(x) = length(x1) + length(x[ ! x %in% x1])
>
> Any better idea?
>
>
> --- On Sun, 10/12/08, Jorge Ivan Velez <[EMAIL PROTECTED]> wrote:
>
>> From: Jorge Ivan Velez <[EMAIL PROTECTED]>
>> Subject: Re: [R] Extracting subset of a vector
>> To: [EMAIL PROTEC
) + length(x[ ! x %in% x1])
>
> Any better idea?
>
>
> --- On Sun, 10/12/08, Jorge Ivan Velez <[EMAIL PROTECTED]> wrote:
>
> > From: Jorge Ivan Velez <[EMAIL PROTECTED]>
> > Subject: Re: [R] Extracting subset of a vector
> > To: [EMAIL PROTECT
an Velez <[EMAIL PROTECTED]>
Subject: Re: [R] Extracting subset of a vector
To: [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Date: Sunday, October 12, 2008, 1:06 AM
Hi Megh,
Try this:
x<-c(100,96,88,100,100,96,80,68,92,96,88,92,68,84,84,88,72,88,72,88)
x1 = sample(x, 5, replace=FALSE)
x[ ! x %i
Thanks for this suggestion. However I am not getting :
length(x) = length(x1) + length(x[ ! x %in% x1])
Any better idea?
--- On Sun, 10/12/08, Jorge Ivan Velez <[EMAIL PROTECTED]> wrote:
> From: Jorge Ivan Velez <[EMAIL PROTECTED]>
> Subject: Re: [R] Extracting subset of a v
Megh Dal wrote:
I have 2 vecros :
x<-c(100,96,88,100,100,96,80,68,92,96,88,92,68,84,84,88,72,88,72,88)
x1 = sample(x, 5, replace=FALSE)
Now i want to get remaining values of vector "x" those are not member of vector
"x1". Can anyone please tell me how to do that?
x[!(x %in% x1)] should do
Hi Megh,
Try this:
x<-c(100,96,88,100,100,96,80,68,92,96,88,92,68,84,84,88,72,88,72,88)
x1 = sample(x, 5, replace=FALSE)
x[ ! x %in% x1]
HTH,
Jorge
On Sat, Oct 11, 2008 at 3:25 PM, Megh Dal <[EMAIL PROTECTED]> wrote:
> I have 2 vecros :
> x<-c(100,96,88,100,100,96,80,68,92,96,88,92,68,84,84,
Hi Megh,
two options:
x=1:20
y=1:10
z1=x[x%in%y==FALSE]
z2=x[x!=y]
z1
z2
Cheers,
Daniel
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