on: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
>> Im
>> Auftrag von Michael Bedward
>> Gesendet: Donnerstag, 11. November 2010 10:56
>> An: friedericksen.h...@gmail.com
>> Cc: r-h...@stat.math.ethz.ch
>> Betreff: Re: [R] How to get a speci
richt-
>> Von: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] Im
>> Auftrag von Michael Bedward
>> Gesendet: Donnerstag, 11. November 2010 10:56
>> An: friedericksen.h...@gmail.com
>> Cc: r-h...@stat.math.ethz.ch
>> Betreff: Re: [R] How
Hi Ivan,
thank you very much for your detailed explanations and response!
Please excuse, that I did not include a reproducible example.
Yes, what I am looking for is such a function - but I suspect, that it does not
exist already, so I have to write it on my own.
Best,
Friedericksen
On 11/11/
What you want is some sort of indexing nested lists based on names (as we
are used to for vectors, for example). As Ivan pointed out, I don't think
there's an "out-of-the-box" function in R that supports such indexing as it
requires some sort of mapping of the nested list's hierarchical structure.
Hi Friedericksen,
This function will do it. No doubt there are more elegant ways :)
rmatch <- function(x, name) {
pos <- match(name, names(x))
if (!is.na(pos))
return(x[[pos]])
for (el in x) {
if (class(el) == "list") {
out <- getEl(el, name)
if (!is.null(out)) return(o
Hi,
A reproducible example would have been nice, but a correct code even
more (you forgot some commas)!
So if you meant this:
x <- list(
list(
list(df1,df2),
list(df3,
list(df4,df5)),
list(df6,df7)))
check str(x): (I removes the details of each df)
List of 1
$ :List of 3
..
6 matches
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