Hi:
An alternative is the following:
# This regenerates your dataset:
xx <- list(matrix(1:9, nrow = 3, byrow = TRUE),
matrix(10:18, nrow = 3, byrow = TRUE),
matrix(19:27, nrow = 3, byrow = TRUE))
# Flatten matrix elements of each component into vectors:
xxf <- lapply(xx,
If I understand, you can try this:
array(do.call(rbind, xx), c(3, 3, 3))
On Wed, Dec 30, 2009 at 11:45 AM, Muhammad Rahiz
wrote:
> Hi all,
>
> Given the following,
>
>> xx
> [[1]]
> V1 V2 V3
> [1,] 1 2 3
> [2,] 4 5 6
> [3,] 7 8 9
> [[2]]
> V1 V2 V3
> [1,]10 11 12
> [2,]13 14 15
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