Thank you Richard.
Best regards,
Paul
El vie., 27 de diciembre de 2019 4:27 p. m., Richard O'Keefe <
rao...@gmail.com> escribió:
> The specific problem you are trying to solve is so constrained that
> you do not need a
> general purpose method.
> You start with a string that contains characters
Thank you very much Rui.
Best regards!
El vie., 27 de diciembre de 2019 4:22 p. m., Rui Barradas <
ruipbarra...@sapo.pt> escribió:
> Hello,
>
> You forgot to cc the list, I'm replying all to have a complete thread so
> that others now and in the future can search similar problems they might
> en
The specific problem you are trying to solve is so constrained that
you do not need a
general purpose method.
You start with a string that contains characters drawn from a *subset*
of ASCII with
at most 64 elements. Accordingly, all you need is a table mapping characters to
6-character strings.
ta
Hello,
You forgot to cc the list, I'm replying all to have a complete thread so
that others now and in the future can search similar problems they might
encounter.
The following function bin2dec works as expected.
bin2dec <- function(x){
s <- strsplit(x, "")
s <- lapply(s, function(x){
Hello,
Your code and the answers provided, specially Marc's, led me to
utf8ToBin <- function(x, out = c("ascii", "dec", "bin")){
out <- match.arg(out)
ascii_datformat <- utf8ToInt(x)
Base <- ascii_datformat - 48
Base <- ifelse(Base > 40, Base - 8, Base)
Bin <- R.utils::intToBin(Base)
Hi Paul,
Since you start from strings, it's not clear to me where ASCII enters
the picture. If you really need ASCII, you can use the charToInt()
function in the "R.oo" package. Also there's the AsciiToInt() function
in the "sfsmisc" package. If you just want to use R's native
as.numeric() conver
Use the Rmpfr package.
it will print numbers in any base from 2 to 62
> library(Rmpfr)
> ?Rmpfr
> b15 <- mpfr(15, precBits=6)
> formatBin(b15)
[1] +0b1.11100p+3
>
On Fri, Dec 27, 2019 at 10:43 AM Paul Bernal wrote:
>
> Dear friends,
>
> Hope you are all doing well. I need to find a way to conve
Dear Jeff,
Hope you are doing great. The link I provide below has the results I am
expecting. I am doing a test, trying to convert this string: "133m@ogP00PD
;88MD5MTDww@2D7k" into ascii numbers, then to decimal, and ultimately, into
binary. I am trying to recreate the results obtained in the link
Your question is incomplete... what do you expect the result to be?
Perhaps [1] is relevant?
[1]
https://stackoverflow.com/questions/52298995/r-binary-decimal-conversion-confusion-ais-data
On December 27, 2019 7:42:36 AM PST, Paul Bernal wrote:
>Dear friends,
>
>Hope you are all doing well. I
> On Dec 27, 2019, at 10:42 AM, Paul Bernal wrote:
>
> Dear friends,
>
> Hope you are all doing well. I need to find a way to convert ascii numbers
> to six digit binary numbers:
>
> I am working with this example, I converted the string to ascii, and
> finally to decimal, but I am having tro
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