Hi, a solution could be:
# example matrix a:
a <- matrix(1:100, 10, 10)
a[, 1] <- (sample(c("aa","bb" , "ab"), 10, rep=TRUE))
a <- a[order(a[, 1]), ] # order the matrix by row = 1
#subsetting a:
lev <- levels(as.factor(a[, 1]))
subs <- list()
for(i in 1:length(lev)) {
subs[[i]] <- a[a[, 1] %
The split function does essentially this, but puts the results into a list
rather than using the dangerous and messy assign function. The overall
syntax is simpler as well.
On Thu, Feb 12, 2015 at 3:14 AM, Jim Lemon wrote:
> Hi Samarvir,
> Assuming that you want to generate a separate data fram
Hi Samarvir,
Assuming that you want to generate a separate data frame for each
value of "Name",
# name of initial data frame is ssdf
for(nameval in unique(ssdf$Name)) assign(nameval,ssdf[ssdf$Name==nameval,])
This will produce as many data frames as there are unique values of
ssdf$Name, each name
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