Firstly, the way you have constructed your data frame in the example will
convert everything to factors. What you need to do is actually a bit simpler:
###
dum <- data.frame(date, col1, col2)
###
One way to turn this into the kind of data frame you want is to convert the
main part of i
Try this:
reshape(dum, direction = 'long', idvar = 'date', varying =
list(c('col1', 'col2')))
On Wed, Mar 16, 2011 at 11:28 AM, pelt wrote:
> Dear all,
>
> I have a dataframe which looks like this (dummy):
>
> date<-c("jan", "feb", "mar", "apr", "may", "june", "july",
> "aug","sep","oct","nov","
require(reshape2)
melt(dum, id = 1)
On Wednesday, March 16, 2011 at 9:28 AM, pelt wrote:
Dear all,
>
> I have a dataframe which looks like this (dummy):
>
> date<-c("jan", "feb", "mar", "apr", "may", "june", "july",
> "aug","sep","oct","nov","dec")
> col1<-c(8.2,5.4,4.3,4.1,3.1,2.5,1.1,4.5,3.2,1
3 matches
Mail list logo