thank you both... assumption is in fact that a and b are always the same
length... these work for me well...
much appreciate it...
Andras
On Sunday, August 6, 2017 12:14 PM, Ulrik Stervbo
wrote:
Hi Andreas,
assuming that the increment is always indicated by the same value (in your
exam
Hi Andreas,
assuming that the increment is always indicated by the same value (in your
example 0), this could work:
df$a <- cumsum(seq_along(df$b) %in% which(df$b == 0))
df
HTH,
Ulrik
On Sun, 6 Aug 2017 at 18:06 Bert Gunter wrote:
> Your specification is a bit unclear to me, so I'm not sure t
Your specification is a bit unclear to me, so I'm not sure the below
is really what you want. For example, your example seems to imply that
a and b must be of the same length, but I do not see that your
description requires this. So the following may not be what you want
exactly, but one way to do
Hi Andras,
here is an other solution which also works if b contains missing values:
a <-seq(0,10,by=1)
b <-c(NA, 11:20)
f <-16
#
a[which.max(b[b If it's not homework, then I'm happy to provide more help:
>
>
> a <-seq(0,10,by=1)
> b <-c(10:20)
> d <-data.frame(a=a,b=b)
> f <-16
>
> subset(d, b <
If it's not homework, then I'm happy to provide more help:
a <-seq(0,10,by=1)
b <-c(10:20)
d <-data.frame(a=a,b=b)
f <-16
subset(d, b < f & b == max(b[b < f]))$a
# I'd turn it into a function
getVal <- function(d, f) {
subset(d, b < f & b == max(b[b < f]))$a
}
Sarah
On Mon, Dec 9, 2013
Thank you for providing a reproducible example. I tweaked it a little
bit to make it actually a data frame problem.
There are lots of ways to do this; here's one approach.
On second thought, this looks a lot like homework, so perhaps instead
I'll just suggest using subset() with more than one con
Hi,
Not sure if this is what you wanted:
activity<-
data.frame(Name=paste0("activity",LETTERS[1:5]),stringsAsFactors=FALSE)
dates1<-
data.frame(dat=as.Date(c("2013-02-01","2013-02-04","2013-02-05"),format="%Y-%m-%d"))
merge(dates1,activity)
# dat Name
#1 2013-02-01 activityA
#2 2
That sounds like a job for merge().
If you provide an actual reproducible example using dput(), then you
will likely get some actual runnable code.
Sarah
On Mon, Apr 1, 2013 at 11:54 AM, ramoss wrote:
> Hello,
>
> I have 2 data frames: activity and dates. Activity contains a l variable
> list
rate Research Laboratory
-
E-mail: apjawor...@mmm.com
Tel: (651) 733-6092
Fax: (651) 736-3122
From: Claudia Beleites
To: apjawor...@mmm.com
Cc: r-help@r-project.org
Date: 03/12/2010 02:13 PM
Subject: Re: [R] Data frame question
Andy,
Did you run into any kind of tro
Andy,
Did you run into any kind of trouble?
I'm asking because I'm maintaining a package for spectroscopic data that heavily
uses "I (spectra.matrix)" ...
However, once you have the matrix safe inside the data.frame, you can delete the
"AsIs":
> a <- matrix (1:9, 3)
> str (a)
int [1:3, 1:
... or in one step
df <- transform(df,
col1 = ifelse(col1 > 3, NA, col1))
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
On Behalf Of K. Elo
Sent: Friday, 15 February 2008 4:29 PM
To: r-help@r-project.org
Subject: Re: [R] data frame questi
Hi,
joseph wrote (15.2.2008):
> Thanks. I have another question:
> In the following data frame df, I want to replace all values in col1
> that are higher than 3 with NA. df= data.frame(col1=c(1:5, NA),col2=
> c(2,NA,4:7))
My suggestion:
x<-df$col1; x[ x>3 ]<-NA; df$col1<-x; rm(x)
-Kimmo
__
t;; r-help@r-project.org
Cc: r-help@r-project.org
Sent: Thursday, February 14, 2008 3:09:40 PM
Subject: Re: [R] data frame question
Create
the
new
data.frame
and
do
the
muliplying
on
it?
df2
<-
df1
df2[,1]
<-
df2[,1]*2
---
joseph
<[EMAIL PROTECTED]>
wrote:
>
>
>
Create the new data.frame and do the muliplying on it?
df2 <- df1
df2[,1] <- df2[,1]*2
--- joseph <[EMAIL PROTECTED]> wrote:
>
>
> Hi
>
> I have a data frame df1 in which I would like to
> multiply col1
> by 2.
>
>
> The way I did it does not allow me to keep the old
> data
> frame.
>
>
>
On Thursday 14 February 2008 06:27:07 pm Stefan Grosse wrote:
SG> df$col3<-df1$col1*2
ups it should be
df1$col3<-df1$col1*2
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PLEASE do read the posting guide http://www.R-
On Thursday 14 February 2008 06:12:23 pm joseph wrote:
jo> I have a data frame df1 in which I would like to multiply col1
jo> by 2.
jo> The way I did it does not allow me to keep the old data
jo> frame.
jo>
jo>
jo> How can I do this and be able to create a new data frame
jo> df2?
jo>
jo>
jo> > df1$
If I understand:
df2 <- transform(df1, col3=col1*2)
On 14/02/2008, joseph <[EMAIL PROTECTED]> wrote:
>
>
> Hi
>
> I have a data frame df1 in which I would like to multiply col1
> by 2.
>
>
> The way I did it does not allow me to keep the old data
> frame.
>
>
> How can I do this and be able
df2 = df
?
G.
On Thu, Feb 14, 2008 at 09:12:23AM -0800, joseph wrote:
>
>
> Hi
>
> I have a data frame df1 in which I would like to multiply col1
> by 2.
>
>
> The way I did it does not allow me to keep the old data
> frame.
>
>
> How can I do this and be able to create a new data frame
joseph <[EMAIL PROTECTED]> wrote in
news:[EMAIL PROTECTED]:
> I have 2 data frames df1 and df2. I would like to create a
> new data frame new_df which will contain only the common rows based
> on the first 2 columns (chrN and start). The column score in the new
> data frame should
> be replaced w
On 10/02/2008, joseph <[EMAIL PROTECTED]> wrote:
> Hello
> I have 2 data frames df1 and df2. I would like to create a
> new data frame new_df which will contain only the common rows based on the
> first 2
> columns (chrN and start). The column score in the new data frame
> should
> be replaced wit
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