y by:
dat1$t.tr<- as.character(dat1$t.tr)
A.K.
- Original Message -
From: "Fethe, Michael"
To: Dennis Murphy ; "R-help@r-project.org"
Cc:
Sent: Monday, August 26, 2013 8:45 AM
Subject: Re: [R] If else loop problem: the condition has length > 1 and only
689 -43.47 645.53
> #4 Pto 72 624 -68.17 555.83
> #5 Pto 72 666 -68.17 597.83
> #6 Pto 24 620 -29.39 590.61
>
>
> #or ?merge()
>
> A.K.
>
>
>
>
> - Original Message -
> From: Bert Gunter
> To: arun
> Cc: &q
a-j)? This code
produces :
In Ops.factor(signal2, 10.465507) : - not meaningful for factors
Thanks for the input.
________________
From: Dennis Murphy
Sent: Monday, August 26, 2013 4:59 AM
To: Fethe, Michael
Subject: Re: [R] If else loop problem: the condition has length > 1 and
nces@r-
> project.org] On Behalf Of arun
> Sent: Monday, August 26, 2013 8:32 AM
> To: Fethe, Michael
> Cc: R help
> Subject: Re: [R] If else loop problem: the condition has length > 1 and
> only the first element will be used
>
> HI,
>
> It may be better to provide
Cc: "Fethe, Michael" ; R help
Sent: Monday, August 26, 2013 10:09 AM
Subject: Re: [R] If else loop problem: the condition has length > 1 and only
the first element will be used
Suggestion:
Don't do the ifelse stuff below.
See ?switch instead.
-- Bert
On Sun, Aug 25, 2013 at 1
Suggestion:
Don't do the ifelse stuff below.
See ?switch instead.
-- Bert
On Sun, Aug 25, 2013 at 11:32 PM, arun wrote:
> HI,
>
> It may be better to provide an example dataset using ?dput().
> dput(head(dataset),20)
>
> Try:
> signal3<- ifelse(t.tr=="Pst 24", signal2-17.29, ifelse(t.tr=="Pst
HI,
It may be better to provide an example dataset using ?dput().
dput(head(dataset),20)
Try:
signal3<- ifelse(t.tr=="Pst 24", signal2-17.29, ifelse(t.tr=="Pst 48", signal2
- 43.93256, etc.))
A.K.
- Original Message -
From: "Fethe, Michael"
To: "r-help@r-project.org"
Cc:
Sent:
Hi Gary,
A solution in two pieces.
First, you need to be able to match the rows of your data frame. There
might be a more elegant way to do it, but I couldn't think of one that
gave the option of ordering or not, so I wrote a function:
isin <- function(dd, tomatch, ordered=TRUE) {
# find toma
8 matches
Mail list logo
