On 13/12/11 04:39, threshold wrote:
Indeed in txt it looks fine. Anyway, I must stay without 0 because csv is THE
format.
It may well be the case that csv is THE format, but csv is not the problem.
Excel is the problem.
The solution is: Don't use Excel!!! (This is excellent advice in any
c
right,
Table <- data.frame(matrix(0,8,3))
day = "Monday"
Table[1,1]=day
Table[1,2]=3
works, thanks a lot. robert
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Matrix (which is secretly a vector) can only have one mode
(numeric/factor/character/etc.) for all its elements. If you need
multiple types, go to a data frame
Michael
On Mon, Dec 12, 2011 at 10:39 AM, threshold wrote:
> Indeed in txt it looks fine. Anyway, I must stay without 0 because csv is
Indeed in txt it looks fine. Anyway, I must stay without 0 because csv is THE
format.
I got another question. why for
Table <- matrix(0,8,3)
day = "Monday"
Table[1,1]=day
all other elements become characters too?
Thanks, robert
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On Dec 12, 2011, at 7:23 AM, threshold wrote:
Dear R users, I got the following problem. Given that
data[3,2]
[1] "010252"
Code:
intro <- data.frame()
intro[1,1] <- as.character(data[3,2])
write.csv(intro, file='intro.csv')
In 'intro.csv' file I am loosing the 0 in frot of 10252, which I
threshold wrote on 12/12/2011 06:23:33 AM:
> Dear R users, I got the following problem. Given that
>
> > data[3,2]
> [1] "010252"
>
> Code:
> intro <- data.frame()
> intro[1,1] <- as.character(data[3,2])
> write.csv(intro, file='intro.csv')
>
> In 'intro.csv' file I am loosing the 0 in frot of
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