quot;Smith" "Smith" "Smith" "Smith" "Jones" "Jones" "Jones"
"Gunter"
If that remains unclear, I am doing something wrong today.
It is nice to see alternatives but some people just want one answer. Read my
first mes
"If you want a much more compact solution that handles arbitrary pairs of
"what to copy", number_of_copies, you can write a function that evaluates
two arguments at a time or takes two vectors as arguments like this one I
wrote quickly and crudely:"
Please! -- The "times" argument of rep can be a
For the particular example you asked for, consider the "each" you can use
with rep()
rep(1:13, each=84)
This is what it does for a shorter version of 4 each:
> rep(1:13, each=4)
[1] 1 1 1 1 2 2 2 2 3 3 3 3 4 4 4 4 5 5 5 5 6 6 6 6
7 7 7 7 8 8 8 8 9 9 9 9 10 10
Bert Gunter
Sent: Thursday, June 13, 2024 9:13 PM
To: Ebert,Timothy Aaron
Cc: Francesca PANCOTTO ; r-help@r-project.org
Subject: Re: [R] Create a numeric series in an efficient way
[External Email]
Nope. She would have wanted the 'each' argument = 84. See ?rep.
-- Bert
On Thu, Jun 13,
> To: r-help@r-project.org
> Subject: Re: [R] Create a numeric series in an efficient way
>
> [External Email]
>
> I apologize, I solved the problem, sorry for that.
> f.
>
>
>
> Il giorno gio 13 giu 2024 alle ore 16:42 Francesca PANCOTTO <
> francesca.panco
rom: R-help On Behalf Of Francesca PANCOTTO via
R-help
Sent: Thursday, June 13, 2024 2:22 PM
To: r-help@r-project.org
Subject: Re: [R] Create a numeric series in an efficient way
[External Email]
I apologize, I solved the problem, sorry for that.
f.
Il giorno gio 13 giu 2024 alle ore 16:42 Fra
I apologize, I solved the problem, sorry for that.
f.
Il giorno gio 13 giu 2024 alle ore 16:42 Francesca PANCOTTO <
francesca.panco...@unimore.it> ha scritto:
> Dear Contributors
> I am trying to create a numeric series with repeated numbers, not
> difficult task, but I do not seem to find an e
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