Need reproducible code and data to respond.
As per the last line to every message in r-help, reduce the file to the
smallest subset that exhibits the error and post it with self contained
code that will read it in and reproduce the error message.
On Fri, Jul 17, 2009 at 10:29 AM, Keith wrote:
> Y
Yep, it's my mistake while manipulating the data. Now it works fine
except there is a warning message coming out:
Warning message:
In zoo(rval, ix) :
some methods for “zoo” objects do not work if the index entries in
‘order.by’ are not unique
I checked the faq and some other documents, it seems
By the way, note that read.zoo passes the ... arguments to read.table
and so can use the same skip= and nrows= arguments that read.table
uses. These can be used to read in a subset of the rows.
On Thu, Jul 16, 2009 at 10:35 AM, Gabor
Grothendieck wrote:
> There is no such limitation. There is l
There is no such limitation. There is likely a data problem with
one or more records past the 280th one.
Suggest you remove the first 280 and then divide the remaining
in half and try each half and keep dividing that way until you have
located the offending record or records.
On Thu, Jul 16, 20
Thanks Gabor,
I tried a little bit, and your example works. However, it seems that
the read.zoo has a limitation of records up to around 300 !? I took
your suggestion and modified a little bit in order to read from the
file which contains about 9000 records:
dataTs <- read.zoo("filename.csv", hea
Try the zoo package:
Lines <- "time[sec] , Factor1 , Factor2
00:00:00 01.01.2007 , 0. , 0.176083
01:00:00 01.01.2007 , 0. , 0.176417
11:00:00 10.06.2007 , 0. , 0.148250
12:00:00 10.06.2007 , NA , 0.147000
13:00:00 10.06.2007 , NA , 0.144417"
library(zoo)
library(chron)
z <- read.zoo(t
6 matches
Mail list logo
