Hi Cristian,
yes, indeed. What I'm not sure about is how doing this by groups will
give you a different result, if the object is already sorted according
to the group structure. As you are working with differences, each
group 'loses' an observation, which will be the observation that is
calculat
Thanks Andrew, but what you gave me can actually be done simpler like
my_agg$vol.diff <- diff(my_agg$Vol)
or
my_agg$vol.diff <-c(NA, diff(my_agg$Vol)) # for a list with the same
#length as the aggregated mean list
However, what I need is to be able to h
Hi Cristian,
instead of aggregate, how about something like:
n <- dim(my_agg)[1]
my_agg$vol.diff <- my_agg$Vol - c(NA, my_agg$Vol[1:(n-1)]
my_agg <- my.agg[my.agg$Age > min(my.agg$Age),]
(assumes same minimum age for all treatments)
(not checked)
Cheers,
Andrew
On Thu, Nov 01, 2007 at 12:0
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