Thank you !
I was also able to do it this way, too!
hc <- ddply(tab1, .(time), summarize, S1 = length(unique(S1)))
On Sat, Nov 21, 2015 at 3:40 PM, wrote:
> Hello,
>
> Is that a real doubt? Like Bert said, you should spend some time with an R
> tutorial. All you need is to know how to form a
Hello,
Is that a real doubt? Like Bert said, you should spend some time with
an R tutorial. All you need is to know how to form a data.frame.
tmp <- tapply(tab1$S1, tab1$time, function(x) length(unique(x)))
data.frame(time = names(tmp), S1 = tmp)
Rui Barradas
Citando Ashta :
> Hi Rui ,
>
Hi Rui ,
I tried that one before I send out my original message.
it gave me only this,
tapply(tab$S1, tab$time, function(x) length(unique(x)))
1 2 3
2 1 3
I am expecting an output of like this
time S1
12
21
33
On Sat, Nov 21, 2015 at 2:38 PM, wrote:
> Hello,
Hello,
Try
tapply(tab$S1, tab$time, function(x) length(unique(x)))
Hope this helps,
Rui Barradas
Citando Ashta :
> Hi Bert and all,
> I have related question. In each time period there were different
> locations where the samples were collected (S1). I want count the
> number of uni
Time to do your own homework by working through an R tutorial or two.
There are many on the web -- or see the Intro to R tutorial that ships
with R.
?tapply
?unique
is one of many answers to your query.
Cheers,
Bert
Bert Gunter
"Data is not information. Information is not knowledge. And knowled
Hi Bert and all,
I have related question. In each time period there were different
locations where the samples were collected (S1). I want count the
number of unique locations (S1) for each unique time period . So in
time 1 the samples were collected from two locations and time 2 only
from
Thank you Bert!
What I want is at least 500 samples based on random sampling of time
period. This allows samples collected at the same time period are
included together.
Your script is doing what I wanted to do!!
Many thanks
On Sat, Nov 21, 2015 at 1:15 PM, Bert Gunter wrote:
> David's "
David's "solution" is incorrect. It can also fail to give you times
with a total of 500 items to sample from in the time periods.
It is not entirely clear what you want. The solution below gives you a
random sample of time periods in which X1>0 and the total number of
samples among them is >= 500.
Thank you David!
I rerun the your script and it is giving me the first three time periods
is it doing random sampling?
tab.fan
time X1 X2
22 5 230
33 1 300
55 2 10
On Sat, Nov 21, 2015 at 12:20 PM, David L Carlson wrote:
> Use dput() to send data to the list as it is
Use dput() to send data to the list as it is more compact:
> dput(tab)
structure(list(time = 1:8, X1 = c(0L, 5L, 1L, 0L, 2L, 3L, 1L,
4L), X2 = c(251L, 230L, 300L, 25L, 10L, 101L, 300L, 185L)), .Names = c("time",
"X1", "X2"), class = "data.frame", row.names = c(NA, -8L))
You can just remove the
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