Taking it back - no need for all.x = T, all.y = F
On Tue, Dec 22, 2015 at 3:56 PM, Dimitri Liakhovitski
wrote:
> Actually, the correct merge line should be:
> my.merge <- merge(myinfo, mydata, by="version", all.x = T, all.y = F)
>
> On Tue, Dec 22, 2015 at 3:50 PM, Dimitri Liakhovitski
> wrote:
Actually, the correct merge line should be:
my.merge <- merge(myinfo, mydata, by="version", all.x = T, all.y = F)
On Tue, Dec 22, 2015 at 3:50 PM, Dimitri Liakhovitski
wrote:
> You are right, guys, merge is working. Somehow I was under the
> erroneous impression that because the second data frame
You are right, guys, merge is working. Somehow I was under the
erroneous impression that because the second data frame (myinfo)
contains no column 'myid' merge will not work.
Below is the cleaner code and comparison:
#
### Example with smaller data frames
##
I know I am overwriting.
merge doesn't solve it because each version in mydata is given to more
than one id. Hence, I thought I can't merge by version.
I am not sure how to answer the question about "the problem".
I described the current state and the desired state. If possible, I'd
like to get fro
Library dplyr to use arrange() for ordering, in the case.
library(dplyr)
result.order <- arrange(result, d, version, a, b, c)
dim(result.order)
[1] 30005
head(result.order)
d versiona b c
1 -2.986456069 1 0.2236414154 0.004258038663 1.089
You seem to be saving 'myid' and then overwriting it with the last
statement:
result[[i]] <- result[[i]][c(5, 1:4)]
Why doesn't 'merge' work for you? I tried it on your data, and seem to get
back the same number of rows; may not be in the same order, but the content
looks the same, and it does
6 matches
Mail list logo
