Re: [R] Pattern matching and replacement in matrix

Hi, I think you can make it work by combining gsub() and sapply() (or lapply()), though I don't really know how (those *apply() functions are still kind of a mystery for me). Maybe someone else can help you Ivan Le 5/19/2010 12:35, Dani Valverde a écrit : Hello, Is there any function like g

Re: [R] Pattern matching and replacement in matrix

Try this: DF <- data.frame(a = head(letters), A = head(LETTERS)) DF[] <- lapply(DF, gsub, pattern = "a", replacement = "X") m <- cbind(a = head(letters), A = head(LETTERS)) m[] <- gsub("a", "X", m) In the future please provide test data and desired output as per posting guide (see bottom of ever

Re: [R] Pattern matching and replacement in matrix

Exactly how do you want to do that? (PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.) Provide a before/after example of what you want. You could use the 'apply' functions. On Wed, May 19, 2010 at 6:35