Re: [R] strsplit with a vector split argument

Hi, You could try: strsplit(c("a,b;c","d;e,f"),",|;") #[[1]] #[1] "a" "b" "c" # #[[2]] #[1] "d" "e" "f" A.K. - Original Message - From: Sam Steingold To: r-help@r-project.org Cc: Sent: Wednesday, September 18, 2013 11:42 AM Subject: [R] strsplit with a vector split argument Hi, I fin

Re: [R] strsplit with a vector split argument

On 09/18/2013 09:04 AM, arun wrote: Hi, You could try: strsplit(c("a,b;c","d;e,f"),",|;") He did it with "[,;]" which is equivalent but slightly faster. The more characters you have inside the square brackets, the more beneficial it is to use [abcde] over a|b|c|d|e. It's also more compact and

Re: [R] strsplit with a vector split argument

On Sep 18, 2013, at 10:42 AM, Sam Steingold wrote: > Hi, > I find this behavior unexpected: > --8<---cut here---start->8--- >> strsplit(c("a,b;c","d;e,f"),c(",",";")) > [[1]] > [1] "a" "b;c" > > [[2]] > [1] "d" "e,f" > --8<---cut here--

Re: [R] strsplit with invalid regular expression

In R, the source code representation of a special character uses the \ as an escape character to begin a special character sequence. For example, "\n" is a single newline character. Because backslash has this special meaning, to represent a single backslash character one must escape it: "\\" lo

Re: [R] strsplit with invalid regular expression

HI, cond<-"andsin(log_angle_1_4)"  diff_operator<-"sin\\("  strsplit(cond,diff_operator) #[[1]] #[1] "and"    "log_angle_1_4)" A.K. - Original Message - From: Bharat Warule To: r-help@r-project.org Cc: Sent: Thursday, November 8, 2012 6:39 AM Subject: [R] strsplit with inv

Re: [R] strsplit with invalid regular expression

> strsplit(")asdasdsin(abcd)", "sin\\(") [[1]] [1] ")asdasd" "abcd)" > On Thu, Nov 8, 2012 at 12:39 PM, Bharat Warule wrote: > Hi all, > > > diff_operator <- "\\(" > > strsplit(cond, diff_operator) > [[1]] > [1] "andsin" "log_angle_1_4)" > > > diff_operator <- "\\sin(" > > strsplit(co

Re: [R] strsplit help

Alison, You've got two geneids with two periods (instead of just one period). gene.list <- strsplit(as.character(Rumino_Reps_agreeWalign$geneid),"\\.") Rumino_Reps_agreeWalign[sapply(gene.list, length)!=2, ] geneid count_Conser count_NonCons count_ConsSubst count_NCSubst 74

Re: [R] strsplit help

Thanks - I checked through and it looks as if all of the geneids are formatted similarily so I don't know which one would be causing an error. Interestingly, your sapply method works on the same data. So I'm happy although still confused, because the strsplit method worked the other day with a

Re: [R] strsplit help

David, Right you are! Thanks for pointing that out. strsplit <- 1:10 strsplit("With spaces", NULL) strsplit Jean David Winsemius wrote on 04/11/2012 01:17:07 PM: > [image removed] > > Re: [R] strsplit help > > David Winsemius > > to: > > Jean

Re: [R] strsplit help

On Apr 11, 2012, at 2:01 PM, Jean V Adams wrote: Alison, Your code works fine on the first six lines of the data that you provided. Rumino_Reps_agreeWalign <- data.frame( geneid = c("657313.locus_tag:RTO_08940", "457412.251848018", "657314.locus_tag:CK5

Re: [R] strsplit help

Alison, Your code works fine on the first six lines of the data that you provided. Rumino_Reps_agreeWalign <- data.frame( geneid = c("657313.locus_tag:RTO_08940", "457412.251848018", "657314.locus_tag:CK5_20630", "657323.locus_tag:CK1_330

Re: [R] Strsplit with a separator of ||

Thanks! JIng -Original Message- From: Berend Hasselman [mailto:b...@xs4all.nl] Sent: 22. maaliskuuta 2012 9:33 To: Berend Hasselman Cc: jing tang; r-help@r-project.org Subject: Re: [R] Strsplit with a separator of || On 22-03-2012, at 08:28, Berend Hasselman wrote: > > On 22-0

Re: [R] Strsplit with a separator of ||

You need another \\ > strsplit("a||bc","\\|\\|") [[1]] [1] "a" "bc" > On Thu, Mar 22, 2012 at 3:23 AM, jing tang wrote: > Hi, > > I tried to use strsplit for separating a string with || like > strsplit(string,"\\||") but it returned each single character was separated. > > For example: > > s

Re: [R] Strsplit with a separator of ||

On 22-03-2012, at 08:28, Berend Hasselman wrote: > > On 22-03-2012, at 08:23, jing tang wrote: > >> Hi, >> >> I tried to use strsplit for separating a string with || like >> strsplit(string,"\\||") but it returned each single character was separated. >> >> For example: >> >> strsplit("a||bc"

Re: [R] Strsplit with a separator of ||

On 22-03-2012, at 08:23, jing tang wrote: > Hi, > > I tried to use strsplit for separating a string with || like > strsplit(string,"\\||") but it returned each single character was separated. > > For example: > > strsplit("a||bc","\\||") > > [[1]] > > [1] "a" "" "" "b" "c" > > where I wan

Re: [R] strsplit() does not split on "."?

Because it uses regexp: use split='\\.' to split on "." char and read help(strsplit) :) Ryszard -- Confidentiality Notice: This message is private and may contain confidential and proprietary information. If you have receiv

Re: [R] strsplit() does not split on "."?

Hi Ryszard, Try strsplit("a.b", "[.]")[[1]] and see "Extended Regular Expressions" in ?regexp. HTH, Jorge,- On Thu, Jan 12, 2012 at 10:15 AM, Czerminski, Ryszard <> wrote: > Any ideas what is wrong? > > > strsplit("a.b", ".") # generates empty strings with split="." > [[1]] > [1] "" "" "" >

Re: [R] strsplit() does not split on "."?

Reread the help for strsplit: ## Note that 'split' is a regexp! ## If you really want to split on '.', use unlist(strsplit("a.b.c", "\\.")) ## [1] "a" "b" "c" ## or unlist(strsplit("a.b.c", ".", fixed = TRUE)) For your example: > strsplit("a.b", "\\.") [[1]] [1] "a"

Re: [R] strsplit question

On Wed, Oct 12, 2011 at 1:20 AM, Erin Hodgess wrote: > Dear R People: > > I have the following set of data >> Block[1:5] > [1] "5600-5699" "6100-6199" "9700-9799" "9400-9499" "8300-8399" > > and I want to split at the - > >> strsplit(Block[1:5],"-") > [[1]] > [1] "5600" "5699" > > [[2]] > [1] "610

Re: [R] strsplit question

On Oct 12, 2011, at 1:20 AM, Erin Hodgess wrote: Dear R People: I have the following set of data Block[1:5] [1] "5600-5699" "6100-6199" "9700-9799" "9400-9499" "8300-8399" and I want to split at the - strsplit(Block[1:5],"-") [[1]] [1] "5600" "5699" [[2]] [1] "6100" "6199" [[3]] [1] "9

Re: [R] strsplit question

Hi Erin, this is one way: Block <- c("5600-5699","6100-6199","9700-9799","9400-9499","8300-8399") splBlock <- strsplit(Block,"-") sapply(splBlock, "[", 1) greetings, Remko -- View this message in context: http://r.789695.n4.nabble.com/strsplit-question-tp3896847p3896850.html Sent from th

Re: [R] strsplit question

sapply(strsplit(Block[1:5],"-"), function (x) {x[1]}) comes to mind... --- Jeff Newmiller The . . Go Live... DCN: Basics: ##.#. ##.#. Live Go... Live: OO#.. Dead: OO#.. Playing Research Engineer (Solar/Batteries O.O#.

Re: [R] strsplit question

unlist(strsplit(Block[1:5], "-.+$")) if you are going to want the other pieces later, the most efficient way depends on the assumptions you can make about your data. If there are always two elements from the split: matrix(unlist(strsplit(Block[1:5], "-")), ncol = 2, byrow = TRUE) ## or do.call("

Re: [R] strsplit and forward slash '/'

On 3 Aug 2011, at 17:46, Sarah Goslee wrote: > Hi Federico, > > A forward slash isn't a special character: > >> strsplit("T/T", "/") > [[1]] > [1] "T" "T" > > so there's some other problem. > > Are you sure that your first column contains strings and not factors? > What does str(my.data) tell

Re: [R] strsplit and forward slash '/'

On 3 Aug 2011, at 17:41, Duncan Murdoch wrote: > > It looks as though your my.data[1,1] value is a factor, not a character value. > > strsplit(as.character(my.data[1,1]), "/") Thanks Duncan, this solved it. Best Federico > > would work, or you could avoid getting factors in the first plac

Re: [R] strsplit and forward slash '/'

Hi Federico, A forward slash isn't a special character: > strsplit("T/T", "/") [[1]] [1] "T" "T" so there's some other problem. Are you sure that your first column contains strings and not factors? What does str(my.data) tell you? Does strsplit(as.character(my.data[1,1]), "/") work? If you us

Re: [R] strsplit and forward slash '/'

On 03/08/2011 12:37 PM, Federico Calboli wrote: Hi All, is there a way of using strsplit with a forward slash '/' as the splitting point? For data such as: 1 T/TC/C 16/33 2 T/TC/C 33/36 3 T/TC/C 16/34 4 T/TC/C 16/31 5 C/CC/C 28/29 6 T/T

Re: [R] StrSplit

Thanks Jim. Exactly what I needed! -Original Message- From: jim holtman [mailto:jholt...@gmail.com] Sent: 09 October 2010 22:01 To: Santosh Srinivas Cc: r-help@r-project.org Subject: Re: [R] StrSplit Is this what you are after: > x <- c("Scheme Code;Scheme Name;Net

Re: [R] StrSplit

Obviously Jim's solution does work, and I did not intend to imply it didn't. In fact, his read.table solution would work both if the OP had a semi-colon delimited file to begin with (which I was trying to say was ideal from a workflow standpoint) or a vector of strings (for use when paired with te

Re: [R] StrSplit

On Oct 9, 2010, at 12:46 PM, Jeffrey Spies wrote: Jim's solution is the ideal way to read in the data: using the sep=";" argument in read.table. However, if you do for some reason have a vector of strings like the following (maybe someone gives you an Rdata file instead of the raw data file):

Re: [R] StrSplit

Jim's solution is the ideal way to read in the data: using the sep=";" argument in read.table. However, if you do for some reason have a vector of strings like the following (maybe someone gives you an Rdata file instead of the raw data file): MF_Data <- c("106506;AIG India Liquid Fund-Institutio

Re: [R] StrSplit

Is this what you are after: > x <- c("Scheme Code;Scheme Name;Net Asset Value;Repurchase Price;Sale > Price;Date" + , "" + ,"Open Ended Schemes ( Liquid )" + , "" + , "" + , "AIG Global Investment Group Mutual Fund" + , "106506;AIG India Liquid Fund-Institutional Plan-Daily Dividend Option;1001.

Re: [R] strsplit("dia ma", "\\b") splits characterwise

On Thu, Jul 8, 2010 at 4:15 AM, Suharto Anggono Suharto Anggono wrote: > \b is word boundary. > But, unexpectedly, strsplit("dia ma", "\\b") splits character by character. > >> strsplit("dia ma", "\\b") > [[1]] > [1] "d" "i" "a" " " "m" "a" > >> strsplit("dia ma", "\\b", perl=TRUE) > [[1]] > [1] "

Re: [R] strsplit("dia ma", "\\b") splits characterwise

l guess this is expected behaviour, although counterintuitive. \b represents an empty string indicating a word boundary, but is coerced to character and thus simply the empty string. This means the output you get is the same as > strsplit("dia ma", "",perl=T) [[1]] [1] "d" "i" "a" " " "m" "a" I'd

Re: [R] strsplit

Another option is to use the colsplit() function (in the reshape package): testdata <- data.frame(sp = c("GenusA_SpeciesC_Tree", "GenusA_SpeciesF_Tree", "GenusB_SpeciesA_Shrub"), stringsAsFactors=FALSE) library(reshape) testdata <- cbind(testdata, colsplit(testdata$sp, split="_", names=c("Genus",

Re: [R] strsplit

This might not be the most elegant way of doing it, but it should probably work, given that data is always separated by a "_". string.1<-strsplit(c("GenusA_SpeciesC_Tree","GenusA_SpeciesF_Tree", "GenusB_SpeciesA_Shrub"),"_") matrix(unlist(string.1),ncol=3,byrow=TRUE) 2010/6/1 Joël Baumann > He

Re: [R] strsplit

Hi, I don't know if it would help you since your goal is not really clear to me, but here are some thoughts: > x <- c("GenusA_SpeciesC_Tree", "GenusA_SpeciesF_Tree", "GenusB_SpeciesA_Shrub") > test <- strsplit(x, "_") > test [[1]] [1] "GenusA" "SpeciesC" "Tree" [[2]] [1] "GenusA" "Specie

Re: [R] strsplit

How about this: testdata <- data.frame(sp = c("GenusA_SpeciesC_Tree", "GenusA_SpeciesF_Tree", "GenusB_SpeciesA_Shrub"), stringsAsFactors=FALSE) # for one unlist(strsplit(testdata[1,1], split="_")) # for all of them do.call(rbind, sapply(testdata[,1], strsplit, split="_")) Sarah On Tue, Jun 1,

Re: [R] strsplit() and Windows file paths

> -Original Message- > From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On > Behalf Of Nordlund, Dan (DSHS/RDA) > Sent: Thursday, October 29, 2009 12:57 PM > To: r-help@r-project.org > Subject: Re: [R] strsplit() and Windows file paths > >

Re: [R] strsplit() and Windows file paths

> -Original Message- > From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On > Behalf Of Robert Baer > Sent: Thursday, October 29, 2009 12:40 PM > To: r-help@r-project.org > Subject: [R] strsplit() and Windows file paths > > There are two ways to express file paths wi

Re: [R] strsplit a matrix

Henrique, This is a very nice approach. I wonder what if I have data like 2-172-45 and want to break it down into three parts 2, 172 and 45. How do we use your method to achieve it? Thanks. Jun On Mon, Aug 10, 2009 at 12:34 PM, Henrique Dallazuanna wrote: > Try this: > > #1 > gsub(".*-", "", zz

Re: [R] strsplit a matrix

Try this: #1 gsub(".*-", "", zzz) #2 gsub("-.*", "", zzz) #3) gsub(".*-(.*)-.*", "\\1", zzz) On Mon, Aug 10, 2009 at 4:20 PM, Jun Shen wrote: > Henrique, > > This is a very nice approach. I wonder what if I have data like 2-172-45 > and want to break it down into three parts 2, 172 and 45. Ho

Re: [R] strsplit a matrix

Try this: #1 gsub(".*-", "", zzz) #2 gsub("-.*", "", zzz) On Mon, Aug 10, 2009 at 1:56 PM, James Perkins wrote: > Dear all, > > I am trying to split a matrix into 2 as efficiently as possible. > > It is a character matrix: > > 1 2 3 1 "2-271" "2-367" "1-79" > 2 "2-282" "2-378"

Re: [R] strsplit a matrix

one way us the following: mat <- rbind( c("2-271", "2-367", "1-79"), c("2-282", "2-378", "1-90"), c("2-281", "2-377", "1-89") ) sp <- strsplit(c(mat), "-") mat1 <- sapply(sp, "[", 1) mat2 <- sapply(sp, "[", 2) dim(mat1) <- dim(mat2) <- dim(mat) mat1 mat2 I hope it helps. Best, Dim

Re: [R] strsplit for multiple columns

Try this: do.call(cbind, lapply(a[2:ncol(a)], function(x)do.call(rbind, strsplit(as.character(x), '' On Wed, Jun 3, 2009 at 10:39 AM, Duijvesteijn, Naomi < naomi.duijveste...@ipg.nl> wrote: > > Hi, > > > I am trying to split multiple columns. One column works just fine, but I > want to

Re: [R] strsplit

Henrique Dallazuanna wrote: Try this: unlist(part)[1] or part[[1]][1] And in order to isnpect your objects, use str(part) at first which tells you about the structure of the object. Then you know you got a list and can look up how to extract a part of a list as Henrique Dallazuanna pon

Re: [R] strsplit

Try this: unlist(part)[1] or part[[1]][1] On Fri, May 29, 2009 at 2:09 PM, Nair, Murlidharan T wrote: > I am trying split a string and use one part of it to label graphs. I am > using strsplit for that. While I am able to split it, how do I access the > separated parts. > > filName<-"chrI_222

Re: [R] strsplit (regex)

You can do this one even more easily without regular expressions like this: substring(v, 1, 2) substring(v, 3) or with regexps: sub("(..).*", "\\1", v) sub("..(.*)", "\\1", v) or in one line using strapply in the gsubfn package: library(gsubfn) # see http://gsubfn.googlecode.com out <- strapp

Re: [R] strsplit (regex)

stephen sefick gmail.com> writes: > > #how do I break these up into first two letters (RM), number, and then > the last part > #is there an easily accessible regex tutorial on the internet? For regular expressions, the perl man pages at are quite good and

Re: [R] strsplit and regex

:38 AM >To: Redding, Matthew >Cc: r-help@r-project.org >Subject: Re: [R] strsplit and regex > >Here are several solutions: > >#1 ># replace first three and last 3 characters with nothing x <- >c("23:10:34", "01:02:03") gsub("^...|...$", &q

Re: [R] strsplit and regex

Here are several solutions: #1 # replace first three and last 3 characters with nothing x <- c("23:10:34", "01:02:03") gsub("^...|...$", "", x) #2 # backref = -1 says extract the portion in parens # it would have returned a list so we use simplify = c library(gsubfn) strapply(x, ":(..):", backref

Re: [R] strsplit and regex

Try this: format(strptime(tst, "%H:%M:%S"), "%M") On Wed, Oct 15, 2008 at 6:54 PM, Redding, Matthew < [EMAIL PROTECTED]> wrote: > Hi All, > > Is there a means to extract the "10" from "23:10:34" in one pass using > strsplit (or something else)? > tst <- "23:10:34" > > For example my attempt > s

Re: [R] strsplit and regex

It's no harder: use sub() which is vectorized. You've not actually defined the pattern, but here is my guess at your intentions: x <- c("23:10:34", "23:20:30") sub("([0-9][0-9]:)([0-9][0-9])(:[0-9][0-9])", "\\2", x) Another interpetation would be sub("([^:]*:)([^:]*)(:[^:]*)", "\\2", x) for

Re: [R] strsplit and regex

Matthew - Redding, Matthew wrote: Hi All, Is there a means to extract the "10" from "23:10:34" in one pass using strsplit (or something else)? tst <- "23:10:34" For example my attempt strsplit(as.character(tst),"^[0-9]*:") gives [[1]] [1] "" "" "34" Why not simply, strsplit(tst, ":")

Re: [R] strsplit and regex

Hi All, Just to make that question a bit harder - how do I apply that string extraction to vector of these time strings? Thanks, Matt Redding >-Original Message- >From: [EMAIL PROTECTED] >[mailto:[EMAIL PROTECTED] On Behalf Of Redding, Matthew >Sent: Thursday, 16 October 2008 7:54

Re: [R] strsplit and regexp

Try this: > library(gsubfn) > strapply(x, "[0-9]+| +[^ ]+ *")[[1]] [1] "2" " Value " "34" " a-c " "45" " t" which keeps the spaces around the non-numeric entries as in your example; however, if keeping the spaces is not important then its even easier: > strsplit(x, " ")[[1]] [1

Re: [R] strsplit, keeping delimiters

On Sat, Jun 14, 2008 at 11:46 AM, hadley wickham <[EMAIL PROTECTED]> wrote: > On Sat, Jun 14, 2008 at 10:20 AM, Martin Morgan <[EMAIL PROTECTED]> wrote: >> "hadley wickham" <[EMAIL PROTECTED]> writes: >> n >>> On Sat, Jun 14, 2008 at 12:55 AM, Gabor Grothendieck >>> <[EMAIL PROTECTED]> wrote:

Re: [R] strsplit, keeping delimiters

On Sat, Jun 14, 2008 at 10:20 AM, Martin Morgan <[EMAIL PROTECTED]> wrote: > "hadley wickham" <[EMAIL PROTECTED]> writes: > n >> On Sat, Jun 14, 2008 at 12:55 AM, Gabor Grothendieck >> <[EMAIL PROTECTED]> wrote: >>> Try this: >>> library(gsubfn) x <- "A: 123 B: 456 C: 678" strapply(x

Re: [R] strsplit, keeping delimiters

"hadley wickham" <[EMAIL PROTECTED]> writes: n > On Sat, Jun 14, 2008 at 12:55 AM, Gabor Grothendieck > <[EMAIL PROTECTED]> wrote: >> Try this: >> >>> library(gsubfn) >>> x <- "A: 123 B: 456 C: 678" >>> strapply(x, "[^ :]+[ :]|[^ :]+$") >> [[1]] >> [1] "A:" "123 " "B:" "456 " "C:" "678" Also

Re: [R] strsplit, keeping delimiters

On Sat, Jun 14, 2008 at 12:55 AM, Gabor Grothendieck <[EMAIL PROTECTED]> wrote: > Try this: > >> library(gsubfn) >> x <- "A: 123 B: 456 C: 678" >> strapply(x, "[^ :]+[ :]|[^ :]+$") > [[1]] > [1] "A:" "123 " "B:" "456 " "C:" "678" > > and check out the gsubfn home page at: > > http://gsubfn.go

Re: [R] strsplit, keeping delimiters

Try this: > library(gsubfn) > x <- "A: 123 B: 456 C: 678" > strapply(x, "[^ :]+[ :]|[^ :]+$") [[1]] [1] "A:" "123 " "B:" "456 " "C:" "678" and check out the gsubfn home page at: http://gsubfn.googlecode.com On Sat, Jun 14, 2008 at 1:35 AM, hadley wickham <[EMAIL PROTECTED]> wrote: > Hi a

Re: [R] strsplit and sapply

Here is a command I wrote to get the part of the email address before the @ sign. It works, but I don't know why. The variable called email is a vector of email addresses (not yet in character form, so that is why I need "as character"). names(Score) <- sapply(email,function(x) (strsplit(as.cha

Re: [R] strsplit and sapply

check this: TEXT <- c("a", "bb;ccc", ";e;ff") SPLIT <- strsplit(TEXT, ";") sapply(SPLIT, "[", 1) I hope it helps. Best, Dimitris Dimitris Rizopoulos Biostatistical Centre School of Public Health Catholic University of Leuven Address: Kapucijnenvoer 35, Leuven, Belgium Tel: +3

Re: [R] strsplit and sapply

Try: sapply(strsplit(TEXT, ';'), '[', 1) On Fri, Apr 11, 2008 at 8:12 AM, Dennis Fisher <[EMAIL PROTECTED]> wrote: > Colleagues, > > I have some text: >TEXT<- c("a", "bb;ccc", ";e;ff") > > I want to retrieve the portion of each element before the first > semicolon. I can

Re: [R] strsplit on comma, with a trailing comma in input

This works perfectly. Thanks! Peter Dalgaard wrote: > >> > Hmm, I don't think strsplit can do that. However: > > > scan(textConnection("a,,b,"), sep=",", what="") > Read 4 items > [1] "a" "" "b" "" > > -- >O__ Peter Dalgaard Øster Farimagsgade 5, Entr.B > c/ /'_

Re: [R] strsplit on comma, with a trailing comma in input

dankelley wrote: > I have a comma-separated data file in which trailing commas sometimes occur. > I am using strsplit to extract the data from this file, and it seems great > except in cases with trailing comma characters. > > The example below illustrates. What I'd like is to get a fourth elemen

Re: [R] strsplit on comma, with a trailing comma in input

Try appending another comma: strsplit(paste("a,,b,", ",", sep = ""), ",") On Dec 3, 2007 6:22 PM, dankelley <[EMAIL PROTECTED]> wrote: > > I have a comma-separated data file in which trailing commas sometimes occur. > I am using strsplit to extract the data from this file, and it seems great > e

Re: [R] strsplit on comma, with a trailing comma in input

my understanding is that this behavior is known (the help file mentions something along these lines in the example). i'd use something like: theText <- "a,,b," theText <- gsub("\\,$", ", ", theText) and then use strsplit() on "theText" b On Dec 3, 2007, at 6:22 PM, dankelley wrote: I hav

Re: [R] strsplit

On 22 October 2007 at 00:43, Edna Bell wrote: | Hello R Gurus: | | I would like to take a character string and split at the $ sign. | | I thought that strsplit would do it, but here are the results: | | > vv | [1] "whine$ts1" | > vv | [1] "whine$ts1" | > strsplit(vv,"$") | [[1]] | [1] "whine$ts

Re: [R] strsplit

On Mon, 22 Oct 2007, Edna Bell wrote: > Hello R Gurus: > > I would like to take a character string and split at the $ sign. > > I thought that strsplit would do it, but here are the results: > >> vv > [1] "whine$ts1" >> vv > [1] "whine$ts1" >> strsplit(vv,"$") > [[1]] > [1] "whine$ts1" > > > Does

Re: [R] strsplit

Try strsplit(vv,"$",fixed=TRUE) --- Edna Bell <[EMAIL PROTECTED]> wrote: > Hello R Gurus: > > I would like to take a character string and split at > the $ sign. > > I thought that strsplit would do it, but here are > the results: > > > vv > [1] "whine$ts1" > > vv > [1] "whine$ts1" > > strspli