Thank you all for helping me out.
As Michael points out, I abused the rounding and formatting of print()
while debugging.
The default number of digits to print is 7 according to ?print.default,
which makes floating point numbers to be somewhat plausible for index vector
subsetting at first glance:
On Sat, Oct 6, 2012 at 3:23 PM, Bert Gunter wrote:
> But the OP should not be doing this **at all.** He apparently has not
> bothered to read the Intro to R tutorial as he appears not to know
> about vectorized calculations.
>
> -- Bert
>
I don't really think that's relevant or constructive here.
But the OP should not be doing this **at all.** He apparently has not
bothered to read the Intro to R tutorial as he appears not to know
about vectorized calculations.
-- Bert
On Sat, Oct 6, 2012 at 3:29 AM, R. Michael Weylandt
wrote:
> Forgot to cc the list.
>
> RMW
>
> On Sat, Oct 6, 2012 at 1
Hello,
This seems to be a case for FAQ 7.31 Why doesn't R think these numbers
are equal?
See this example:
3/5 - 1/5 - 2/5 # not zero
3/5 - (1/5 + 2/5) # not zero, different from above
In your case, try
for(idx in breaks){
print(idx / interval, digits = 16) # see problem indices
Forgot to cc the list.
RMW
On Sat, Oct 6, 2012 at 11:29 AM, R. Michael Weylandt
wrote:
> A case study of a good question! Would that all posters did such a good job.
>
>
>
> On Sat, Oct 6, 2012 at 7:14 AM, 周果 wrote:
>> Hi there,
>> Here is a minimum working example:
>> -
On 06-10-2012, at 08:14, 周果 wrote:
> Hi there,
> Here is a minimum working example:
>
> lower = 0
> upper = 1
> n_bins = 50
> interval = (upper - lower) / n_bins
> bins = vector(mode="numeric", length=n_bins)
> breaks = seq(from=lo
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