Yes thank you Jorge :working:
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Anna Lippel
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Hi Anna,
Here is a suggestion:
# creating L1
L1 <- lapply(1:5, function(x) matrix(rnorm(10), ncol = 2))
L1
# creating L2
L2 <- lapply(1:5, function(x) sample(5, 2))
L2
# defining a function
foo <- function(x, y) list(x[-y,])
# result
mapply(foo, L1, L2)
HTH,
Jorge
On Fri, Mar 26, 2010 at 5:3
Anna,
See ?mapply
I think you should be able to use that.
Steve Riley, Pharm.D., Ph.D.
Clinical Pharmacology, Specialty Neuroscience
Pfizer Specialty Care Business Unit
Mail Stop MS 6025-B2110
50 Pequot Ave
New London, CT 06320
steve.ri...@pfizer.com
Tel: (860) 732-1796
Fax: (860) 686-567
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