; > twoTimes(p[1:2]) <- c(100,102)
> Calling twoTimes<-: x= 1:2
> > p
> [1] 50 51 3 4 5
>
>
> Bill Dunlap
> Spotfire, TIBCO Software
> wdunlap tibco.com
>
>
> > -Original Message-
> > From: r-help-boun...@r-project.org [mailto:r-help
ling twoTimes<-: x= 1:2
> p
[1] 50 51 3 4 5
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
> Behalf
> Of Harry Mamaysky
> Sent: Wednesday, July 10, 2
So how would I get the following to work?
> aa<-1
> aa
[1] 1
> 'foo<-' <- function(x,value) x<-value
> foo(aa)<-1:10
> aa
[1] 1 2 3 4 5 6 7 8 9 10
> # This doesn't work:
> foo(aa)[4:5] <- c(101,102)
Error in foo(aa)[4:5] <- c(101, 102) : could not find function "foo"
> # What I would like
I think the OP may perhaps want to define a method for "[<-" .
e.g. try:
methods("[<-")
If this is not it ... ??
Cheers,
Bert
On Wed, Jul 10, 2013 at 12:51 PM, David Winsemius
wrote:
>
> On Jul 10, 2013, at 12:17 PM, Harry Mamaysky wrote:
>
>> As I understand it rownames(aa) returns a copy of
On Jul 10, 2013, at 12:17 PM, Harry Mamaysky wrote:
> As I understand it rownames(aa) returns a copy of an attribute of aa. So
> changing the value of this vector should make the change to the copy of the
> row.names attribute. I would then have to set the original row.names equal to
> this co
As I understand it rownames(aa) returns a copy of an attribute of aa. So
changing the value of this vector should make the change to the copy of the
row.names attribute. I would then have to set the original row.names equal to
this copy to effect the change.
So my question is why "rownames(aa)[
On Jul 10, 2013, at 11:47 AM, Harry Mamaysky wrote:
> I know how to define replacement functions in R (i.e. ‘foo<-‘ <-
> function(x,value) x<-value, etc.), but how do you define replacement
> functions that operate on subsets of arrays (i.e. how do you pass an index
> into foo)?
> For example,
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