Re: [R] Problem with lapply

2013-10-16 Thread rissa
Ah ok, I see the problem! Thank you again! -- View this message in context: http://r.789695.n4.nabble.com/Problem-with-lapply-tp4678290p4678371.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https:/

Re: [R] Problem with lapply

2013-10-15 Thread arun
Hi, No problem. Regarding your code: #changed name from 'dataset' to "Testcor" #Your code   firm.names=colnames(Testcor)[2:length(colnames(Testcor))]  firm.names # [1] "PAXN"   "PED"    "PEDP"   "PM" "PRFN"   "PRWN"   "ZG" "ZUBN"   #[9] "ZURN"   "ZWM"    "Market" #includes "Market"

Re: [R] Problem with lapply

2013-10-15 Thread rissa
Thank you! Worked perfectly! By the way: What was wrong with my original code? -- View this message in context: http://r.789695.n4.nabble.com/Problem-with-lapply-tp4678290p4678305.html Sent from the R help mailing list archive at Nabble.com. __ R-he

Re: [R] Problem with lapply

2013-10-15 Thread arun
Hi, Try: Testcor <- read.table("Testcor.txt",sep="",header=TRUE,stringsAsFactors=FALSE) Testcor$DATE <- as.Date(Testcor$DATE) firm.names <- colnames(Testcor)[!grepl("DATE|Market",colnames(Testcor))] res <- sapply(firm.names, function(x) {cor.results <- cor.test(Testcor[,x],Testcor[,"Market"],na.