Great! Thanks, Aravind.
On Monday, February 16, 2015 10:50 PM, Aravind Jayaraman
wrote:
Hi,
I think you need not split the data.frame to get the desired result.
You can work with your list lst4 itself.
#Convert the vectors in the list to data.frames.
lst4 <- lapply(lst4, function(x
Great! many thanks, Chris and Bert.
On Tuesday, February 17, 2015 8:29 AM, Bert Gunter
wrote:
Inline.
-- Bert
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
"Data is not information. Information is not knowledge. And knowledge
is certainly not wisdom."
Clifford Sto
Inline.
-- Bert
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
"Data is not information. Information is not knowledge. And knowledge
is certainly not wisdom."
Clifford Stoll
On Tue, Feb 17, 2015 at 1:33 AM, Chris Campbell
wrote:
> # Assuming you want to create many data fram
# Assuming you want to create many data frames, you can use
# assign to create new objects.
newDFNames <- unique(means$source)
newDFNames
# [1] "iris1.csv" "iris2.csv"
for (nm in newDFNames) {
assi
Hi,
I think you need not split the data.frame to get the desired result.
You can work with your list lst4 itself.
#Convert the vectors in the list to data.frames.
lst4 <- lapply(lst4, function(x) {as.data.frame(t(iris1.csv))})
#Get the data.frames in the list to the global environment
list2env(ls
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