Your function only works for the first dimensions (e.g. indices
indicating the positions in the first two dimensions in datacube), correct?
Otherwise it looks very handy! And certainly more elegent than my
function monster!
Jannis
On 08/04/2011 09:58 PM, R. Michael Weylandt wrote:
Hi Jannis
As currently implemented it works for both "Location" and "Destination" (I
really should think of some better variable names) of any dimensionality,
but it does assume that if say, you give a 2d location, those correspond to
the first two dimensions of destination.
But if you give 1d or 3d, e.g.,
This function you wrote is interesting, but I almost missed it since I
didn't see a direct example!
cubeValues(NULL, data, indices)
cubeValues(1, data, indices)
cubeValues(c(1,2), data, indices)
(sorry if I'm beating a dead horse here)
On Thu, Aug 4, 2011 at 2:58 PM, R. Michael Weylandt <
michae
(I was just about to send this before your last reply)
As a more general tip, I find that using %in% is easier to understand than
"is.element" and "setdiff" because it can be more universal, especially when
combined with "all" and the "!".
To me the functions like setdiff are easier to read, but h
Thanks, Gene, for your hint! I indeed did not check any possible
situation and my function was not returning what I intened it to return.
This updated version, however, should. I am sure there are much easier
ways (or ready made functions) to do the same.
ind.datacube = function(
##title<< c
Hi Jannis,
Like Gene, I'm not entirely sure what your code is intended to do, but it
wasn't hard to adapt mine to at least print out the desired slice through
the higher-dimensional array:
cubeValues <- function(Insert, Destination, Location) {
Location = as.matrix(Location)
Location = ar
I'm just wondering
When I use your function on your data I get a result that is not very
intuitive. Is this what you were trying to do?
(I took the liberty of setting dims to 3 since 'auto', 1, and 2 didn't
work.
> data<- array(rnorm(64),dim=c(4,4,4))
> indices<- matrix(FALSE,nc
Thanks, Michael. I was, however, after a function I coul use for both
extracting and replacing subarrays. In case anybody else stumbles over
this problem, here is my solution. Its programming is most probably
horribly clumsy:
ind.datacube = function(
##title<< create logical index matrices fo
> This might be a little late: but how about this (slightly clumsy) function:
>
> putValues <- function(Insert, Destination, Location) {
> Location = as.matrix(Location)
> Location = array(Location,dim(Destination))
> Destination[Location] <- Insert
> return(Destination)
> }
>
> It
Thanks for all the replies!Unfortunately the solutions only work for
extracting subsets of the data (which was exactly what I was asking for)
and not to replace subsets with other values. I used them, however, to
program a rather akward function to do that. Seems I found one of the
few aspects
What do you think about this?
apply(data, 3, '[', indices)
On Mon, Aug 1, 2011 at 4:38 AM, Jannis wrote:
> Dear R community,
>
>
> I have a general question regarding indexing in multidiemensional arrays.
>
> Imagine I have a three dimensional array and I only want to extract on
> vector along
On Aug 1, 2011, at 10:50 AM, Duncan Murdoch wrote:
On 11-08-01 5:38 AM, Jannis wrote:
Dear R community,
I have a general question regarding indexing in multidiemensional
arrays.
Imagine I have a three dimensional array and I only want to extract
on
vector along a single dimension from
On 11-08-01 5:38 AM, Jannis wrote:
Dear R community,
I have a general question regarding indexing in multidiemensional arrays.
Imagine I have a three dimensional array and I only want to extract on
vector along a single dimension from it:
data<- array(rnorm(64),dim=c(4,4,4))
result<- data[1
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