On Feb 28, 2012, at 12:10 PM, mrzung wrote:
I really appreciate to your attention.
I want to change the data form "A" into "B"
http://r.789695.n4.nabble.com/file/n4428807/1.png
http://r.789695.n4.nabble.com/file/n4428807/2.png
Please use text copied versions of dput(a) and dput(b) rathe
Hello,
Is it just a columns names issue?
Try (DF is your data, 'A' or other data.frame)
# colNames <- colnames(DF)
colNames <- c("name", "publish day", "2011-01-01", "2011-01-02",
"2011-01-03", "2011-01-04", "2011-01-05")
x <- as.Date(colNames[-(1:2)])
x
[1] "2011-01-01" "2011-01-02" "20
I really appreciate to your attention.
I want to change the data form "A" into "B"
http://r.789695.n4.nabble.com/file/n4428807/1.png
http://r.789695.n4.nabble.com/file/n4428807/2.png
In fact, there are 1095 column in data "A".
Specifically, variable "publish_day" is when some book in the
Hi
Your mail is quite messy. what is ***? How your data are structured?
str(your.data)
Please submit part of your data by
dput(your.data)
and show what the output shall be.
Regards
Petr
>
> Actually, what I really want to do is that,
>
>
> <<"annual productivity data(2011)">>
>
>
Actually, what I really want to do is that,
<<"annual productivity data(2011)">>
firts date 2011-01-01 2011-01-02
2011-01-03 2011-01-04
Hi,
There is not anything really like macro functions in R (and honestly,
that is probably a good thing). Most the times I have seen people
generating thousands of variables (vectors in your case) it is due to
a lack of understanding how lists can be utilized to simplify code.
If you give us some
On Mon, Feb 27, 2012 at 9:56 AM, mrzung wrote:
> hi,
>
> I know how to use the "for" loop function like:
>
> for(i in 1:ncol(mat)){
> mat[i]<-b[i,2]
> }
>
> but, in this case
>
> r1<-b[1,1]
> r2<-b[2,1]
> r3<-b[3,1]
> r4<-b[4,1]
>
> *
> *
> *
>
> r3002<-b[3002,1]
> r3003<-b[3003,1]
>
> - must make
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