and in addition to bill's suggestion, you may want to consider not
growing a list.
Instead of 'v <- list()', use:
v <- vector("list", nrow(A))
b
> Will your code work as you wish if you
> replace the "for(v[[1]] in x[[1]]) { ... }"
> with the following?
> for(i in x[[1]]) {
> v[[2]] <- i
Thanks Bill, that sorted it out! And thank you too Ben!
Bill and Ben. Are you familiar with the flowerpot men by any chance!?
Thanks again!
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> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of Pj253
> Sent: Tuesday, March 23, 2010 7:54 AM
> To: r-help@r-project.org
> Subject: [R] using a list to index elements of a list
>
>
> I have a list of vectors, x, with x[[1]]=1
can you also post an example of A and an example of the expected result?
On Tue, Mar 23, 2010 at 3:36 PM, Pj253 wrote:
>
> Thanks for your reply Ben!
>
> I don't think I want v to be identical to x... I guess I haven't put the
> question in the right context. What I'm actually trying to do is...
Thanks for your reply Ben!
I don't think I want v to be identical to x... I guess I haven't put the
question in the right context. What I'm actually trying to do is... (*
indicates extra information, not necessarily relevant for my question, but
to help put it in context)
A, some matrix (*a tra
if this was to work, wouldn't the object 'v' be identical to 'x'?...
so, why not use 'x' itself?
b
On Tue, Mar 23, 2010 at 2:53 PM, Pj253 wrote:
>
> I have a list of vectors, x, with x[[1]]=1:5, say.
>
> And I need to go through each element of each vector in a for loop.
> Something like:
>
> for
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