That's it.
thanks very much, I save hours if work qith your reply
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Mario Garrido Escudero
PhD student
Dpto. de Biología Animal, Ecología, Parasitología, Edafología y Qca. Agrícola
Universidad de Salamanca
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http://r.789695.n4.nabble.com/Applying-a-function-to-a
Or just include is.na=TRUE in the definition of kurtosis():
kurtosis<-function(x) {
m4<-sum((x-mean(x,na.rm=TRUE))^4,na.rm=TRUE)/length(x)
s4<-var(x,na.rm=TRUE)^2
m4/s4 - 3 }
HTH
Stephan
Am 29.05.2011 11:34, schrieb Jim Holtman:
kurtosis(fem[!is.na(fem)])
Sent from my iPad
On May 29,
kurtosis(fem[!is.na(fem)])
Sent from my iPad
On May 29, 2011, at 4:54, gaiarrido wrote:
> Here´s my problem,
> i have developed the function kurtosis (using R-book as a guide) with this
> commands:
> kurtosis<-function(x) {
> m4<-sum((x-mean(x))^4)/length(x)
> s4<-var(x)^2
> m4/s4 - 3 }
>
> Th
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