On Thu, Jun 05, 2008 at 09:05:25AM +0200, Philipp Pagel wrote:
> a bad idea. Alternatively, this should work:
>
> foo$id <- cumsum(as.logical(diff(foo$id))) + 1
I should have explicitly said that this only works after sorting, of
course.
cu
Philipp
--
Dr. Philipp Pagel
Lehrstuhl für Ge
On Wed, Jun 04, 2008 at 07:36:04PM -0600, Manli Yan wrote:
> no,the id is variable of a table,such as:
> treatment id age response
> low 1 50 20
> low 1 60 30
> high5 50 30
> high5 60 40
>
> ...
>
> I want to rearranage the
id<-c(1,1,1,1,3,3,3,7,7,7,7,11,11,11,2,2,2,4,4,4,4,8,8,8)
sort(id)
[1] 1 1 1 1 2 2 2 3 3 3 4 4 4 4 7 7 7 7 8 8 8 11 11 11
Quoting Manli Yan <[EMAIL PROTECTED]>:
no,the id is variable of a table,such as:
treatment id age response
low 1 50 20
low
no,the id is variable of a table,such as:
treatment id age response
low 1 50 20
low 1 60 30
high5 50 30
high5 60 40
...
I want to rearranage the table according the id (increasing),since id is not
strictly from 1~n,it is in
Are these the ranks of the data?
help.search("rank")
Manli Yan wrote:
id<-c(1,1,1,1,3,3,3,7,7,7,7,11,11,11)
how to sort this kind of data to
id:(1,1,1,1,2,2,2,3,3,3,3,4,4,4.)
thanks~
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