Re: [R] uniroot function question

kchkchkch wrote > > Heh. Yes, > Berend Hasselman wrote >> >> Shouldn't the line with uniroot be (why try as function?) >> >> sol = uniroot(fcn, lower = p1, upper = 1) >> >> Before the line with for(i in 1:n) insert the following >> >> fcn = function(p2) p1*f(p1) + (.20/5.66)*(exp(5.66*(p2

Re: [R] uniroot function question

Heh. Yes, Berend Hasselman wrote > > Shouldn't the line with uniroot be (why try as function?) > > sol = uniroot(fcn, lower = p1, upper = 1) > > Before the line with for(i in 1:n) insert the following > > fcn = function(p2) p1*f(p1) + (.20/5.66)*(exp(5.66*(p2 - p0)) - > exp(5.66*(p1 - p0)))

Re: [R] uniroot function question

kchkchkch wrote > > I have one equation, two unknowns, so I am trying to build the solution > set by running through possible values for one unknown, and then using > uniroot to solve for the accompanying second solution, then graphing the > two vectors. > > p0 = .36 > f = function(x) 0.29 * exp