Mostly agree, except that I would suggest hardcoding the notion of "in the
future", so that you don't get surprises when someone reruns your code 20 years
from now.
-pd
> On 28 Dec 2017, at 21:54 , Simmering, Jacob E
> wrote:
>
> Your dates have an incomplete year information with 34. R assu
Le 28/12/2017 à 18:13, Ramesh YAPALPARVI a écrit :
Hi all,
I’m struggling to get the dates in proper format.
I have dates as factors and is in the form 02/27/34( 34 means 1934). If I use
Try this
x <- "02/27/34"
x2 <- paste0(substr(x, 1, 6), "19", substr(x, 7, 8))
as.Date(x2, format="%m/%d/%Y
Your dates have an incomplete year information with 34. R assumes that 00-68
are 2000 to 2068 and 69 to 99 are 1969 to 1999. See ?strptime and the details
for %y.
You can either append “19” to the start of your year variable to make it
completely express the year or check if the date is in the
If the vector elements are (still) strings, you could simply try
x<- c("2000-01-01", "2000-01-23", "2001-03-12", "2009-12-31")
substring(x, 1, 7)
# [1] "2000-01" "2000-01" "2001-03" "2009-12"
Hope this helps a little.
Allan
On 29/06/10 14:36, Thomas Jensen wrote:
Dear R Experts,
I have a
On Jun 29, 2010, at 8:36 AM, Thomas Jensen wrote:
> Dear R Experts,
>
> I have a vector of dates in character format like this:
>
> date
> "2000-01-01"
> "2000-01-23"
> "2001-03-12"
> ...
> ...
> ...
> "2009-12-31"
>
> I would like to delete the last part of the character string (i.e. the "day"
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