at 22:24, Linlin Yan (颜林林) wrote:
> | Because the official source is not as new as the latest version yet.
>
> That is not true --- you get the most recent R version prebuilt for Ubuntu
I am not a programmer and am self-taught so I may lack the
language to ask this appropriately (perhaps why an rseek search was unfruitful).
Let's say I saved a file to my desktop called foo.pdf. Then I want R to return
the file path of
foo.pdf (pretend I don't know the location(path) of
Hi,
I have function that I want to optimize. Am playing with the optim() function
in R
Two issues:
1) I can't seem to get it to work with a function that takes multiple inputs.
Dummy Example:
myFunc <- function(A,B,D,D){
# Do stuff
return E
}
> myFunc(1,2,3,4)
[1] 12
# wor
Hello All,
I am trying to use FlexMix package for my two linear regression models:
http://finzi.psych.upenn.edu/R/library/flexmix/doc/regression-examples.pdf
y1 = w1 * x1 + w2 *x2 + w3 * x3 +beta1
y2 = w4 * x4 + w4 *x4 + w4 * x4 +beta2
and I would like to combine these two regression models wi
Hello everyone,
I have a graph and a segment parallel to the x axis at y=-10, x=0, and
bars on it.
Now the question is,
Is there a way to leave the segment there but let the graph axis start from
the origin?
In this way the segment will be out of the graph
Thanks
[[alternative HTML ver
Look at ylim, as an optional argument to plot.
Michael
On Thu, Aug 25, 2011 at 1:07 PM, Claudio Zanettini <
claudio.zanett...@gmail.com> wrote:
> Hello everyone,
> I have a graph and a segment parallel to the x axis at y=-10, x=0, and
> bars on it.
> Now the question is,
> Is there a way to le
Yes I tried but if I set the lim to 0 then it will not displayed the line
that is at -10, right?
2011/8/25 R. Michael Weylandt
> Look at ylim, as an optional argument to plot.
>
> Michael
>
> On Thu, Aug 25, 2011 at 1:07 PM, Claudio Zanettini <
> claudio.zanett...@gmail.com> wrote:
>
>> Hello ev
"lim" is not the argument: "ylim" is.
You put in a vector of length 2 comprising the min and max y you wish:
consider this:
x = -5:5; y = x^2; z = rep(-5,11);
layout(1:2)
plot(x,y,type="b"); lines(x,z,col=2)
plot(x,y,ylim = c(-8,max(y)+3),type="b"); lines(x,z,col=2)
For your work, you'd need yli
> I tried setting ylim=(0, 1000)
> but the segment that I have draw is at y=-10
> so if I set the y origin to 0 I don t have the segment,
> if a l leave it at -10 I have the segment but the axis start from -10.
>
> I would like to have both.
> So to have a graph with ylim=( 0, 1000)
> and under it
I'm not really sure what you are asking for, but I might venture to suggest
a few ideas:
1) Do you mean to say you want two plots: one with ylim around -10 and the
other running from 0 to 1000?
2) Are you looking for a "break" in the y-axis? If so, plotrix may be able
to help, but it's hardly wor
On Aug 25, 2011, at 1:30 PM, Claudio Zanettini wrote:
I tried setting ylim=(0, 1000)
but the segment that I have draw is at y=-10
so if I set the y origin to 0 I don t have the segment,
if a l leave it at -10 I have the segment but the axis start from
-10.
I would like to have both.
So to h
For the initial .Rd file look at the 'prompt' function, it will create a basic
.Rd file based on the current function definition with all the structure in
place, then you go in and edit it to have more meaningful information.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain
When you have an unbalanced quote, it may be hard to determine exactly
where it is. It is probably up to the user to determine with there is
truncation. In some cases you might have data that goes over several
lines that are within quotes and is legal. You might also read up on
the 'fill' and 'f
-- Forwarded message --
From: Claudio Zanettini
Date: 2011/8/25
Subject: Re: [R] Segment out of the Graph
To: David Winsemius
Thanks David and Michael,
In attachment there is one of the graph.
the line below the graph is not related to the y label.
I draw it at y= -10 just beco
Thanks Jean,
but this package appears to be perfect for the US + a couple of other
country that unfortunately UK is not one of them. What I want is a solution
that takes a list of coordinates/postcodes/cities and a list of values and
gives me a colourful UK map. Any thoughts?
Cheers
On Thu, Aug 25
Hi
I have created the following plot over the empirical returns.. What I now
want to do is to overlay a curve/line with the normal density as a
comparison of the two. Does anyone know how to do this?
(NB the last two lines are the problem, and are wrong, I know).
Thank you in advance!
Rikke
http
Using write.table i would like to save data as an excel file to a folder. I
am not too sure how to write the file path or what to name the file. I would
appreciate any feedback.
> write.table(x, file = "", append = FALSE, quote = TRUE, sep = " ",
+ eol = "\n", na = "NA", dec = ".",
Hello,
I have been looking for functions for calculating the within-groups
variance and between-groups variance, for the case where you have
several numerical variables describing samples from a number of groups.
I didn't find such functions in R, so wrote my own versions myself (see
below). I ca
Hi,
I have produced a list g and I would like to reduce the amount of
information contained in each object in g.
For each matrix I would like to keep the values where the column name equals
g[year][[1]][[x]] and the row names equals g[year][[1]][[-x]]. So in
g$`1999`$`8029`, year = 1999 and x = 8
Hi!
I am a beginner and I hope you will help me!
I have one data frame with numbers as columns names that correspond to codes.
In a list I have the codes and the corresponding state.
Now I need to match the columns (codes) of the data.frame with the codes in the
list, since not all the codes in
Try the dir() function.
?dir
# for example
dir("c:/", pattern="foo.pdf", full.names=T, ignore.case=T, recursive=T)
Jean
Tyler Rinker wrote on 08/25/2011 11:54:28 AM:
>
> I am not a programmer and am self-taught so I may lack the
> language to ask this appropriately (perhaps why an rseek searc
Hello everyone,
I need to fit a bivariate normal regression model to a dataset where the
same covariate (say, X) influences two separate but correlated responses
(say, Y1 and Y2). So, the bivariate
model would look like :
Y1 = a1 + b1*X + e1
Y2 = a2 + b2*X + e2
where e1 and e2 are error terms wh
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