Great! I got it. You're right, I misinterpreted Duncan's suggestion.
Thanks a lot to both of you...
Matteo
On 24 November 2011 02:47, Rolf Turner-3 [via R]
wrote:
> On 24/11/11 09:23, matric wrote:
>> Thanks Duncan,
>> I knew it. But if I use the complete variable name, I'll have far too
>> many
On 24/11/11 09:23, matric wrote:
Thanks Duncan,
I knew it. But if I use the complete variable name, I'll have far too
many arguments for my function
Did you understand Duncan's post? He told you that
df[,var]
would work, whereas df$var doesn't. So he gave you a solution
to the probl
On 11-11-23 3:23 PM, matric wrote:
Thanks Duncan,
I knew it. But if I use the complete variable name, I'll have far too
many arguments for my function
Maybe a new design is in order.
Duncan Murdoch
On 23 November 2011 20:59, Duncan Murdoch-2 [via R]
wrote:
On 23/11/2011 2:29 PM, matr
Thanks Duncan,
I knew it. But if I use the complete variable name, I'll have far too
many arguments for my function
On 23 November 2011 20:59, Duncan Murdoch-2 [via R]
wrote:
> On 23/11/2011 2:29 PM, matric wrote:
>> Hi,
>> I'd like to create a function that accepts as arguments a string that
On 23/11/2011 2:29 PM, matric wrote:
Hi,
I'd like to create a function that accepts as arguments a string that is to
be substituted within a variable name. For instance, suppose I have a data
frame df:
df<-data.frame(x_narrow=c(rnorm(100,0,1)),x_wide=c(rnorm(100,0,10)))
What I have in mind is s
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