Fantastic. Solved.
Thanks!
On Sat, Apr 3, 2010 at 9:59 AM, Gabor Grothendieck
wrote:
> # 1
> grep returns an index, not the value unless you use grep(..., value =
> TRUE).
>
> Easier might be:
>
> # 2
> Sample2 <- substr(Sample, 1, 2)
> ifelse(Sample2 == "BU", "up", ifelse(Sample2 == "BM", "mid
# 1
grep returns an index, not the value unless you use grep(..., value = TRUE).
Easier might be:
# 2
Sample2 <- substr(Sample, 1, 2)
ifelse(Sample2 == "BU", "up", ifelse(Sample2 == "BM", "mid", "down"))
or
#3 the following which matches the first 2 characters against the
given list names and
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of Sam Albers
> Sent: Saturday, April 03, 2010 9:18 AM
> To: r-help@r-project.org
> Subject: [R] Using ifelse and grep
>
> Good Morning,
>
> I am trying to create a new column of c
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