Dear Eric
I think you are looking for sub or gsub
Without an example set of input and output I am not quite sure but you
would need to define an expression which matches your separator (;)
followed by any characters up to the end of line. If you have trouble
with that then someone here will n
Hi,
I'm not sure about the more generalized solution, but how about this for a
start.
x <- c("a;b;c", "d;e", "foo;g;h;i")
x
#[1] "a;b;c" "d;e" "foo;g;h;i"
sapply(strsplit(x, ";",fixed = TRUE), '[',1)
#[1] "a" "d" "foo"
If you want elegance then I suggest you take a look at the s
the following works - double backslash to remove the "or"
functionality of | in a regex. (Bill Dunlap showed that you don't
need sapply for it to work)
xs <- "this is | string"
xsv <- paste(xs, 1:10)
strsplit(xsv, "\\|")
On Oct 23, 3:50 pm, Jonathan Greenberg wrote:
> William et al:
>
> Th
William et al:
Thanks! I think I have a somewhat more complicated issue due to the
type of string I'm using -- the split is " | " (space pipe space) -- how
do I code that based on your sub code below? Using " | *" doesn't seem
to be working. Thanks!
--j
William Dunlap wrote:
-Ori
xs <- "this is string"
xsv <- paste(xs, 1:10)
sapply(xsv, function(x) strsplit(x, '\\sis\\s'))
This will split the vector of string "xsv" on the word 'is' that has a
space immediately before and after it.
On Oct 23, 1:34 pm, Jonathan Greenberg wrote:
> Quick question -- if I have a vector of s
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of Jonathan Greenberg
> Sent: Thursday, October 22, 2009 7:35 PM
> To: r-help
> Subject: [R] splitting a vector of strings...
>
> Quick question -- if I have a vector of strings tha
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