On Fri, Oct 2, 2009 at 7:23 PM, Peter Ehlers wrote:
> Hello Rainer,
>
> I think that your problem is with trying to fit a logistic model to
> data that don't support that model. Removing the first two points
> from your data will work (but of course it may not represent reality).
> The logistic f
Mmm, just Friday ... :)
Thank you jim & gabor
> -Messaggio originale-
> Da: jim holtman
> [mailto:jholt...@gmail.com]
> Inviato: venerdì 2 ottobre 2009
> 14.12
> A: Luca Braglia
> Cc: r-help@r-project.org
> Oggetto: Re: [R] help with
> regexp mass substitution
>
> You need perl=TRUE:
__
Dear All,
We are happy to announce the release of the new version of DEoptim
(version 2.0-0) which is now available from CRAN.
The DEoptim package [3] performs Differential Evolution (DE) minimization,
a genetic algorithm-based optimization technique [2,3]. This allows robust
minimization ov
Hi all,
I'm using the try function for data import with read.csv function. I would
like to know if there is a double allocation of memory when using this code
test.t <- try(input1 <- read.csv("myfile.csv") )
compared to this one
test.t <- try( read.csv("myfile.csv") )
I think for the first code,
You are right, Patrick, there is no evidence that he is - as much as there
is no evidence that he is not. There is no evidence that he is in
Switzerland; there is no evidence that he is in Computer Science; and there
is no evidence that he is in fact "Mahesh." It seems to me we are now
redeclaring
Dear Bryan,
In the ggplot() function you can choose between aes() and aes_string().
In the first you need to hardwire the variable names, in the latter you
can use objects which contain the variable names. So in your case you
need aes_string().
Unfortunatly, facet_grid() works like aes() and not
Hi
I modify Rprofile.site file in etc directory in installed version of R
and I load all packages and data files I use through it. You shall also go
through file Rconsole in the same directory.
Regards
Petr
r-help-boun...@r-project.org napsal dne 02.10.2009 13:03:25:
> > I want to use the .R
Hi all,
I'm very confused! I've been using the same code for many weeks without any
bother for various covariates. I'm now looking at another covaraite and
whenever I run the code you can see below I get an error message: "Error in
rep(0, nrow(data)) : invalid 'times' argument"
This code works:
If you mean the values of the smooth function for different values of its
argument then take a look at setting `type="terms"' for `predict.gam'... the
returns predictions split up by individual smooth terms (and any parametric
terms)
On Thursday 01 October 2009 12:49, Daniel Rabczenko wrote:
>
hello all,
will you plz tell me how can i convert RData files to txt,,,
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented,
> "DW" == David Winsemius
> on Sat, 3 Oct 2009 12:56:51 -0400 writes:
DW> On Oct 3, 2009, at 11:54 AM, Chen Gu wrote:
>> Hello,
>>
>> I am doing a simple if else statement in R. But it always comes out
>> error
>> such as 'unexpected error'
>> There are
Repeat the DD calculation but with this pattern instead:
pat <- "^# +USGS +([0-9]+) +(.*)"
and then merge DD with DF:
DDdf <- data.frame(gauge = as.numeric(DD[,1]), gauage_name = DD[,2])
both <- merge(DF, DDdf, by = "gauge", all.x = TRUE)
On Sun, Oct 4, 2009 at 10:14 PM, Gabor Grothendieck
w
Introduction to Metabolomics and biomarker research.
The course will take place in Innsbruck, 16th to 17th November 2009, and
will be held in German.
For more details see:
http://www.gdch.de/vas/fortbildung/kurse/fortbildung2009.htm#1175
--
Dr. Matthias Kohl
www.stamats.de
Dear all,
Lets say I have the following data frame:
> df1 <- data.frame(Show=c('Star Trek', 'Babylon 5', 'Dr Who'), Size=c(0.7,
> 0.0, 0.701), Date=as.Date(c('2007-08-03', '2007-08-03', '2007-08-03'),
> format='%Y-%m-%d'))
> df2 <- data.frame(Show=c('Star Trek', 'Dr Who', 'Torchwood'), Size=c(
Try the reshape package:
> my.df
Show Size Date
1 Babylon 5 0.000 2007-08-03
2Dr Who 0.701 2007-08-03
3Dr Who 0.850 2007-08-04
4Dr Who 0.850 2007-08-05
5 Star Trek 0.700 2007-08-03
6 Star
mykh...@gmail.com wrote:
hello all,
will you plz tell me how can i convert RData files to txt,,,
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.
I updated to Ubuntu 9.10 Beta yesterday, and yes I do see the same message
and I am a bit irritated. I don't want to read these 'marketing' lines any
time I start up R.
I simply deleted the lines from "/etc/R/Rprofile.site" for now, but I am
still wondering who put that in. Is there any deeper r
You can try something about like this:
lapply(ls(), function(obj)cat("\n", obj, "<-",
paste(deparse(get(obj)), collapse = "\n"), file = 'RData.txt', append
= TRUE))
source('RData.txt')
On Mon, Oct 5, 2009 at 4:00 AM, wrote:
> hello all,
> will you plz tell me how can i convert RData files to t
Thanks Thierry for the work-around. I was out of ideas.
I had looked around for the facet_grid() analog of aes_string(), and
concluded there wasn't one. The only thing I found was the notion of
facet_grid("...") but apparently it is intended for some other use, as it
doesn't work as I thought i
Hi,
Whether or not what follows is to be recommended I don't know, but it
seems to work,
p <- ggplot(diamonds, aes(carat, ..density..)) +
geom_histogram(binwidth = 0.2)
x = quote(cut)
facets = facet_grid(as.formula(bquote(.~.(x
p + facets
HTH,
baptiste
2009/10/5 Bryan Hanson :
> Thanks
Hello everyone,
I'm running the following for loop to generate random variables in chunks of
60 at a time (l), here h is of order in millions (could be 5 to 6 millions),
note that generating all the variables at once could have an impact on the
final results
for(j in 1:h){
dat$t.o[seq(0,g1,l)[j]+
Andrew is correct: the upcoming release of Ubuntu (Karmic Koala) will
feature the REvolution R distribution. (I am a REvolution Computing
employee.) Our developers have been working with Canonical's
representatives over the past several months to upgrade R in Ubuntu to
2.9.2 and to include the REvo
In article <6f6f0fd60910050629p28c99209jcd7836353fd2d754
@mail.gmail.com>, antonioparede...@gmail.com says...
> I'm running the following for loop to generate random variables in chunks of
> 60 at a time (l), here h is of order in millions (could be 5 to 6 millions),
> note that generating all the
On Oct 5, 2009, at 3:00 AM, mykh...@gmail.com wrote:
hello all,
will you plz tell me how can i convert RData files to txt,,,
?load
?write.csv
?cat
--
David Winsemius, MD
Heritage Laboratories
West Hartford, CT
__
R-help@r-project.org mailing l
> Whether or not what follows is to be recommended I don't know, but it
> seems to work,
>
> p <- ggplot(diamonds, aes(carat, ..density..)) +
> geom_histogram(binwidth = 0.2)
>
> x = quote(cut)
> facets = facet_grid(as.formula(bquote(.~.(x
> p + facets
That's what I'd recommend. You can also
Dear R users,
The author of Tinn-R (Jose Claudio Faria) now is co-author of
Vim-R-plugin2, a plugin that makes it possible to send commands
from the Vim text editor to R. We added many new key bindings,
restructured the menu and created new Tool Bar buttons. The new
version is available at:
http
Now why do I always come up with a twisted bquote() where a simple
paste() would do!
Thanks,
baptiste
2009/10/5 hadley wickham :
>> Whether or not what follows is to be recommended I don't know, but it
>> seems to work,
>>
>> p <- ggplot(diamonds, aes(carat, ..density..)) +
>> geom_histogram(b
Hi,
I search a way to replace multiple occurrences of a string with
different strings
depending on the place where it occurs.
I tried the following;
x <- c("xx y e d xx e t f xx e f xx")
x <- gsub("xx", c("x1", "x2", "x3", "x4"), x)
what I want to get is;
x =
x1 y y e d x2 e t f x3 e f x4
Define a matrix to hold the data and insert it into the loop?
Something like
mymat <- matrix(rep(NA, 20), nrow=10)
for(i in 1:10){
a <- i
b <- i+1
mymat[i,] <- c(a,b)
}
matplot(mymat)
--- On Mon, 10/5/09, RR99 wrote:
> From: RR99
> Subject: [R] Saving each output of a loop into so
Hi all,
I am trying to run a glm with mixed effects. My response variable is
number of seedlings emerging; my fixed effects are the tree species
and distance from the tree (in two classes - near and far).; my random
effect is the individual tree itself (here called Plot). The command
I've used is:
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of Martin Batholdy
> Sent: Monday, October 05, 2009 7:34 AM
> To: r help
> Subject: [R] gsub - replace multiple occurences with different strings
>
> Hi,
>
> I search a way to repl
On Oct 5, 2009, at 5:38 AM, Martin Maechler wrote:
"DW" == David Winsemius
on Sat, 3 Oct 2009 12:56:51 -0400 writes:
DW> On Oct 3, 2009, at 11:54 AM, Chen Gu wrote:
Hello,
I am doing a simple if else statement in R. But it always comes out
error
such as 'unexpected error'
There are
Good day for all,
I'm a beginner aRgonaut, thus I'm having a problem to plot a quadratic model
of regression in a plot.
First I wrote:
>plot(Y~X)
and then I tried:
>abline(lm(Y~X+I(X^2))
but "abline" only uses the first two of three regression coefficients, thus
I tried:
>line(lm(Y~X+I(X^2))
Hi All,
I was wondering if if it is possible to change the font style and the font
size for x labels, y labels and the main title for a box plot?
Thanks
--
View this message in context:
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Sent from the R help mailing list archive at Nabble.
Hi
I want to integrate my R function with C++/C# application and want to pass
parameters from C++/C#. Can any body guide me in this regard?
Thanks
[[alternative HTML version deleted]]
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See family argument in ?par:
par(family = 'serif')
boxplot(rnorm(100), main = 'Title of Boxplot')
On Mon, Oct 5, 2009 at 11:48 AM, kayj wrote:
>
> Hi All,
>
> I was wondering if if it is possible to change the font style and the font
> size for x labels, y labels and the main title for a box plo
I hardly use base graphics so I'm no help there. You can do this
easily with ggplot2 though:
library(ggplot2)
X <- rnorm(100)
Y <- rnorm(100) - X^2
qplot(x=X, y=Y, geom=c("point", "smooth"), method="lm", formula = y ~
poly(x, 2))
Note that X is not x and Y is not y in the sense that "formula = Y
Hello,
I'm having an error when trying to fit the next GLM:
>>model<-glm(response ~ CLONE_M + CLONE_F + HATCHING
+(CLONE_M*CLONE_F) + (CLONE_M*HATCHING) + (CLONE_F*HATCHING) +
(CLONE_M*CLONE_F*HATCHING), family=quasipoisson)
>> anova(model, test="Chi")
>Error in if (dispersion == 1) Inf else obj
On Oct 5, 2009, at 12:47 PM, Henrique Dallazuanna wrote:
See family argument in ?par:
par(family = 'serif')
boxplot(rnorm(100), main = 'Title of Boxplot')
On Mon, Oct 5, 2009 at 11:48 AM, kayj wrote:
Hi All,
I was wondering if if it is possible to change the font style and
the font
siz
see ?curve
e.g.
qftn <- function(x) 1 + 2*x - .1*x^2
curve(qftn, 0, 10)
hth,
Kingsford
On Mon, Oct 5, 2009 at 9:42 AM, Juliano van Melis wrote:
> Good day for all,
>
> I'm a beginner aRgonaut, thus I'm having a problem to plot a quadratic model
> of regression in a plot.
> First I wrote:
>
>>
Hi Rainer,
Sorry, I hadn't read your post quite carefully enough.
The problem appears to be with SSlogis. It seems that
control parameters are not being passed through SSlogis.
If you specify a start vector, minFactor can be set.
nls( y ~ Asym/(1+exp((xmid-x)/scal)), data = dat,
start=list(A
ryusuke:
It sounds like you need to have (D)COM server to be able to work on the
background. As for the foreground, rcom is what you need and it appears to be
working OK. I am out of my office right now but I'll back to work next week and
I will be able to explain in more detail how the applicat
On Mon, Oct 5, 2009 at 8:52 AM, Umesh Srinivasan
wrote:
> Hi all,
[snip]
>
> Fixed effects:
> Estimate Std. Error z value Pr(>|z|)
> (Intercept) -138.8423 0.4704 -295.1 < 2e-16 ***
> SpeciesCr -0.9977 0.6259 -1.6 0.11091
> SpeciesDb -1.2140 0.6945 -1.7 0.0
I'm a fellow (K)Ubuntu user, although I'm waiting for KK to be
released before upgrading. I just wanted to point out that presumably
this advertisement can be avoided by installing R as instructed at
http://cran.r-project.org/bin/linux/ubuntu/ rather than using Ubuntu's
version. I usually do this a
Comment at end Below.
Bert Gunter
Genentech Nonclinical Biostatistics
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Kingsford Jones
Sent: Monday, October 05, 2009 10:30 AM
To: Umesh Srinivasan
Cc: r-help
Subject: Re: [R] interpr
On Monday 05 October 2009 09:38:21 am David M Smith wrote:
> Andrew is correct: the upcoming release of Ubuntu (Karmic Koala) will
> feature the REvolution R distribution. (I am a REvolution Computing
> employee.) Our developers have been working with Canonical's
> representatives over the past sev
> tmp2 <- matrix(1:8,4,2)
> dimnames(tmp2)
NULL
> tmp2
[,1] [,2]
[1,]15
[2,]26
[3,]37
[4,]48
> dimnames(tmp2)[[2]] <- c("a","b")
> tmp2
a b
[1,] 1 5
[2,] 2 6
[3,] 3 7
[4,] 4 8
> tmp1 <- matrix(1:4,4,1)
> dimnames(tmp1)
NULL
> tmp1
[,1]
[1,]1
[2,]
On Mon, Oct 5, 2009 at 11:57 AM, Bert Gunter wrote:
[snip]
> -- ... and if the correlations are "high" it tells you that your model may
> be near unidentifiable = the model parameters may not be effectively
> estimated from the data. To understand what "high", "near" and "effectively"
> may mean f
Hi all,
I think this is a very basic question, but I'm new to this so please bear
with me.
I'm using match to translate elements of a data frame using a lookup table.
If the content of a particular cell is not found in the lookup table, the
function returns NA. I'm wondering how I can just ignore
Hi all,
I have an easy data set. It has three columns: Subject, Condition, dprime. A
small excerpt follows, in order to illustrate:
Subject Condition dprime
HY s 3.725846
CM s 2.877658
EH s 5
HY st 2.783553
CM st 2.633955
EH st
On Oct 5, 2009, at 4:01 PM, Jill Hollenbach wrote:
Hi all,
I think this is a very basic question, but I'm new to this so please
bear
with me.
I'm using match to translate elements of a data frame using a lookup
table.
If the content of a particular cell is not found in the lookup
table
On 6/10/2009, at 9:01 AM, Jill Hollenbach wrote:
Hi all,
I think this is a very basic question, but I'm new to this so
please bear
with me.
I'm using match to translate elements of a data frame using a
lookup table.
If the content of a particular cell is not found in the lookup
table,
Let me clarify:
I'm using this--
dfnew<- sapply(df, function(df) lookuptable[match(df, lookuptable [ ,1]),
2])
>lookup
0101 01:01
0201 02:01
0301 03:01
0401 04:01
>df
0101 0301
0201 0401
0101 0502
>dfnew
01:01 03:01
02:01 04:01
01:01 NA
but what I want is:
>dfnew2
01:01
Hello,
I am very new to R. I would like to plot astronomy data by right
ascension, declination, and various "distance" values, such as
redshift and comoving distance, in 3D. Is there any 3D polar plotting
functions? I can't seam to locate any information on whether it exists
or not.
_
atorso wrote:
>
> Hello,
>
> I'm having an error when trying to fit the next GLM:
>
>>>model<-glm(response ~ CLONE_M + CLONE_F + HATCHING
> +(CLONE_M*CLONE_F) + (CLONE_M*HATCHING) + (CLONE_F*HATCHING) +
> (CLONE_M*CLONE_F*HATCHING), family=quasipoisson)
>>> anova(model, test="Chi")
>
>>Error
Searching on "spherical coordinates" brings up quite a few hits in r-
search:
Try:
http://search.r-project.org/cgi-bin/namazu.cgi?query=%22spherical+coordinates%22&max=100&result=normal&sort=score&idxname=functions&idxname=Rhelp08&idxname=views&idxname=Rhelp02
The most relevant appears to be:
See http://addictedtor.free.fr/graphiques/
for many examples with code.
Bert Gunter
Genentech Nonclinical Biostatistics
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of sverre
Sent: Monday, October 05, 2009 1:13 PM
To: r-help@r-
On Oct 5, 2009, at 4:47 PM, Jill Hollenbach wrote:
Let me clarify:
I'm using this--
dfnew<- sapply(df, function(df) lookuptable[match(df, lookuptable [ ,
1]),
2])
It seems a very bad idea to use the same name in your functions as
that of the dataframe argument you might be passing. You
Date-Time-Stamp input method to correctly interpret user-specific
formats:coding is 90% there - based on exmple at
http://tolstoy.newcastle.edu.au/R/help/05/02/12003.html
...anyone got the last 10% please?
CONTEXT:
Data is received where one of the columns is a datetimestamp. At midnight,
th
Off the top of my head, I think you're working to hard at this.
I would read in the timestamp column as a character string. Then,
find those where the string length is too short [using nchar()],
append "00:00:00" to those [using paste()], and then convert to
POSIXt [using as.POSIXct()].
No
On Oct 5, 2009, at 5:14 PM, esp wrote:
Date-Time-Stamp input method to correctly interpret user-specific
formats:coding is 90% there - based on exmple at
http://tolstoy.newcastle.edu.au/R/help/05/02/12003.html
...anyone got the last 10% please?
CONTEXT:
Data is received where one of the col
Try this. First we read a line at a time into L except for the
header. Then we use strapply to match on the given pattern. It
passes the backreferences (the portions within parentheses in the
pattern) to the function (defined via a formula) whose implicit
arguments are x, y and z. That function
Hi There,
I have created the following function
format<- function(){
repeat {
form<-readline(paste("\nIn what format do you want to save these
plots?\nChoose from: wmf, emf, png, jpg, jpeg, bmp, tif, tiff, ps, eps, or
pdf.\nNote: eps is the suggested format for publication quality plots.\nPlot
f
Here are two approaching using Bill's sample data:
1. gsubfn supports proto objects whose methods have access to a count
variable that is built into gsubfn and automatically reset to zero at
the start of each string so you can do this (gsubfn uses proto
internally so you don't have to explicitly l
use %in% instead of '=='
On Mon, Oct 5, 2009 at 7:47 PM, jimdare wrote:
>
> Hi There,
>
> I have created the following function
>
> format<- function(){
> repeat {
> form<-readline(paste("\nIn what format do you want to save these
> plots?\nChoose from: wmf, emf, png, jpg, jpeg, bmp, tif, tiff, p
On 05/10/2009 7:47 PM, jimdare wrote:
Hi There,
I have created the following function
format<- function(){
repeat {
form<-readline(paste("\nIn what format do you want to save these
plots?\nChoose from: wmf, emf, png, jpg, jpeg, bmp, tif, tiff, ps, eps, or
pdf.\nNote: eps is the suggested format
Looks interesting. Could you make a vimball out of it to facilitate
installation.
On Mon, Oct 5, 2009 at 10:12 AM, Jakson A. Aquino
wrote:
> Dear R users,
>
> The author of Tinn-R (Jose Claudio Faria) now is co-author of
> Vim-R-plugin2, a plugin that makes it possible to send commands
> from t
x <- data.frame(d=letters[1:3], e=letters[3:5])
lookuptable <- c(a="aa", c="cc", e="ee")
match.or.keep <- function(x, lookuptable) {if (is.factor(x)) x <- as.character(x);
m <- match(x, names(lookuptable)); ifelse(is.na(m), x, lookuptable[m])}
# to return a matrix
apply(x, 2, match.or.keep, looku
On Oct 5, 2009, at 7:56 PM, Duncan Murdoch wrote:
On 05/10/2009 7:47 PM, jimdare wrote:
Hi There,
I have created the following function
format<- function(){
repeat {
form<-readline(paste("\nIn what format do you want to save these
plots?\nChoose from: wmf, emf, png, jpg, jpeg, bmp, tif, tiff,
Look at the bottom of the message for my question
#here is a little function that I wrote
USGS <- function(input="discharge", days=7){
library(chron)
library(gsubfn)
#021973269 is the Waynesboro Gauge on the Savannah River Proper (SRS)
#02102908 is the Flat Creek Gauge (ftbrfcms)
#02133500 is the D
On Oct 5, 2009, at 9:39 PM, stephen sefick wrote:
Look at the bottom of the message for my question
#here is a little function that I wrote
USGS <- function(input="discharge", days=7){
library(chron)
library(gsubfn)
#021973269 is the Waynesboro Gauge on the Savannah River Proper (SRS)
#02102908
On Mon, Oct 05, 2009 at 08:03:23PM -0400, Gabor Grothendieck wrote:
> Looks interesting. Could you make a vimball out of it to facilitate
> installation.
It seems that VimBall is capable of creating vimballs of simple
plugins which have a file at ftplugin and a another at doc. The
Vim-R-plugin
Hi - I read through dse package manual a bit. I'm not quite certain
how I can use it to estimate a time varying coefficient regression
model? I might pick up an inappropriate package. Any suggestion would
be greatly appreciated. Thank you.
rh
__
R-help@
Sorry, I want the cumsum of precipitation by gauge name.
that can then be used with the appropriate datetime stamp to pot a
cumulative rainfall plot.
On Mon, Oct 5, 2009 at 9:03 PM, David Winsemius wrote:
>
> On Oct 5, 2009, at 9:39 PM, stephen sefick wrote:
>
>> Look at the bottom of the message
Will R have more glitches on one operating system as opposed to
another, or is it pretty much the same?
robert
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PLEASE do read the posting guide http://www.R-project.org/po
hey, i wonder how to perform limit in R.
In R help, i find the function "lim", but it seems i need to load package
first, can anyone tell me which one?
Or ANY method of taking limit, i searched it for 2 days but i failed,
thanx~~
--
View this message in context:
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On Oct 5, 2009, at 10:45 PM, stephen sefick wrote:
Sorry, I want the cumsum of precipitation by gauge name.
that can then be used with the appropriate datetime stamp to pot a
cumulative rainfall plot.
I dunno. Here is what I get when I extract the data-gathering part of
that extended funct
This is a rather vague question, ... I hope you will agree? Are you
asking for some approach that does symbolic calculus? Perhaps package
Ryacas?
On Oct 5, 2009, at 9:07 PM, dahuang wrote:
hey, i wonder how to perform limit in R.
In R help, i find the function "lim", but it seems i need
I'm seeing what looks to me like odd behaviour when I use na.omit on a
simple "length" function, as follows.
> sno
[1] 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22
23 24 25 26 27 28 29 30 31 32 33 34
> a
[1] 0 1 0 0 1 1 0 0 0 0 0 0 0 0 1 1 0 1 1 0 0 0 0 0 0 0 0 0 0 0 0 1
This looks buggish to me (though at least non-intuitive), but I am almost
sure there is an explanation for why the b==0 condition includes the NAs.
You find a way to circumvent it in the last two lines of the example below.
a=c(1,1,1,0,0,0)
b=c(1,NA,0,1,NA,0)
sno=rnorm(6)
na.omit(length(sno[a==1
just put na.omit() inside length() if you intend to omit the NA
elements of the vector (otherwise you are trying to omit the NA's of
the returned value of length() which is a scalar 2):
length(na.omit(sno[a==1 & b==0]))
Regards,
Yihui
--
Yihui Xie
Phone: 515-294-6609 Web: http://yihui.name
Depar
Thanks for that. It works as expected now. A case of GIGO (garbage in-
garbage out) on my part, with some head-banging. :-)
Regards
Viju Moses
Yihui Xie wrote:
just put na.omit() inside length() if you intend to omit the NA
elements of the vector (otherwise you are trying to omit the NA's of
t
thank you for your reply,,
i tried your commands but its not working,,i have attached the RData
file,,which i want to convert into txt..
Ilyas
On Mon, Oct 5, 2009 at 9:27 PM, Henrique Dallazuanna wrote:
> You can try something about like this:
>
> lapply(ls(), function(obj)cat("\n", obj, "<-",
>
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