> today <- as.Date("2015-03-04") # default format
Better is:
today <- Sys.Date()
S
-Original Message-
From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of William Dunlap
Sent: Thursday, 5 March 2015 7:47a
To: Brian Hamel
Cc: r-help@r-project.org
Subject:
Our R-user's group (UC Davis) has a good post on working with dates/times
in R:
http://www.noamross.net/blog/2014/2/10/using-times-and-dates-in-r---presentation-code.html
On Wed, Mar 4, 2015 at 11:08 AM, David L Carlson wrote:
> Wow! A bold prediction from someone who has done exactly zero
> i
Wow! A bold prediction from someone who has done exactly zero investigation of
the basic, built-in date/time features in R. Since your example did not include
the first two digits of the year, I've used %y instead of %Y. That will assume
"19" precedes values from 69-99 and "20" precedes values f
Tena koe Brian
See ?as.Date and ?strptime (and, maybe, ?locales). For example:
as.Date('2/15/15', '%m/%d/%y')
[1] "2015-02-15"
as.Date('12/15/14', '%m/%d/%y') < as.Date('2/15/15', '%m/%d/%y')
[1] TRUE
> as.Date('12/15/16', '%m/%d/%y') < as.Date('2/15/15', '%m/%d/%y')
[1] FALSE
You might have p
You will need to convert strings like "2/15/15" into one of the time/date
classes available in R and then it is easy to do comparisons. E.g., if you
have no interest in the time of day you can use the Date class:
> d <- as.Date(c("12/2/79", "4/15/15"), format="%m/%d/%y")
> today <- as.Date("2015-
Your hunch is wrong.
Start by typing
?Date
at the R prompt. Continue with
?as.Date
Then to find out if the date is earlier than today
delta <- thedate - Sys.Date()
(of course, that will change if you use it tomorrow)
Getting your indicator variable can be done very easily with base R; no
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