On Mar 2, 2010, at 8:11 AM, Sebastian Bauer wrote:
Hello,
is there an elegant way, how I can convert each row of a data frame
into distinct elements of a list?
split(dfrm, rownames(dfrm))
In essence, what I'm looking for is something like
rows.to.lists <- function( df ) {
ll <-
Hi!
On 03/02/2010 02:22 PM, Nutter, Benjamin wrote:
as.data.frame(t(df))
For example
x<- as.data.frame(t(mtcars))
typeof(x)
[1] "list"
Thanks for the quick reply!
I would never have guessed that as.data.frame() works that way!
BTW
This one seems also to do the trick:
rows.to.list <- f
> as.data.frame(t(df))
For example
> x <- as.data.frame(t(mtcars))
> typeof(x)
[1] "list"
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of Sebastian Bauer
Sent: Tuesday, March 02, 2010 8:12 AM
To: r-help@r-project.org
Subject: [R]
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