What exactly are you looking to do? If it's just to get the name, drop the
get() call and just put:
q1 <- kinderrechte[,q0]
l1 <- paste(q0,"_l",sep="")
Michael Weylandt
On Mon, Sep 19, 2011 at 6:55 AM, Marion Wenty wrote:
> hi jim,
>
> with the function "get" I could solve the problem using the
hi jim,
with the function "get" I could solve the problem using the following
commands:
q1 <- kinderrechte[,q0]
l1 <- get(paste(q0, "_l", sep = ""))
in this way i am getting the content of the object instead of the name of
the object.
thank you very much for your help!
marion
2011/9/16 jim h
hello jim,
thank you for your reply.
Do you know a solution without having to use a loop?
Marion
2011/9/16 jim holtman
> for (i in names(kinderrechte)){
>q1 <- kinderrechte[, i]
>i 1 <- get(i)
> }
>
> On Fri, Sep 16, 2011 at 4:47 AM, Marion Wenty
> wrote:
> > Hello,
> >
> > does anyo
You have to give more specifications as to what you want to do with
the data that is being processed. You have values being put into 'q1'
and 'i1' that don't seem to be used in the loop. Do you just want
these values returned? You can easily do it "without a loop" using
lapply:
result <- lapply
did not see the "_l" so changes below:
On Fri, Sep 16, 2011 at 8:33 AM, jim holtman wrote:
> for (i in names(kinderrechte)){
> q1 <- kinderrechte[, i]
> i 1 <- get(paste(i, "_l", sep = ""))
> }
>
> On Fri, Sep 16, 2011 at 4:47 AM, Marion Wenty wrote:
>> Hello,
>>
>> does anyone know the so
for (i in names(kinderrechte)){
q1 <- kinderrechte[, i]
i 1 <- get(i)
}
On Fri, Sep 16, 2011 at 4:47 AM, Marion Wenty wrote:
> Hello,
>
> does anyone know the solution to this problem:
>
> I imported a dataframe from Spss into R and saved it as an object called
> "kinderrechte".
>
> I hav
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