Re: [R] transforming column of a dataframe by var- and median-functions

2008-03-09 Thread Henrique Dallazuanna
I think that your 'C' column is a factor(or character), because the character used(comma). One option: dat$C <- as.numeric(gsub(",", ".", as.character(dat$C))) library(doBy) summaryBy(C ~ B, data=dat, FUN=c(median, var), na.rm = T) On 09/03/2008, Agrarimmobilien <[EMAIL PROTECTED]> wrote: > H

Re: [R] transforming column of a dataframe by var- and median-functions

2008-03-09 Thread Daniel Malter
I think tapply does the job you want: tapply(C,B,mean,na.rm=TRUE) tapply(C,B,var,na.rm=TRUE) Cheers, Daniel - cuncta stricte discussurus - -Ursprüngliche Nachricht- Von: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] Im Auftrag von Agrarimm