Hi Greg - this is perfect - Thank You!
Also, thanks to everyone for the other suggestions
Greg Snow-2 wrote:
>
> How about:
>
> x3 <- cumsum( x2* 0.24^(5:0) ) / 0.24^(5:0)
>
> with the 5 replaced by the length -1 for the more general case.
>
> --
> Gregory (Greg) L. Snow Ph.D.
> Statistic
How about:
x3 <- cumsum( x2* 0.24^(5:0) ) / 0.24^(5:0)
with the 5 replaced by the length -1 for the more general case.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
> -Original Message-
> From: r-help-boun...@r-projec
alf Of Pele
> Sent: Monday, February 23, 2009 4:48 PM
> To: r-help@r-project.org
> Subject: Re: [R] Formula that includes previous row values
>
>
> Hi Jorge - many thanks for you suggestion, but I am looking
> for a way where I don't have to use a loop. I meant to
>
Hi Jorge - many thanks for you suggestion, but I am looking for a way where I
don't have to use a loop. I meant to include that in my description.
Thanks again!
Jorge Ivan Velez wrote:
>
> Dear Pele,
> Probably not the best way to proceed but it works:
>
> X<-read.table(textConnection("ID
Dear Pele,
Probably not the best way to proceed but it works:
X<-read.table(textConnection("ID X2
1.001.00
2.000.00
3.001.00
4.003058
5.000.00
6.006.00"),header=TRUE)
closeAllConnections()
X
x3<-0
for(i in 2:(nrow(X)+1)) x3<-c(x3, X$X2[i-1]+0.24*x3[i-1])
X$x3<-x3[-1]
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