Thanks David,
Neat use of merge there.
I think I can also do this with:
ddply(data,.(id),f)
On Thu, 2014-03-27 at 16:06 -0500, David Carlson wrote:
> It may be possible to do this in a single step, but
>
> > x1 <- aggregate(response~id+age, data, mean)
> > x2 <- data[data$eye=="l", c("id", "res
It may be possible to do this in a single step, but
> x1 <- aggregate(response~id+age, data, mean)
> x2 <- data[data$eye=="l", c("id", "response2")]
> merge(x1, x2)
id age response response2
1 1 2 4.60 High
2 2 9 2.65 High
3 3 5 3.65 High
4 4 2 7.55
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