wow, thanks for the informative inputs! I'm glad I post that silly
question..thanks!
On Wed, Oct 17, 2012 at 6:51 PM, Greg Snow <538...@gmail.com> wrote:
> Rui answered the main question by pointing out that you need z.test(m,
> stdev=s(m)), or you could use z.test(m,,sd(m)), but I think the stde
Rui answered the main question by pointing out that you need z.test(m,
stdev=s(m)), or you could use z.test(m,,sd(m)), but I think the stdev=
approach is clearer. But you are really abusing the concept of z
tests in general (and the z.test function in particular) by using the
sd of the sample. If
On Wed, Oct 17, 2012 at 7:45 AM, Balqis wrote:
> Sep=cbind(kIp,k02p,k04p,k07p)
> Sep=as.data.frame(Sep)
>
I see Rui has already taken a stab at your question, but I just want
to chime in to say the preceeding is really a terrible idiom. It would
be much _much_ better to write
Sep = data.frame(kl
Hello,
Without a data example I can't test this but, the call to ?z.test seems
to be wrong, you are passing a value for argument 'mu' equal to sd(m)
but _not_ passing a value for argument 'stdev'. Try
kzt <- sapply(Sep, function(m) z.test(m, stdev = sd(m)))
Hope this helps,
Rui Barradas
Em
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