Dear Boris,
Thanks very much, have a great week.
Best regards
Antônio Olinto
Fisheries Institute
São Paulo, Brasil
2015-03-21 21:09 GMT-03:00 Boris Steipe :
> ... just for completeness - the more concise way: (no need to go through
> names()).
>
> boxplot(mydata[,order(apply(mydata,2,median)
... just for completeness - the more concise way: (no need to go through
names()).
boxplot(mydata[,order(apply(mydata,2,median))])
... or descending
boxplot(mydata[,order(-apply(mydata,2,median))])
B.
On Mar 21, 2015, at 7:04 PM, Boris Steipe wrote:
> There may be more concise ways to d
There may be more concise ways to do this - but you are 99% there with your
approach:
try:
boxplot(mydata[,names(sort(apply(mydata,2,median)))])
B.
On Mar 21, 2015, at 6:49 PM, Antonio Silva wrote:
> Thanks Bill and David
>
> Here goes an example
>
> SP1<-c(9,6,7,8,5,8,7,5,9,7)
> SP2<-c(1,
Thanks Bill and David
Here goes an example
SP1<-c(9,6,7,8,5,8,7,5,9,7)
SP2<-c(1,3,4,2,4,2,5,3,2,1)
SP3<-c(4,6,7,5,7,8,7,6,5,4)
SP4<-c(5,4,3,5,2,3,4,3,4,2)
mydata<-data.frame(SP1,SP2,SP3,SP4)
rownames(mydata)<-c("ST1","ST2","ST3","ST4","ST5","ST6","ST7","ST8","ST9","ST10")
mydata
boxplot(mydata)
You can use the reorder() function to reorder the grouping vector's
factor levels according to a function of the data in each group. E.g.,
compare the following two plots:
d <- data.frame(Response=cos(1:15), Group=rep(c("A","B","C"),c(6,5,4)))
par(mfrow=c(1,2))
boxplot(Response ~ Group,
On Mar 20, 2015, at 2:20 PM, Antonio Silva wrote:
> Hello
>
> I'm using a dataframe (mydata) where row names are sampling points and
> column names are species in a multivariate analysis.
>
> If I write boxplot(mydata) I'll have boxplots for each species abundance in
> alphabetical order.
>
>
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