Dear Dennis, David, Jeff, and Denes,
Thanks for your helps and comments. The simple one seems good enough for
my works.
Best,
Steve
On Wed, Dec 17, 2014 at 5:46 AM, Dénes Tóth wrote:
>
> Dear Jeff,
>
> On 12/17/2014 01:46 AM, Jeff Newmiller wrote:
>
>> You are chasing ghosts of performance pa
Dear Jeff,
On 12/17/2014 01:46 AM, Jeff Newmiller wrote:
You are chasing ghosts of performance past, Denes.
In terms of memory efficiency, yes. In terms of CPU time, there can be
significant difference, see below.
The data.frame
function causes no problems, and if it is used then the OP w
You are chasing ghosts of performance past, Denes. The data.frame
function causes no problems, and if it is used then the OP would not need
to presume they know the internal structure of the data frame.
See below. (I am using R3.1.2.)
a1 <- list(x = rnorm(1e6), y = rnorm(1e6))
a2 <- list(x = rn
On 12/16/2014 06:06 PM, SH wrote:
Dear List,
I hope this posting is not redundant. I have several list outputs with the
same components. I ran a function with three different scenarios below
(e.g., scen1, scen2, and scen3,...,scenN). I would like to extract the
same components and group the
Something like
scens <- paste0("scen", 1:N)
new.df <- data.frame(sapply(scens, function(x) get(x)[["pop.inf.r"]]))
-
David L Carlson
Department of Anthropology
Texas A&M University
College Station, TX 77840-4352
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