You might have better luck reformatting your data as time series, then you can
still print it in a matrix like form, but access it serially without worrying
about wrapping around rows.
Another option would be to transpose the matrix so that months go down the
columns, then use the %% and %/% op
Hi:
This isn't particularly elegant, but I think it works:
# The function to be applied:
f <- function(x, idx) {
n <- length(x)
if(idx[1] < idx[2]) {idx <- seq(idx[1], idx[2])
} else { idx <- c(seq(idx[1], n), seq(1, idx[2])) }
mean(x[idx])
}
# tests
> month.data = matrix(c(3,
On Oct 13, 2010, at 4:54 PM, Alisa Wade wrote:
Thanks, David for the response.
Unfortunately, that only works for the case where I happen to only
want the last and first month "wrap".
But it doesn't work for any other case, e.g., say I want months
start.month = 4, end.month = 2.
Now
woul
Thanks, David for the response.
Unfortunately, that only works for the case where I happen to only want the
last and first month "wrap".
But it doesn't work for any other case, e.g., say I want months start.month
= 4, end.month = 2.
Now
start=4; end=2; year.avg = apply(month.data[, c(start,end)],
On Oct 13, 2010, at 4:10 PM, Alisa Wade wrote:
Perhaps it is just that I don't even know the correct term to search
for,
but I can find nothing that explains how to wrap around from the end
to a
start of a row in a matrix.
For example, you have a matrix of 2 years of data, where rows are
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