>I want to do very similar things with all the dataframes and their structure
>is also the same.
>Is there a way to write a loop? (so that I don't have to write the same 18
>times)
>I tried things like that:
>for (x in 1:length(plot))
>{
> plot(paste("auto.",plot[x],sep="")[,1],
> pas
get() is your friend.
Try:
for (x in 1:length(plot))
{
thisdf <- paste("auto.", plot[x], sep="")
plot(thisdf[, 1], thisdf[, 2], col=...)
}
HTH,
Ray Brownrigg
Sybille Wendel wrote:
Hello,
I need a command.
I have a lot of data in different dataframes(auto.0a, auto.0b, auto.0c,
Sybille Wendel wrote:
> Hello,
>
> I need a command.
> I have a lot of data in different dataframes(auto.0a, auto.0b, auto.0c,
> auto.5Na,...), that has similar names.
>
> I could print the names all at once wih a loop with the command paste(), see
> below:
>
> plot<-c("0a","0b","0c","5Na","5Nb",
On 18 Jun 2008, at 10:36, Sybille Wendel wrote:
I need a command.
I have a lot of data in different dataframes(auto.0a, auto.0b, auto.
0c, auto.5Na,...), that has similar names.
I could print the names all at once wih a loop with the command
paste(), see below:
plot<-
c("0a","0b","0c","5
You can put all dataframes into a list L, e.g.
L <- list(auto.0a, auto.0b,...)
and then do either a for-loop or use lapply. For example
for (ii in 1:length(L)){
plot(y~x, data=L[[ii]],...)
}
or
lapply(L, function(d) plot(y~x, data=d)
Med venlig hilsen
Søren Højsgaard
-Oprindel
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